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Bubbler
12:29 AM
@Mr.Xcoder Isn't it
abs(x1*y2 - x2*y1)
?
6 hours later…
Mr. Xcoder
6:41 AM
@Bubbler It is.
But there is a short way to implement that other than applying the formula itself
Bubbler
6:52 AM
@Mr.Xcoder Sure, matrix determinant of
[[x1 y1] [x2 y2]]
and then abs.
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Jelly Hypertraining
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