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12:29 AM
@Mr.Xcoder Isn't it abs(x1*y2 - x2*y1)?
 
 
6 hours later…
6:41 AM
@Bubbler It is.
But there is a short way to implement that other than applying the formula itself
 
6:52 AM
@Mr.Xcoder Sure, matrix determinant of [[x1 y1] [x2 y2]] and then abs.
 

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