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1:49 AM
A new tag was created by Marine Galantin.
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Q: consistency of Neyman Pearson lemma in the case simple vs simple test for exponential families

Marine GalantinBasics, jump to section 2 for the question : I know that in the case of an exponential family with 1 parameter, meaning the distribution function of the sample variables can be written like : $$ f_X(t) = \exp( \eta( \theta) T(t) - d( \theta) + S( x) ) $$ if we compare two hypothesis like those ...

"Natural parameter" links here. For the usage of this term in differential geometry, see differential geometry of curves.In probability and statistics, an exponential family is a parametric set of probability distributions of a certain form, specified below. This special form is chosen for mathematical convenience, based on some useful algebraic properties, as well as for generality, as exponential families are in a sense very natural sets of distributions to consider. The term exponential class is sometimes used in place of "exponential family", or the older term Koopman-Darmois family. The terms...
 
 
4 hours later…
6:00 AM
 
6:15 AM
I know extremely little about this topic, but we do have a tag , and some questions with this tag seem at first glance to be about exponential family, as in the Wikipedia article.
Sorry, the tag is actually .
Examples of questions about exponential family : this question, this one, another one.
But the tag-wiki for seems more restrictive, so I'm not sure it is intended to cover this usage...
I've replaced your newly-created exponential-familly with the existing exponential-distribution, although I'm not entirely sure it's appropriate as it's out of my area of expertise. If you really want to create exponential-family, it's better to first "test the waters" by posting in the Tag management thread. You can also discuss this in the Tagging chatroom. — Arnaud D. 29 secs ago
 
6:36 AM
Unknown x created a new tag . No tag info. I think that this tag can be safely removed.
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Q: Why should there is a $c\in [0,1]$: $f(c)=f(c+1)$.

Unknown xProblem of continuous real valued function I don't understand Jim's comment on (b). He took $g(x)=f(x+1)-f(x)$. Why should there is a $c\in [0,1]$: $f(c)=f(c+1)$. I can't apply mean value theorem here directly. Since given function need not be differentiable. I am not able to find a condition ...

 

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