fraid not ... Now since I'm planning to take only carry-on luggage (2 day trip), I'm looking at the list of what I can't take on the airplane. ule pills
That's just nuts, @robjohn. Usually I take long trips, so I check a bag, but for 2 days and a tiny bag it seem a waste of money and of time (which I won't have tomorrow night).
abc-conjecture only gives me partial results. For $k = 2$ it seems there are no more than $2$, for $k = 3$, looks like $3/2 \cdot n^{1/2} + O(1)$. I haven't generalized.
Okay, yeah, so I'm trying to show that $ [-1,1] \times [-1,1] \rightarrow \mathbb{R^3}$ given by $(x,y,z) \rightarrow ((1+\cos (\pi t_1))(\cos (\pi t_2)),(1+\cos (\pi t_1))(\sin (\pi t_2),\sin(\pi t_1))$ is 1-1
@TedShifrin If I have a homogenous $G$-space $X$, is there automatically some group $H$ such that $X \cong G/H$ with the $G$-action given by multiplication?
@Mike: By definition of homogeneous space, $G$ acts transitively on $X$, and then (perhaps assuming $G$ connected) $X\cong G/G^o$, where $G^o$ is the isotropy subgroup of a point.
