@AvnishKabaj Are you theree??

@Abcd not today I'm studying too

Just post the question I'll see it later on

@AvnishKabaj Nevermind.

@MadhuchhandaMandal How do I send them to you? i have clicked their pictures...and saved them in pdf...

What to do next?

@Abcd You can mail me

(@Abcd I sent you my email address on the other room)

@MadhuchhandaMandal @Abcd can you guys send it to me too?

@MadhuchhandaMandal Sent

@Tanuj Email....

@Abcd Thanks a lot !!!! Its really very helpful

Hello people! I have this pyramid $ABCDE$, and there is a current of intensity $I$ entering the circuit through $A$ and exiting through $C$. Each wire ($AB$, $AC$, $AD$, $AE$, $DE$, $BE$, $CB$, $CD$) has resistance $R$. Noting that the structure is symmetrical when "cut" with the plane $(ABE)$, I've sketched this equivalent circuit. Can anyone confirm it is correctly drawn?

For the record, I am asked to find the equivalent resistance between points $A$ and $C$, $R_{AC}$, and by solving the problem based off my (I hope correct) equivalent circuit, I got $\frac{7R}{15}$.

@JohnRennie u there?

A metal rod having cross section area A length l Young's modulus Y coefficient of linear expansion alpha is supplied 40 calorie of heat. The energy stored in the rod is??

168 joules is not the answer

The rod must be fixed at its ends

In that case , E= Volume of rod* (0.5 k x^2)

Where x is the thermal expansion of the rod