In your definition of $n$, you create a row vector. x0 would then be a row vector, except that you take the sin of n': n-transposed. So x0 would, I believe, be a column vector. Which means that y0 would be a column vector, and so fliplr would be operating on a column vector and hence do nothing (at least, this would be the case if Octave works as MATLAB does). Did you check that y0 is a row vector, as expected? — Emily Sep 6 '12 at 21:12

@EdGorcenski - x0 is being transposed in the sum() as well, so I end up with a row vector. Typing whos shows all vectors have a 1 in their 1st dimension. — ysap Sep 6 '12 at 21:33

Ah, so it is; I missed that! — Emily Sep 6 '12 at 21:49

@EdGorcenski - I just posted an update to the question. — ysap Sep 6 '12 at 21:49