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00:02
you need to compute the components of one force, using the other force's direction as an axis. well, if the angle is bigger than 90, to compute the component in the other force's direction you need to cosine that angle, or you could cosine that angle's supplement and then negate the resulting value, either way works
so only if it is over 90 I do 180-angle?
the problems i did in the homework seem like i always just did it that way unless it was worded. Very confused:(
I got the same number though, at least for cos120 and cos60, but cos120 was negative and that made me add the number since the formula is subtract
you shouldn't be trying to memorize rules you don't understand
figure out why you're computing whatever. have geometric understanding.
I don't know why
Book doesn't really say why either, I have no idea how i even figured it out before
Im like freaking out for this test, and feel like I've forgotten everything
:/
00:33
I haven't seen Chris's sis around for a while.
user147690
yesterday, by Chris's sis
@robjohn The form you got is nice.
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They talked to you yesterday haha
@AlexClark Yes, and that is the last time I saw her. That is a long time for her not to be here.
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@robjohn Fair enough. Wait how did you change your picture to inactive?
@AlexClark pardon? which picture?
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00:45
@robjohn Your gravatar(or whatever it is called) top right grayed out when it was the first on the list, I have never seen this happen before
@AlexClark I edited a deleted chat comment, just because it seemed possible. It is marked as edited in the history, but is still deleted.
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@robjohn And that set you to inactive?
@AlexClark Perhaps it had something to do with that. The software may not be able to handle it.
Hey guys, can you actually talk about questions in this room ?
:21543779 no, it was one of mine that I up-arrowed to.
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00:48
Oh okay
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@SpawnKilleR Sure?
Anyone familiar with Fisher information I am trying to solve something but I cant quite understand it :S
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I am not sorry
:21543779 yep, that's what did it.
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@robjohn Did you ever find out what caused all of the people to remain in the chat page after they had exited the browser?
00:51
@AlexClark obviously a bug, but I don't know the nature of it
Anyone good with trig?
@Maximilian what kind of trig?
vectors right now
Teacher gave us questions which he says is the test, and already first one I got stuck
I think i overcomplicated it. did an entire page without an answer
I don't think it would be that hard
"Use the parallelogram method to find the resultant of u and w", u=<2,-5>, w=<3,2>
I found the angles and the magnitudes
magnitude of u was $\sqrt{29}$
and magnitude of w was $\sqrt{13}$
Doesn't the parallelogram method give you $\langle5,-3\rangle$
-_- I was overthinking it
you are correct
I drew that, and then continued on to find something else.. oops
Thank you
 
1 hour later…
02:07
@AlexClark Saw you blogroll, including me there is a little premature!
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@PaulPlummer Oh you view my page haha
Will you still be using that when you "abandon" the challange? @AlexClark
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@PaulPlummer I will continue to use that page. Although I guess I wouldn't be committingtothatchallenge :P
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@PaulPlummer I think I will rewrite the challenge to a 6 month form
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@PaulPlummer Perhaps a 3 month form, but I haven't had time to plan anything out yet
02:10
maybe you should by the domain notcommittingtoachallenge and have you site redirect to there. @AlexClark
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Hahaha perhaps, or maybe Concernedaboutdyinginthefire.com
Mike will be so proud of you
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@PaulPlummer I think I will keep my current one, and just make smaller projects
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And actually commit to them :)
I actually have a site up, but at the moment it is just documentation of the themes and things like that. And an about page
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02:15
I want to start writing posts on actual math that will interest people, but I am still a few months off that I imagine
Hello all.
Have any of you spotted the elusive Tee Dog lately?
-_-
I'll get him someday.
@AlexClark Here it is so far mathsalad.com
02:34
back
02:45
mathsalad
I want one of those math salad
02:59
any finite group can we always find set of generators for it ?
I guess there is always trivial one
Trivial one, @Karim?
I mean all set G @TedShifrin
Oh ... Rather overkill :)
Toooooo many relations!
hey @Ted
03:07
I was thinking how far can we shrink set G so it can generate G ?
morning
for finite groups
Hi @cbjork
68?
I guess there is no really algorithmic way of doing this
03:08
Nope, you blew it ...
ouch...
Not that way.
:D What's the number?
what way ? can we do it I haven't read about free groups yet
03:09
From 2 men and 2 women, 2 people are selected at random. What is the probability that both people selected are the
same sex?

Can someone explain me why the answer is 0.333 and not 1/2?
which is dummit trying to explain that he will make this rigorous at section of free groups
I don't remember. Something like 75.
Well that's a great way to end (compared to 63-68)!
yup. In general, I was disappointed, but not by you. You made me happier. :)
@rubito: How many ways can you get MM? How many ways can you get FF? How many ways can you get MF? How many total combinations are there?
03:11
is he talking about the age?
of retiring or what
@Cbjork
regoodnight @Mike
@Karim Average grade.
Great! @MikeMiller not quite
I WAS CLOSE
03:12
@KarimMansour grade on the final. I have a history of consistency on Ted's exams.
@Cbjork oh I see
I remember now why Chrome drives me nuts :(
@MikeMiller I might be wrong but you can only get MM one way and same with FF, but there's a total of 4 combinations
@rubito: There are not a total of four combinations.
03:14
The bar to type in moves all over and disappears ... On the iPad
You've got four people, and you're choosing two. What's 4 choose 2?
Aye. There are six possible combinations.
24/2 * (4 - 2)
which is 24/2 = 12/2 = 6
yaay
just kdding
03:15
More down to earth: if it's Alex and Bart on one side, and Clarice and Danielle on the other, here are your possible combinations:
AB (MM)
AC, AD, BC, BD (MF)
CD (FF)
damn I wish I could open my brain and put bunch of books there
instead of taking sometime reading them
It doesn't work, @Karim .... Just like memorization rarely works for learning math.
yeah I guess if you open it up and put the book there
then it is memorization
one gotta make connections and intuition in his head too I guess
Yup, understanding is different from RAM access
@MikeMiller So, the probability of both people being of the same sex is 2/6 because the other 4 combos are not
03:18
Yeah
there are 2 combos where both are the same sex, out of six combos total
great! thanks man!
Sure, sure.
$\int _0^1\:f\left(x\right)\left(a-x\right)^2dx=0$
Haha first time to chat... guess LateX doesn't work
@SethKitchen See LaTeX in chat on the right.
03:23
start ChatJax
I'm such a noob :)
It's what it links to, not the text itself. Bookmark the link and then click the bookmark in this room.
Hello all.
Hi @MichaelA.
Thanks! Can anyone explain why that has no solutions for f(x)
@MikeMiller Hi Mike.
03:25
How's things?
Semester's over, so pretty great. How about you?
Still in the quarter here. I was sick this week so fell a bit behind on reading, doing some catchup this weekend.
Where do you guys go?
I'm a graduate student at UCLA.
Hi @MichaelA
03:28
@TedShifrin Hi Ted.
Impressive
I go to Stony Brook.
Where's that?
Long Island, New York.
Sounds expensive
03:28
Home to some of the best geometers alive...
yeah
stony brook nice uni
Seth, your question certainly has $f$ that work .... What's $a$, btw?
f=0 works
oh and it has to be nonnegative
@Seth: It shouldn't be expensive; any reputable PhD program provides their students with stipends that cover both tuition and living expenses.
a is any number i think... not mentioned in the problem
03:30
Well, duh. You need to put that in there. Does it have to be continuous too?
When you ask questions, hypotheses are part of math :D
@MikeMiller Wow. Im an undergrad so excuse my ignorance.
No need for apologetics, I understand.
@Mike just makes me apologize :)
03:32
With you it's fun, @Ted
Oh-oh... could probably have phrased that better.
Hmm ...
Is main down for anyone else?
Not for me.
So, Seth, what happens if your $f$ isn't always zero?
03:34
aw man, people get so snarky with you when you comment without reading their question.
I get snarky too ...
When people don't read my answer and tell me to post as a separate question.
Toss a fair coin 3 times. What is the probability that all three tosses turn up the same?

Is the answer to this 0.125?
I told someone about the unit-speed parameterization, which he mentioned he knew about in the second sentence of his question.
I mean yeesh, people these days, expecting me to read more than the first sentence? :P
03:36
@rubito: does it matter whether the first toss is heads or tails?
ohh!!!!
Let me make f(x)=1... I get $-(a-1)^3/3 + (a^3)/3$.. which isn't zero, but I don't know how you can check every answer
@SethKitchen $$f(x) = \frac{6 a^2-8 a+3}{12 a^2-12 a+4} - x$$ works.
Don't do it by trying to integrate, Seth. Draw a general picture.
There must be some more restrictions on $f$ in order to say that it doesn't have any solutions.
math-cs.ucmo.edu/~curtisc/contest/2014/smomaa14.pdf is the link to the solution... I am just too noob to understand
Nonnegative @Antonio, and continuous!
@TedShifrin Oh I didn't see the nonnegative part.
but like how did you come up with that
@MichaelAlbanese lol
03:39
@SethKitchen Plug in $f(x) = b-x$, solve for $b$.
hm
what does group presentation really help us in
@TedShifrin What do you mean by general picture?
it seems it doesn't really extract information about a group
@Seth. Forget the $(x-a)^2$. It is nonnegative. Think about the general continuous nonneg. fn. what course are you in?
just some abstract thing
03:41
Calc 3... i'm just a freshmen :( .. But I want to be like you guys
Calc 3? Really?
this is like single variable ....
I don't understand how you can check all functions at one time
draw me a positive function with zero area, Seth.
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@Paul How much time did you spend writing the about section haha
You can't.
03:43
@KarimMansour Group representations are extremely concrete. What would you rather have, an abstract group, or a group of matrices?
Right, but how do we know a is not 0?
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@Paul Also why the Github section?
And that does make it easy to understnad Ted. Thanks!
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@SethKitchen I haven't been following, but it sounds like you want to think of the absolute value of a function?
03:44
I mean how do we know a is not 1
I see @pjs36
$a$ is irrelevant.
I am just reading just introduction so I will not be over my head yet until I read everything on free groups later on and discuss it with you guys @pjs36
How do you know though?
@pjs36: Depends.
03:45
@AlexClark Just trying to learn some math stuffs
All that matters is that both $f$ and $(x-a)^2$ are nonnegative.
@KarimMansour No worries! They're also nice for other reasons. For me, I'd prefer to have characters, rather than representations, but that's just because I never learned representation theory :P
@MikeMiller Well, of course! But I'm just pointing out that representations are, in many cases, less abstract than being handed a generic group.
Ok, let's say there is a solution and @AntonioVargas plugs in that $f(x)=b-x$, how do I know the answer that comes out is nonnegative and continuous? I guess I know it is continuous if the denominator is never 0
I should also learn some representation theory this summer too
I guess what I'm really asking is how do I check if it is nonnegative
03:48
@SethKitchen ?
representation theory has historically been a weak point of mine
My answer was wrong. $f(x) = b-x$ isn't necessarily nonnegative.
how do you know?
well if $b=1/2$ then $b-x$ is negative for $x > 1/2$
Yeah, I don't know any of it, @MikeMiller. I just learned character theory (traces of irreducible representations) from those group theorists that taught me all my algebra
03:50
Ok so the only thing I would be able to plug in is some power of x or a positive integer?
lol
group theorists
I claim to have once known something about the representation theory of $S_n$
you say it in funny way @pjs36
@SethKitchen No. Please think more about what Ted is telling you.
I understand that there is no answer. I am just wondering if there was an answer
how i would solve
03:51
Reread that sentence.
there's no answer. How could there be an answer if there's no answer?
I do try, Karim :P
I know for $S_n$, integer partitions just roam freely, but I only ever got the Spark Notes version
I want to be able to apply this to other problems. That's all I'm trying to say.
Sup everyone
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h
03:52
h
@SethKitchen I see. Well there's a wealth of theory regarding solving integral equations - there's no one method.
@AlexClark, you're committing right? Just making sure
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@KajHansen Indeed
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@KajHansen I won't change it again haha
@AlexClark, I'm going to be away from the gym for a little over 2 weeks :(
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03:54
@KajHansen Ahh shit man, those gains :(
Went home, 3 hours away from my top-tier university weight room.
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Do you have $100 you can just buy a barbell and some weights?
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Did you go home by car?
To be fair, I might need it because my shoulder and elbow joints were starting to feel a little strained from going every day. Nothing serious of course.
I used to know an Alex Clark. He went to Westpoint
03:56
Given that in 4 flips of a fair coin there are at least two "heads", what is the probability that there are two "tails"?

Sorry about all the probability questions, I'm studying for a final and I really don't get this stuff
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@KajHansen Do you do overhead press or incline bench dumbbell press?
So maybe it's for the better. I just know I'll be hit with DOMS when I start up again, and it'll be hard to get back into it at first.
@rubito: Stop giving us all your homework.
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@rubito There are either two heads, three heads or four heads, so that means there are so many tails, you have a few cases, and you should know how to consider them
@AlexClark, I do both. I know they put a good bit of strain on the rotator cuff, so I'm always pretty careful with my form
03:57
We could troll him :) @rubito 50 %
Well, @Kaj, I'm done done ...
@TedShifrin Is not homework, I'm going over our review problems and I'm okay with the later stuff but the early probability is what I don't get
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@KajHansen Loading up the incline dumbbell is where I always got injured haha, I quit based on that
@SethKitchen I think I came off harsh in the last message. Sorry about that. I shouldn't be doing something else while chatting :)
Use conditional probability, @rubito.
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03:59
@SethKitchen I don't know what that is sorry. I am in Straya'
@TedShifrin Okay I'm gonna give it a shot
@AntonioVargas You're fine :) You're helping!
@TedShifrin, that's kind of depressing to think about. I'll miss interrupting your office hours :)
Not really, @Antonio. I Said the same thing three times.
@AlexClark It's a military academy in the US
03:59
@TedShifrin Well it's true.
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@TedShifrin But we all know you are harsh :P
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@TedShifrin You are done done now, congratulations! Heaps of time to dedicate to mathematics without having to deal with distracting students
@Ted: "A smooth map $f: M \to M$ which is $C^1$ sufficiently close to the identity is a diffeomorphism." $M$ is closed. Why should this be true?
@AlexClark, I actually go rather light on the dumbbells and save the heavy lifting for the barbell. For one, it's hard just getting into the starting position on DB presses safely.
Lifting < Running
04:01
@SethKitchen, depends on what you're going for IMO. Of course, my cardio is nowhere near where it should be, and running would help with that.
When you don't have compact, @Mike, what does this mean?
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@KajHansen Exactly hahaha. I would grab one with both hands while sitting and pull it onto my knee, and then grab the other with my stronger arm and put it on my other knee, but getting from sitting with that to lying down(on the incline) is where I hurt my shoulder for days on two occassions
Fair enough, @Ted.
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I need a coffee/redbull hmmmm
Can you prove it for compact?
04:03
@AlexClark, to get from knee to starting position, I'd do this weird "kick" from a sitting upright position to get one DB up, and take advantage of the momentum to get the other one up. Kind of dangerous when you think about it.
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@KajHansen Yep that's the stuff that kills my back xD. I have been just doing bench/DL/OH and nothing else for a month and a half, and it's been pretty great for some reason
Wait, @Ted, of course I can. Nevermind.
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Well I better go get a coffee and get back to work
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Cya guys later
04:05
Well I think more than just cardio, losing BMI, stress relief, leg muscle, and thinking time that comes from running far outweighs the nut bursting, constipation, and aneurism that is weight lifting.
What do you mean in general?
That's truly not bad at all @AlexClark. If I did that, I might throw in some forearm stuff for the grip strength. Especially since my DL is getting too heavy for me to maintain grip. Anyways, see you around!
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@SethKitchen I do 5 minutes a day, every day, just three sets atm a day, and its been great and so little time/effort
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@KajHansen I'm using straps now :)
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Bye
04:06
sufficiently close on something compact means you can bound the derivatives away from being nonsingular; local diffeomorphisms of closed manifolds are surjective, and thus are covering maps; I can't possibly homotope this diffeomorphism to be a nontrivial covering map.
@AlexClark Haha I'm just messing with you.
Night all ...
@SethKitchen, there is some major stress relief that I get from weightlifting. The endorphin release from deadlifting alone is enough to keep my depression and anxious thoughts at bay for the next few hours.
nights @TedShifrin
@Ted: I don't, the question is only posed for closed things. I guess with the right definition of $C^1$ topology on the space of smooth maps of something noncompact you can use the same argument to show that it's a local diffeo; I'm not sure if I should buy that it's still a diffeo.
04:07
@TedShifrin night thanks for the help
See you @Ted!
Let $T_o$ be an isosceles triangle with base b and base angles a. Define a sequence ${T_n}$ n from 0 to infinity of triangles recursively as follows. The base of each triangle $T_n$ is b, and the base angles of triangle $T_n+1$ have half the measure of the base angles of triangle $T_n$. Evaluate lim n->infinity $2^n*area(T_n)/area(T_o)$
how do I know base angles are $a/2^n$ ?
Because $a/2^n = \frac{1}{2}a/2^{n-1}$ is half of $a/2^{n-1}$, which is half of... which is half of $a$
@AlexClark Because I took the template from someone, and the template linked to their github. I spent like a minute on the about page
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04:24
@PaulPlummer What sort of statistics do you get to collect?
I don't plan on setting up any sort of statistics
And not sure
I think it could be a bit, I would just have to set it up
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@PaulPlummer Not even view counts??
Not sure what I would use it for, maybe if I want to get depressed I would set it up :D
Does this digram look correct?
I know I could set up google analytics @AlexClark
04:27
wordpress seems to come with analytics
wow, someone went through and clicked all the links on my blogroll
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@PaulPlummer I think it is nice to see it build up over time(although mine has done the opposite for obvious reasons)
@MikeMiller I think that was me
A couple hours ago
and would I start it as $cos^2(A+B)-2cos(A+b)+1+sin^2(A+B)=cos^2A+2cosAcosB-cos^2B-Sin^2A+2sinAsinB-sin^‌​2B$
only one person did it, so it must have been
Actually I don't think I clicked on the whats new, terry tao blog
Not sure why I clicked on the rest though, I had been to all of them but the floer homology
04:32
floer homology isn't really for anyone but me
i only put it there to remind myself of it later
Haha, I saw a talk at JMM of someone doing some interesting stuff with floer homology and knots or links or braids (don't remember), I didn't really understand the floer homology, but it seemed like it had a nice geometric interpretation
i'm trying to understand floer homology now
It was actually one of my favourite talks, seemed like really cool stuff
well, heegaard floer; floer homology in general is absurdly broad
it just means "morse theory on infinite dimensional manifolds"; when one uses it on a 4-manifold, say, they associate an infinite dimensional manifold and a Morse functional on it and then do Morse homology on that. oftentimes this infinite dimensional manifold is something like the space of solutions to a certain PDE
04:35
"it just means..."
morse theory = studying a function whose critical points don't suck
given a morse function on a smooth manifold you can reconstruct the manifold from it.
there's a notion of Morse homology, which ends up spitting out singular homology in the finite dimensional case; that's no longer true in infinite dimensions, which is why it's nice
eg here's an example of how it might be useful. if I give you a smooth manifold and a function on it that has exactly two nondegenerate (not messed up) critical points, then the manifold must be homeomorphic to $S^n$
this is how Milnor proved that his exotic 7-spheres were actually homeomorphic to $S^7$
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@MikeMiller Are these $C^n, S^n$ things inaccessible to me? I keep reading them and they are bugging me
@Maximilian Can't help you there myself at this time Max, but I'm sure other people in this room know Trig and can help out. :)
$C^n$ function = function that's $n$ times differentiable, and whose $n$th derivative is continuous
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Ahhh I have seen this in normal contexts
04:39
$S^n$ is just an $n$ dimensional sphere
$S^n$ = n-dimensional sphere, $\{(x_1, \dots, x_{n+1}) \in \Bbb R^{n+1} | x_1^2 + \dots + x_{n+1}^2 = 1\}$
user147690
Ahhh alright, easy enough
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But you have equal there, so it is the surface of the sphere
no, the terminology is that that's the sphere
user147690
Or the shell of t he sphere so to speak
04:40
what you're thinking of is called the unit ball
user147690
But the sphere is hollow correct?
I think I got 99 votes @AlexClark
user147690
That's what I meant
I don't understand what you mean then
04:42
That is the definition of a sphere, if it wasn't "hollow" then it wouldn't be a sphere
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@PaulPlummer Wow, you are in a tie with Yes for the week, nice!
what I was talking to Ted about is the notion of two smooth maps being "$C^1$ close"; you can define a norm on $C^1$ functions on a compact smooth manifold (concretely, on $[0,1]$), and two $C^1$ functions are $C^1$ close if both them and their derivatives are close; if you learn about the sup norm I mean that $\|f\|_{C^1} = \|f\|_{sup} + \|f'\|_{sup}$
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Yes the sup norm is the $p=\infty$ norm
yes
also known as the $C^0$ norm
user147690
Oh I haven't heard that before
04:44
different name, same thing
user147690
What does $C^1$ close mean?
user147690
Oh you define it immediately
$f$ is $C^1$ close to $g$ if $\|f-g\|_{C^1}$ is small
how small 'small' is depends on the situation
user147690
Oh okay, that makes 'some' sense
54 points away from delete votes lol
04:47
Nice, I will have to recruit for my ring of thugs that delete things
you've got to catch up
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@PaulPlummer I am out of that game lmao, I can't even cast downvotes
where do you find the questions that need to be pushed over by a vote or two for community
deleting that afterwards lest we sound like the mob
actually no
user147690
@MikeMiller Well the easiest place is the front page haha, otherwise page 24000 arranged by votes
04:49
lol
@MikeMiller Read here
Too many bad questions have answers with a lot of votes
Then you can use advance search, to for example search for questions with no answers and zero votes, or something close to that
For example
answers:0 isanswered:no hasaccepted:no closed:no score:0 created:2014-09
Or you could search for closed questions, although I will have to see if there is a way to filter out questions with high voted answers

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