04:27
new-tag deleted-tag A new tag real was created. This does not seem like a good tag name - I have removed it: math.stackexchange.com/posts/3695883/revisions
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Proposal: Remove gre-exam, gmat-exam.
These are meta tags with very bare-bones tag wikis. Furthermore, there aren’t any other tags for important math exams, i.e. the IMO or USAMO, so why should we make an exception for these two?
Posts where the tag gmat-exam was added removed (inlucing the editors): data.stackexchange.com/math/query/1105163/… data.stackexchange.com/math/query/1038474/…
Most frequent taggers/removers for gmat-exam: data.stackexchange.com/math/query/1146497/… data.stackexchange.com/math/query/1038477/…
deleted-tag The tag gmat-exame is gone. The same post on meta mentioned also gre-exam - that one is rather big.
Posts where the tag gre-exam was added removed (inlucing the editors): data.stackexchange.com/math/query/1105163/… data.stackexchange.com/math/query/1038474/…
Most frequent taggers/removers for gre-exam: data.stackexchange.com/math/query/1146497/… data.stackexchange.com/math/query/1038477/…
09:11
new-tag A new tag differentiation-under-integral-sign was created by pi-π. The same tag was created and removed in April: chat.stackexchange.com/transcript/3740/2020/4/21
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Using differentiation under integral sign, prove that $\int_{0}^{\infty} e^{-(x^2+\frac {a^2}{x^2})b^2} dx=\frac {\sqrt {\pi}}{2b} \cdot e^{-2ab^2}$.
My Attempt:
Let,
$$F(a)= \int_{0}^{\infty} e^{-(x^2+\frac {a^2}{x^2})b^2} dx$$
Differentiating both sides with respect to $a$
$$\frac {dF(a)}{da}=...
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14:43
15:39
@MartinSleziak Cool ! (I was just wondering..) Also calculus should make a snug fit with such questions
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