> It is easy to prove with absolutely no order theory that for infinite X, if X×X bijects with X then P(X)×P(X) bijects with P(X). (Hint: Let c in X. For any set S, let S' = { (0,a) : a in S } union {(1,c)}. Use an injection from X×X into X to get an injection from X' into X, and then get an injection from X'×X' into X, and then consider f : P(X)×P(X) -> P(X) where f(S,T) = { f(a,b) : a in S' and b in T' }.) Also, #(N×N) = #(N) is arguably a number-theoretic fact. These together imply that every set we need in 'ordinary' mathematics would satisfy the desired theorem, without any order theor…