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06:24
@JohnRennie Hi :)
Hi :-)
I'm a little confused regarding the experiment.
So I’m investigating how frequency affects the voltage of a resistor
OK ... ?
I don't understand what you mean by measuring voltage as a function of frequency.
You connect the oscilloscope inputs across the resistor, so you are measuring the voltage across the resistor.
06:28
So this experiment isn't about capacitors anymore, then?
Then you adjust the frequency of the signal generator and you measure the voltage across the resistor for a range of frequencies e.g. from 10Hz to 10kHz.
@Ajay If there is no capacitor in the circuit then the voltage across the resistor will be constant and will not change as you change the frequency.
But when the capacitor is present the voltage across the resistor will be a function of frequency.
Oh, is it going back to that out of phase point?
So the experiment is about capacitors because the capacitor is responsible for the change in voltage with frequency.
@Ajay Are we talking about just an RC circuit, or the RLC circuit that your teacher suggested?
The RLC circuit
Because now I have to change everything.
With the RLC circuit we get the peak in the voltage at the resonant frequency:
ω² = 1/(LC)
When the reactance of the inductor and capacitor are the same something weird happens. The LC part of the circuit behaves as if it has a zero resistance.
That means the circuit behaves as if only the resistor is present i.e. all the voltage is dropped across the resistor.
07:26
@JohnRennie Could you explain this diagram in more detail?
is ωt an angle?
ω is an angular velocity i.e. it has units of angle per second. So if we multiply it by time we get units of angle.
So yes, ωt is an angle.
Ok :)
Thanks
07:53
Hi @JohnRennie
Hi :-)
How far have you got with this?
I know the solution but I am not understanding the question completely.
The question just asks you to find x, so you get x = b/a
Then it asks if this equation is valid for all possible values of b and a, and as we have discussed it is not valid for a = 0.
Yes?
08:00
Yes
That's all the question is asking.
Doesn’t the question mean is the solution you have written valid for all real a and b in eqn ax=b?
Yes, but zero is a real number so the answer is that it is not valid if 𝑎 has the real value 𝑎 = 0.
👍🏼
Sent
For some reason the messages are taking a minute or two to reach me ...
Aha it just arrived!
08:06
😅
What do you think the answer is?
If a quantity x increases by 100% then it becomes x+x=2x.
Correct! :-)
If the value of x=2 and then x increases by x then the new value is 4.
Yes, so the answer to the question is that the new value is 2 × the original value
@cOnnectOrTR12 Exactly as you wrote here :-)
08:17
👍🏼
Sent
How far have you got with this?
First of all x should be -ve.
Yes, although I think you should justify that statement i.e. say why 𝑥 has to be negative.
The way I would do this is to draw the number line and put -21/43 on it.
Shall I draw the diagram?
Because the answer is -ve
@JohnRennie first let me say.
OK, go ahead ...
08:23
Because the answer is -ve
So you're saying that on the left side 13/15 is positive while on the right side -21/43 is negative. And you can only get a negative number on the left side by adding a negative number to 13/15. Therefore 𝑥 must be negative.
Yes?
Now we are adding a number to -ve number and this results in a -ve number. That means x is increasing. So x<-21/43
Adding a positive number to 𝑥 moves to the right along the number line.
And if we end up at -21/43 after moving right that means we must have started on the left side of -21/43.
So 𝑥 must be to the left of -21/43.
08:30
@JohnRennie adding positive to x moves x to the right and adding negative moves x to left.
Correct
And we are adding +13/15 to 𝑥 so that means we are moving to the right.
👍🏼
@JohnRennie My teacher mentioned impedance(and so did you). However, I don't see where the impedance comes in?
Just to be confusing there are different terms for what is basically the same thing in electronics.
The simplest one is resistance as in ordinary resistors where they obey Ohm's law:
V = IR
and for a resistor R is just a constant and does not change with frequency.
OK so far?
Yes
08:44
Now, capacitors and inductors have a similar property that relates the current to the voltage, but for capacitors and resistors it does change with frequency.
To distinguish it from resistance we call it reactance and usually write it as X.
So for both capacitors and inductors we get:
V = IX
where for a capacitor:
X = 1/(ωC)
and for an inductor:
X = ωL
Then finally, we use the term impedance to mean either resistance or reactance so impedance covers resistors, capacitors and inductors and indeed any combination of the three.
So it's really just different words to describe what is basically the same thing.
09:30
Hi @JohnRennie
 
1 hour later…
10:50
From which certain value can we use the term limit the value tends to something in macroscopic level. Or in other words from which value in the macroscopic case can we say its statistically significant and using a limit would give significant errors ?

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