Mathematics - 2013-03-15 (page 1 of 5)

Karl's students

00:16

@κρανίοπεριπολία Did you steal my belonging? :-)

κρανίοπεριπολία

@Karl'sstudents No, I just borrowed your artistic work.

Karl's students

@κρανίοπεριπολία :-) When will you return it?

κρανίοπεριπολία

@Karl'sstudents ;-)

@Karl'sstudents Who is Karl?

Gauss?

Karl's students

@κρανίοπεριπολία Karl is a math and chemistry high-school teacher.

He used to create the graphics in his worksheets and
exams using LATEX's {picture} environment. While the results were acceptable, creating the graphics often
turned out to be a lengthy process. Also, there tended to be problems with lines having slightly wrong angles
and circles also seemed to be hard to get right. Naturally, his students could not care less whether the lines
had the exact right angles and they nd Karl's exams too dicult no matter how nicely they were drawn.
But Karl was never entirely satised with the result.

κρανίοπεριπολία

@Karl'sstudents What is the name of your "image"?

Karl's students

00:22

@κρανίοπεριπολία google.com/…

who play command and conquer here?

Peter Tamaroff

Dis be a dupe

caveman

user19161

00:46

@PeterTamaroff Morning Pedro, I just woke up.

Peter Tamaroff

@JasperLoy Just woke up? What time is it there'

Alexander Gruber

WHEW.

just got accepted to grad school, bout to write some papers with this OG.

2

time to go get wrecked. catch y'all later.

Peter Tamaroff

01:04

@AlexanderGruber Wrecked as in wasted/drunk?

@AlexanderGruber WOW, that guy looks like DA BAWZ.

κρανίοπεριπολία

later

Tobias Kildetoft

01:31

@AlexanderGruber congratulations

user19161

01:47

@PeterTamaroff It is 0947 now.

anon

anyone know what's being referred to?

user19161

@anon Not sure what rules.

user19161

OMG, Pedro got a star for saying such a normal thing?

anorton

@anon My guess is she is referring to something from this thread: meta.math.stackexchange.com/questions/8740/… or this thread: meta.stackoverflow.com/questions/165928/…

(It's a bit of a stretch, but possible...)

amWhy

02:04

@AlexanderGruber Congratulations, Alex! :-D

user19161

Changed to the brown square.

user19161

@amWhy Is it a slow night again?

amWhy

02:23

@JasperLoy So-so...I'm not going to worry about it! I've been staying up late these days, and sleeping in a tad, as a result.

@JasperLoy How are you?

Tim

Is there some online website that can OCR a scanned pdf book?

The one I was using is down now.

Thanks!

I am also looking for downloading this Springer book in the closest university library. But they don't have access to it. Does someone have the access to it?
http://link.springer.com/book/10.1007/978-1-4684-0198-1/page/1
Elements of Multivariate Time Series Analysis, by Gregory C. Reinsel

Thanks!

user19161

02:50

2

A: How do I transform the left side into the right side of this equation?

There is a more conceptual explanation. The complex conjugation is an automorphism of the field $\mathbb{C}$ of complex numbers (this easy to see from any from the definitions of $\mathbb{C}$). It follows that the norm function $N : \mathbb{C} \to \mathbb{R}, z \mapsto z \cdot \overline{z}$ is a...

user19161

Wow, this answer is deep man!

amWhy

@JasperLoy I find many of his posts to be incredibly pretentious, certainly not directed to the OP or any future asker with a similar question!

anorton

@amWhy Do you not find the answer at least a little bit interesting? I appreciate when people answer a question with a more in-depth answer than required (or probably wanted) by the OP. It makes things more interesting for those of us who have finished high school algebra... :)

amWhy

03:18

@anorton I know, and it is welcome. But the poster in question exclusively seems to answer in this mode, and at times, it strikes me as being pretentious and vote-seeking. And I usually appreciate when one posts a conceptual, deeper level answer, that they acknowledge that it may not seem helpful at the time...oh well, just my peeve. If you knew me, you'd know I think of everything deeply, but I try to pick and choose when and if it might be appropriate to answer on a deeper-level.

Peter Tamaroff

03:46

@amWhy I added an answer.

user19161

@amWhy Ah, maybe he is naturally deep.

amWhy

@JasperLoy Perhaps, but so am I, but I try to restrain myself, simply because I'm sensitive to those who are not yet deep, and their needs, too. But, to each one's own :-)

@PeterTamaroff I upvoted it, but I'm glad you "took the deeper dive" without the appearance of "vote-seeking" from other regular users...(making it CW)...plus, you qualified, not pretending the OP would "get it".

Peter Tamaroff

@amWhy Thanks.

amWhy

@PeterTamaroff You're welcome, Pedro!

Peter Tamaroff

@amWhy This one is another quintessential example =/

amWhy

03:54

@PeterTamaroff Exactly, and if you look, there are MANY!

user19161

My posts are the opposite of his, all of the level of 1+1=2.

amWhy

He answers questions, which if his answers could be understood by the OP, wouldn't have been asked in the first place!

user19161

math.stackexchange.com/questions/330902/… I am closing this as not a real question!

amWhy

@JasperLoy Not you, Jasper! ("he answers questions...") Your posts aren't all at the level of 1 + 1 = 2! :-)

Peter Tamaroff

I'm off to sleep.

Bye byes, peoples of the math.

amWhy

03:58

@PeterTamaroff g'night!

@JasperLoy me too!!

anon

mfw user after user posts nonsense, or otherwise sends us on wild goose chases

Sanchez

04:14

Anyone knows a little geometry here?

BenjaLim

@Sanchez Hey!!!!!!!!!!!!!!!!!!!!!

Sanchez

Wow hey! Long time no see.

BenjaLim

@Sanchez I miss you so much

Sanchez

haha

how's AG going?

BenjaLim

starting chapter 3 of fulton

@Sanchez Gonna try some exercises in hartshorne on intersection numbers!

Sanchez

04:17

Nice :)

BenjaLim

@Sanchez And my supervisor also asked me to show that the singularities of $y^2 - x^3$ and $x^2 - y^2$ are not the same

by looking at completions

Sanchez

ah ha

BenjaLim

@Sanchez classification of singularities, is there one?

Sanchez

Yes

BenjaLim

ah

Sanchez

04:19

Well, not in your sense probably.

BenjaLim

@Sanchez in fulton he proves some properties of the intersection number

in chapter 3

Sanchez

huh

BenjaLim

the proofs look quite long

Sanchez

I think there's a classification of singularities of say, surface

BenjaLim

do you know where I can find a slick proof?

Sanchez

04:19

I find it weird

What is the definition of intersection number you are using?

BenjaLim

Let $F,G$ be plane curves

then the intersection number is $\dim_k \mathcal{O}_{P}(\Bbb{A}^2)/(F,G)$

Sanchez

You have to localize I suppose.

In any case, don't remember this definition.

Convince yourself by whatever means that all the properties he listed are natural

it's more natural to first list those properties and then prove that your definition is the unique one satisfying all those

BenjaLim

yea sorry he proves that the definition satisfies those properties

Sanchez

Oh well, then it's just a checking, ie the proof is not important. It should be pretty routine except maybe one property It hink.

BenjaLim

yea i think it's 5

Sanchez

04:23

what's that?

BenjaLim

property 5

Sanchez

Yeah, what's that?

BenjaLim

@Sanchez property 5 of page 37: www.math.lsa.umich.edu/~wfulton/CurveBook.pdf

Sanchez

Ah I see.

BenjaLim

@Sanchez I have a gut feeling that if you invoke some high level comm. algebra crap

that it is easier

Sanchez

04:26

I doubt that.

BenjaLim

why?

Sanchez

I don't see how the content of this can be rephrased in "higher" language

BenjaLim

in terms of localization?

Sanchez

so?

BenjaLim

well in that language maybe the proof is easier?

But anyway one of the exercises talks of the hilbert samuel polynomial?

Sanchez

04:28

I don't believe that, anyway.

That's very useful

BenjaLim

yea

@Sanchez Really wanna learn about that crap

Sanchez

oh that should be quick

BenjaLim

howcome ? @Sanchez

Sanchez

if you just want to know what hilbert polynomial is

BenjaLim

I see atiyah - macdonald has stuff bout that

Sanchez

04:32

yeah

So you probably have read about it

BenjaLim

@Sanchez what about completions? I haven't studied those before.

I wanna know enough of completions to show why two completions are not isomorhpic

Sanchez

you mean in your case of $y^2-x^3$ and $x^2-y^2$?

BenjaLim

@Sanchez well don't tell me

but I'm asking where should I read about completions to get up to speed quickly

not sure about AM

Sanchez

Your question can be done by brute force I think

so it isn't like you really need to know anything about completions

BenjaLim

ok but probably i should know about them

he's giving me all these things because he thinks fulton's book is too easy

Sanchez

04:35

AM should be a good place to start then (if you want to learn about artin-rees that kind of thing)

BenjaLim

the thing is they start talking about completions of modules, graded shit

Sanchez

Eisenbud is always a good thing to look at.

BenjaLim

yea

hmm maybe there then

Sanchez

just treat them as expand things in terms of power series

BenjaLim

@Sanchez There's so much shit in AG

fuck

Sanchez

04:37

haha

good luck

BenjaLim

I feel like

I'm standing in front of olympus mons

@Sanchez Sometimes I question if I'm even capable of doing this shit

Sanchez

You can, just be patient.

BenjaLim

yea

@Sanchez I feel like there's so much shit I need to know

fuck

Sanchez

oh you are gonna feel that for a long time.. haha

BenjaLim

@Sanchez man

Sanchez

04:41

Anyway, gotta go now. Talk to you later :)

BenjaLim

ttyl @Sanchez

hang around more

anon

05:08

Let $K$ be a field complete with respect to nonarchimedean absolute value $|\cdot|$. Let ${\cal O}:=\{x\in K:|x|\le1\}$ and $\wp:=\{x\in K:|x|<1\}$. Then $\wp$ is uniquely maximal and prime as an ideal of $\cal O$. I want to prove that for some $c>1$ and for all $x\in\cal O$, $|x|=c^{-v_\wp(x)}$, where $v_\wp$ is the $\wp$-adic valuation (i.e. it satisfies $(x)=\wp^{v_\wp(x)}I$ for $(x)$'s unique factorization, where $\wp\nmid I$ as ideals). Ideas?

(This is to show that every finite valued field extension of ${\bf Q}_p$ is the completion of a number field and vice-versa.)

El'endia Starman

05:51

Hey guys. Math question here: suppose you have a surface ( x,y independent, z=f(x,y) ), and any route on the surface that goes from (x1,y1) to (x2,y2) ends up at the same z value. What is this property called?

Oooh, LaTeX support for chat? $$e^{\pi i}+1=0$$

anon

yes, we have latex support, you have to use a bookmark to activate it

that property doesn't really have a name I don't think

κρανίοπεριπολία

What do you mean by "ends up at the same z value"?

El'endia Starman

@anon Oh, excellent. Thanks!

@κρανίοπεριπολία Imagine terrain with a cave system and you're outside of it. At any point inside the cave system, there is a point on the ground above it. You walk different paths to get to those points.

anon

@κρανίοπεριπολία meaning a path p:[a,b]->R^2->R^3 has p(a)=p(b)

κρανίοπεριπολία

path independent as opposed to path dependent

El'endia Starman

06:02

@κρανίοπεριπολία Yes.

Is there not a more-concise term for that?

κρανίοπεριπολία

path-independent ;-)

El'endia Starman

Darn. :P

Jayesh Badwaik

I am not sure what you are actually asking. if $z=f(x,y)$ is a function, then whatever path you approach it by on the surface, when you get to $(x_2,y_2)$, you will always have $z=f(x,_2,y_2)$.

El'endia Starman

D'oh. I guess it wouldn't strictly be a function if $(x_1,y_1) \ne (x_2,y_2)$ and $f(x_1,y_1) = f(x_2,y_2)$.

κρανίοπεριπολία

It be a one-to-one correspondence property of the function.

El'endia Starman

06:08

Something like this:

anon

@El'endiaStarman no, that's perfectly possible for a function.

your picture shows a different type of situation though

Jayesh Badwaik

@anon he/she probably meant to say the other thing.

anon

presumably you want something to do with monodromy and riemann surfaces

El'endia Starman

Well, the reason I'm asking this is that I'm working on a chess engine that is intended to work with fairly arbitrary boards, which will include situations where a bishop can move one step and end up in one of two places.

anon

then nevermind about the monodromy thing

El'endia Starman

06:15

By the way, this is the question of mine that I pulled that picture from.

anon

it is still not clear to me what you are asking

El'endia Starman

hmmm

anon

you could call it "winding"

El'endia Starman

almost

I'm trying to think of a good way to reproduce a sample board here in chat.

anon

As I understand, you have a surface in R^3 that looks like the above, where locally it can be given by z=f(x,y), but not globally since then it would be multi-valued, and you want a name for a path that goes from (x,y,z1) to the point on the surface directly above it (x,y,z2)

El'endia Starman

06:20

Your description of the surface is correct, but I'm looking for the term for such a surface that has such a path.

A regular chess board wouldn't have this property, and neither would one that wrapped around on all edges (topologically forming a torus).

The one I'm using as a conceptual test allows a piece to move from A1 to H8 by going across either of the corner edges.

anon

noun: staircase. adjective: ramified.

see also these three sections for more terminology

I strongly recommend using ramified, as it is perfect for what you want, and is a very rich mathematical word.

El'endia Starman

@anon I like it. Thanks! :)

anon

good luck on your doohickey

El'endia Starman

@anon Hehe...thaaaanks...

Matt N.

06:37

@JonasTeuwen Ok, I'll remember that.

Jonas Teuwen

07:25

@MattN. Good!

Hemingway only regretted one marriage. After signing the certificate he went across the street to a bar, and the bartender asked him 'what shall it be?' to which he replied: 'Hemlock'.

user585104

The same stuff that did in Socraties.

*Socrates

Jayesh Badwaik

@user585104 He used hemlock as a divisor. :P

user585104

Yep ;-)

Jonas Teuwen

Mr. Hemingway I presume?

Jayesh Badwaik

No, it was an OT remark. By the way, Hemingway's father, brother and sister all committed suicides.

user585104

07:37

Indeed.

Jonas Teuwen

@JayeshBadwaik Yes, mood disorders are quite annoying.

And the bipolary ones quite inheritable.

Jayesh Badwaik

I see.

Jonas Teuwen

I believe one of his sons also did that.

user585104

What isn't inheritable?

Jonas Teuwen

Many things.

Loss of limbs due to trauma for instance.

user585104

07:39

I meant behaviorly...

Jayesh Badwaik

@user585104 Are you in the party zone right now?

user585104

No.

Jonas Teuwen

Many things can be, but very hard to show due to confounding.

But for bipolar disorders, you don't need much thought to notice it is.

As they tend to be very severe.

Hopefully he has more peace now.

Jayesh Badwaik

Ohh. I'm sorry. :-(

Jonas Teuwen

Too many people die of that. Too bad.

Hmm. It is quite painful for the ones left over, but the person itself is in many ways better off in my opinion.

Jayesh Badwaik

07:42

I see.

How do people die of it? Suicide? Or complications?

Jonas Teuwen

Yes.

Often suicide.

Otherwise heart or kidney diseases.

Things get more complicated after a while after the thyroid gland starts failing.

The connection is so strong they started research lines on the autoimmunologic aspects.

Jayesh Badwaik

Ohh.

Jonas Teuwen

Infection markers are much increased in the blood of patients ánd their relatives (even say adopted ones).

It is even stranger: if they have children, the ones that will develop the disorder have much higher levels of those than their brothers or sisters who don't.

Jayesh Badwaik

Adopted ones too? Curious. Contagion?

Jonas Teuwen

But most often, suicide kills them before anything else can :-).

No, genetic is the preliminary conclusion.

Jayesh Badwaik

07:46

But adopted?

Jonas Teuwen

It's so extreme, it almost has to be neurobiological.

Oh no, I mean say separated twins, or child adopted from a bipolar parent.

So, would grow up in a 'normal' family.

Jayesh Badwaik

okay okay... so pointing even more to the genetic link...

Jonas Teuwen

The suicide thing is also interested: the mood disorders run in families. But so do the suicides!

(together with the mood disorders).

You could have families with quite severe mood disorders and no suicides. The same kind of family with plenty.

Also, around the same age and method is the 'same' (usually quite violent).

That's quite peculiar: so many ways to kill yourself, but only a couple are used.

They seem to link this to 'desentisation to pain' - people that are less sensitive to pain are more likely to kill themself in combination with one of these major mood disorders.

But given all that, it still is painful. I know.

It is quite hard to set up research with such patients because you would like to separate 'disease' from 'complications due to treatment (e.g., medications)'.

For one, at least in NL, there are no patients to be found which never had treatment (treatment naive). Secondly, it would be unethical if you find one to not at least offer the treatment.

Jayesh Badwaik

So, no placebo group?

Jonas Teuwen

In the latter case they all accept 'oh? there can be something done about that?'.

Matt N.

07:52

@JonasTeuwen I will also remember to bring ear plugs. Then I can work while the mong is giving their presentation. Just need to sit towards the back end of the room. Problem solved.

Jonas Teuwen

It's not really placebo, but if they with to find this inflammation markers, you would like 'clean' people.

@MattN. Yeah! Just relax.

Matt N.

: )

Jonas Teuwen

I once brought some whisky, the professor said 'no alcohol in the room!'. I was like, alright and drank it on the spot.

3

Was not such a good idea.

Matt N.

The whole bottle?

Jayesh Badwaik

@JonasTeuwen Write that in once sentence and it gets starred.

Jonas Teuwen

07:53

There was not much left.

Matt N.

Ah.

Jonas Teuwen

Done 8-).

Still enough to get me wasted in 15 minutes.

Matt N.

Haha.

Jayesh Badwaik

Hahaha.

Jonas Teuwen

Just go there, if it is annoying you start listening to music or whatever (but sit in the back).

If you do the lecture yourself, you wouldn't want people to get annoyed by you, so it is ok if they do something else.

And at least, they fill up the room, looks better.

Jayesh Badwaik

07:55

Off for lunch, see you guys later.

user585104

What age were you when you had your first drink?

Jonas Teuwen

Like at my master defense. One of the professors got in and before I even started he already got his crossword puzzles out.

16?

Matt N.

If I do the presentation and the idiot doesn't keep their face shut I'll directly address them and tell them to either stfu or gtfo.

Jayesh Badwaik

@user585104 9? it was wine?

Jonas Teuwen

@MattN. Yes, that's good.

But if they are just silently doing something else 8-)).

Oh, you mean soft alcoholic beverages.

Like wine, beer.

Hmm... don't know. 14?

Matt N.

07:56

No, the problem with this person is that they are noisy and a complete idiot.

Jonas Teuwen

@MattN. Yes, kick them out.

Matt N.

If they were silent they wouldn't annoy me!

Jonas Teuwen

Perhaps they are not aware, so you should tell them.

Matt N.

Obviously.

Jonas Teuwen

Yes.

If they seem to be aware, look very pissed off.

Matt N.

07:56

If only the idiot wouldn't talk to me at all. I feel like every time the soundwaves collide with my ear drums my "IQ" drops by 2 points.

Jonas Teuwen

You know, gorilla face, with teeth etc.

Hehehe. I know the feeling.

'Don't fuq with me. I'm about to explode.' - sounds better in Dutch.

Matt N.

: )

Jonas Teuwen

'Je moet niet met me fokken! Ik sta retestrak!'.

Strak is like when a membrane is really tight, so the 'rete' is just like 'ass', you can also replace it with a disease.

Matt N.

: D

Jonas Teuwen

Alright, I'm off for a walk. Bye bye.

Matt N.

08:00

See you later!

Dominic Michaelis

hi

user585104

hi

Dominic Michaelis

oh the first time i asked someone to extend the discussion in chat and he doesn't come

Karl's students

Hi folks

Bogus Boy

1

1+3=4

1+3+5=9

1+3+5+7=16

Dominic Michaelis

08:15

ah you are proving that hte sum of all odd numbers are squares

Bogus Boy

Sum of consecutive odd integers is a square

I forgot this but was only recently reminded

again

Dominic Michaelis

there are a lot of nices proves for this one

Bogus Boy

How do you prove if a number is prime or not

get a big number like 12342123

?

Jayesh Badwaik

Primality Tests the most famous one being AKS Primality Test as of now.

Bogus Boy

Can you explain that?

Dominic Michaelis

08:17

there are several tests

Bogus Boy

I want to get a real big number looking like a prime and see if it actually is

what's the algorith

Dominic Michaelis

for example you could check if it is at least a pseudo prime

Bogus Boy

a pseudo prime is?

I am sorry I am not up-to-date with the jargon

Jayesh Badwaik

@BogusBoy There is no fixed algorithm, there are many different algorithms you can use. Starting with simple stuff such as a prime is of the form $6n \pm 1$ you can rule out majority stuff, and then apply more advanced algorithms.

Bogus Boy

you need a computer to run this stuff for you

you can't check it manually right

for big numbers?

Dominic Michaelis

08:19

wolframalpha PrimeQ[...]

Jayesh Badwaik

Well, it depends, if the big numbers is 22342342348976238964287647823648726482368236482376482376482736482364823764823764‌82736482736482376825 then you can obviously see it is not a prime.

Bogus Boy

so if you were asked to come up with 2 6digit prime number sin one minute

a number ending in 5 or 2,4,6,8,0

will never be prime

got to be

1,3,7,9

Jayesh Badwaik

Coming up with even a 2 4digit prime numbers will be difficult for me in one minute.

Bogus Boy

haha

user585104

Use The Sieve...

Bogus Boy

08:21

what's that

user585104

of Eratonese

Jayesh Badwaik

@user585104 that would be too length again, but good point

Dominic Michaelis

erastotels sieve

Bogus Boy

ok I read that

1
1+3=4
1+3+5=9
1+3+5+7=16

helped some apple engineer to come up with a way to quickly draw circles

how could it?

Jayesh Badwaik

$(x)^2 + (y)^2 = 1500^2$, $1500$ is in pixels

Now you want to draw the circle, what do you do?

x=0, then $y = \sqrt{1500 - x^2}$

Now, either you need a Floating Point Unit (which is an expensive in time computational resource) to find the square root

Bogus Boy

08:26

FPU?

Jayesh Badwaik

or you can use some kind of approximation using integers using the above property.

Bogus Boy

hmm

But I still don't get how "sum of consecutive odd numbers is always a perfect square" insight can help you draw circles quickly

Jayesh Badwaik

I forget exactly how he did it, and I am not able to find the link to that story right now. but the idea is this recursive relation helps save time
\begin{align}
&x_n=x_{n-1}+1 &y_n^2=y_{n-1}^2- 2x_{n-1}+1
\end{align}

Instead of calculating squares all the time

I do not exactly remember what he did with the square root, but he used some similar trick.

Bogus Boy

ok

I have another question

Jayesh Badwaik

askaway

user585104

08:35

@BogusBoy The Sieve of Eratosthenes

Bogus Boy

if you are asked to find out all the colors(hex values) on this page that are in the form of a rectangular band and have area greater than a given minimum. How would you approach it? Like my previous chat is a light bluish band that must be a part of the result.

you have a png snapshot of this chat page

Nimza

Hello

Bogus Boy

got that sir. Thanks

user585104

hi

Jayesh Badwaik

@BogusBoy there are many image processing techniques for this. There are two methods, you can either scan by line, which can be a good method too, or you can detect borders using delta algorithms and then determine the color inside the borders and the area of rectangles enclosed by the borders. The second technique is much more general since it allows you to detect a lot of shapes apart from rectangles.

Bogus Boy

08:41

Hmm

Jayesh Badwaik

By delta algorithms I meant edge-detection.

Bogus Boy

@JayeshBadwaik Thanks

I learned a few good things today. Now I have to go back to work.

user19161

09:17

So many zombies in this chat.

κρανίοπεριπολία

Not enough bananas :-D

user19161

I got some new meds today.

κρανίοπεριπολία

Have you tried them yet?

user19161

Just popped some in.

κρανίοπεριπολία

I hope they help.

user19161

09:21

Yes, together with the bananas in my fridge.

κρανίοπεριπολία

Bananas are good for you.

user19161

I saw a user today with two different profiles, maybe they are siblings and associated their accounts.

κρανίοπεριπολία

Maybe.

user19161

One is A aged B on site C, and the other D aged E on site F.

user19161

So I see the different profiles when I click on C and F which are associated.

user19161

09:26

Or maybe this guy has split personality...

user19161

Or maybe they are just fake profiles...

Vrouvrou

hi

user19161

Hi! It is better to ask nontrivial questions on the main site.

user19161

Chat is for trivial questions and long discussions.

Vrouvrou

how are you

user19161

09:27

Me? I am bad, thanks for asking. Why am I bad? That is my secret...

Vrouvrou

can i help you ?

Dominic Michaelis

hi jasper

user19161

@Vrouvrou No, only I can, and maybe God.

user19161

@DominicMichaelis Hi! How are the pancakes?

Dominic Michaelis

all eaten :(

user19161

09:30

Well done! They must be delicious.

Dominic Michaelis

they have been

i ate as much till my stomach hearts :D

Vrouvrou

^_^ as we say i my country "incha allah"

user19161

@Vrouvrou What language is that?

Vrouvrou

Arabic

i'm from Algeria

user19161

Ah, I was guessing too.

Vrouvrou

09:36

tell me you know something about the use of differential geometry in critical point theory ?

Dominic Michaelis

09:48

i hope he doesn't try to find a pattern math.stackexchange.com/questions/331063/…

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$Mathematics$ Mathematics