last day (124 days later) » 

1:10 PM
First message :P
 
Welcome to the CodeGolf Hackathon!
3
 
FWIW, the Deorst answer for Puzzle 1 is Ě€ĄďK=, but it isn't fully implemented yet.
 
@cairdcoinheringaahing take your time
I will most likely not be online for the next couple of hours, starting from half an hour from now. Please update the scoreboard and ping if you add new submissions (cc @cairdcoinheringaahing @EriktheOutgolfer)
 
@Mr.Xcoder Ok, will do
 
1:14 PM
@EriktheOutgolfer do you know Husk?
 
He knows a bit
Me too
 
@cairdcoinheringaahing well, not fully yet
as mr xcoder said
 
Either of you know enough to solve puzzle 1?
 
I'll add some new features to the challenges, such as difficulty rates
@cairdcoinheringaahing Meh, after a bit of struggling maybe
 
@Mr.Xcoder I have changed the explanation a bit to indicate implicit stuff and nesting, tell me if it's good
 
1:17 PM
How would you rate challenge one on a scale from 1 to 10, in terms of difficulty.
 
Cause we all know Jelly, you two know Pyth, Erik (and maybe Xcoder) knows 05AB1E, I know 2Deorstv, so who's going to do Husk?
@Mr.Xcoder 3-5
 
@cairdcoinheringaahing Maybe H.PWiz will join in the future
 
Are we going to have to get Zgarb or HPWiz doing this as well? :P
 
or zgarb
most likely h.pwiz
but mr xcoder and I can try too...
 
@Erik The explanation is great, let me align those lines though >->
 
1:20 PM
@Mr.Xcoder no
 
@EriktheOutgolfer Why?
 
that's how nesting is represented
 
Ok then.
 
and I want to represent it some way
 
It's yours, so it's up to you.
 
1:21 PM
alright
 
@EriktheOutgolfer Collaborative Husk until I leave?
 
Great
We shall pick an algorithm first though
 
(btw puzzle 1 is a case where prefixes including empty prefix is an advantage...)
 
@EriktheOutgolfer Is it?
 
1:23 PM
except that
there's no average builtin
 
@EriktheOutgolfer No built-in for average
Ninja'd
...
@EriktheOutgolfer Husk CMC: average of a list.
 
where [] -> 0
that's the difficult part
§/ΣL is average definition
 
Presumably along the lines of S÷L$$0L=0$$? for Jelly?
 
@cairdcoinheringaahing Yes xDxD
 
but it returns NaN for []:LN
 
1:27 PM
@EriktheOutgolfer Doesn't work
 
because it's not the whole solution
 
ignore the input
@EriktheOutgolfer link?
 
oh wait it doesn't work
dang it has to be §/LΣ
/ reverses order of arguments
@Mr.Xcoder not ready yet
 
heh
> [NaN,1.0,2.5,2.6666666666666665,4.0,4.4]... Dang
 
and NaN isn't 0
 
1:30 PM
yeah
 
Can't you just do str, replace(Nan, 0), eval?
 
§&§/LΣL seems to work
for the average
 
@cairdcoinheringaahing Ungolfy >_>
 
@Mr.Xcoder Meh, I don't know Husk :P
Could be 1 byte builtin for all I know
 
@EriktheOutgolfer 4 bytes equivalent?
 
1:32 PM
@Mr.Xcoder but mine returns 0 for []:LN
 
oh
Now to map over two collections in parallel
 
oh that's easy I guess
but I'm focusing on the §&§/LΣL part yet
seems like something could be optimized
 
Wouldn't bet on that
 
Ok, I have to go, I think.... Bye!
 
1:35 PM
bye
 
Good luck!
I think I'll add Ohm too
later
 
2:19 PM
@cairdcoinheringaahing you're a genius
I just figured out how your solution works now
 
@LeakyNun Thanks! I thought it was quite a basic solution TBH sheepish grin
Also, you may not have found the explanation
 
 
8 hours later…
10:40 PM
Husk, 8 bytes using caird's algorithm.
11, before I saw caird's
 

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