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7:47 AM
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Preliminary conclusion: Axiom of choice allow the partition of an interval into countably many uncountable dense sets that has no intervals. Then since there are no infintesimal elements in the Lebesgue measure, countable additivity of countably many nonzero measure cannot give a finite value
Thus now the question is then:
> How to show that it is impossible to construct a countable partition of an interval that contain no intervals?
 

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