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arctic tern
arctic tern
02:38
@euclid since $n$ is a fixed, $\{\chi:\chi(n)^d=1\}$ may not be the same thing as $\{\chi:\chi^d=1\}$.
not sure what exactly you mean by "when we talk about dth roots of unity"
 
7 hours later…
euclid
euclid
09:34
@arctictern i still dont know $\{\chi:\chi^d=1\}$ is a group(abelian or cyclic) unconditionally or not.
 
6 hours later…
arctic tern
arctic tern
15:11
@euclid (a) I've told you it is many times. (b) If you know what a group is, you should be able to prove it's a group rather easily. This is very worrying. Like I said, you should study basics before you try to read papers.
 
2 hours later…
euclid
euclid
16:55
yes.thank you

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