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Charlie
Charlie
12:00 AM
@draks... tell us your name :)
 
user19161
@draks... Never saw Joe.
 
draks...
draks...
I'm draks ...
 
Charlie
Charlie
hmm :/
 
user19161
Why did Asaf delete his answer?
 
draks...
draks...
@JacobBlack sure you didn't. You're still here...
 
user19161
12:02 AM
@draks... Justin Bieber=Jason Bourne=Jacob Black=James Bond. QED.
 
draks...
draks...
@JacobBlack whoow I didn't realise that. Let there be Wodka, shakin' not stirred...
 
Charlie
Charlie
@draks... hahaha
 
Henning Makholm
Henning Makholm
@JacobBlack It wasn't really to the point, since OP didn't seem to be trying to use arithmetic on "infinity".
 
user19161
@HenningMakholm Ah yes.
 
Pilot
Pilot
Hi everyone, I have question about Riemann Stieltjes Integral topic
 
draks ...
draks ...
12:09 AM
and I have a bounty ongoing:
11
Q: Two Representations of the Prime Counting Function

draks ... The bounty will be granted for the best work out of Greg's answer. Since Raymond's contributions might be very helpful to recall the necessary math, upvoting his answers is highly appreciated... I have two representations of $\pi(x)$: The Prime Counting Function $\pi(x)$ is given $$ \...

prime-numbers riemann-zeta
@Pilot sorry, please go ahead. I'm sure somebody can help...
 
Jonas Teuwen
Jonas Teuwen
Hell yeah.
I have a new phone - why does an Android phone need windows to update?
Also - I want to uninstall the call software 8-).
 
Orange Harvester
Orange Harvester
@JonasTeuwen Eh? I never had windows and still managed android well. Upgraded the android too.
 
Jonas Teuwen
Jonas Teuwen
Sony Experia P?
 
Orange Harvester
Orange Harvester
Naah, I have HTC Desire Z.
 
Jonas Teuwen
Jonas Teuwen
It did an open the air update for 2.3 -> 4.0...
 
Pilot
Pilot
12:16 AM
I am beginner in Analysis and I am very confused in understanding the following: $\int_a^bfd\alpha=f(c_1)+5f(c_2)+12f(c_3)+1/2\int_c^df(x)dx$ so can we say from this that \alpha function has dicontinuitties at c_1,c_2 and c_3 with respective values 1,5,12
 
Jonas Teuwen
Jonas Teuwen
But for 4.0 -> 4.0.1 it needs...
 
Charlie
Charlie
@draks... does the bounty include saying your real name?
 
draks ...
draks ...
@Charlie let's see... provide an acceptable answer and we'll talk about it...
 
Charlie
Charlie
@draks... no talk, deal or no deal
 
draks ...
draks ...
@Charlie deal
 
Charlie
Charlie
12:18 AM
good ;) @draks
 
Orange Harvester
Orange Harvester
@JonasTeuwen I see.
 
Eric
Eric
if $1/k^{\log(k)} < 1/k^2$ for $k > 100$, this automatically implies that
$\sum_{k=1}^{\infty}1/k^{\log(k)} < \sum_{k=1}^{\infty}1/k^2$ Or only for $k=100$ to $\infty$
 
robjohn
robjohn
We're off to celebrate Valentine's Day early. Things are too busy later this week. BBL
 
draks ...
draks ...
@Charlie can you really do that?
 
Charlie
Charlie
@draks... I hardly think so
 
Orange Harvester
Orange Harvester
12:19 AM
@robjohn Have a good time.
 
robjohn
robjohn
@OrangeHarvester thanks
 
Charlie
Charlie
@draks... If I couldI would change my name to Bobba Fett
 
user19161
@robjohn Have fun! I will celebrate by myself, as usual...
 
draks ...
draks ...
@Charlie reminds me that I was wrong with the last Star Wars citation...
 
Jonas Teuwen
Jonas Teuwen
@OrangeHarvester Hmm... I just went in the store and hold it, thought... looks good! Do this. 1 minute. Seems to be nice anyway.
 
Orange Harvester
Orange Harvester
12:22 AM
@JonasTeuwen Yeah, Xperia P is a really cool design. Is it full metal?
 
Charlie
Charlie
@draks... haha :P
 
draks ...
draks ...
 
Jonas Teuwen
Jonas Teuwen
@OrangeHarvester Looks like it.
The back side, at least :P.
 
Charlie
Charlie
@draks... Great song!
 
user19161
Amazing huh? People upvote comments but not questions and answers, so STINGY.
 
Orange Harvester
Orange Harvester
12:23 AM
@JonasTeuwen Awesome. :-)
 
draks ...
draks ...
@Charlie you wanna samba?
 
Argon
Argon
Oh noes
 
Charlie
Charlie
@draks... no
 
draks ...
draks ...
@Argon another anti-carnevalist...Hi there btw...
 
Charlie
Charlie
@Argon ;)
 
Argon
Argon
12:29 AM
@draks... Hm?
 
draks ...
draks ...
@Argon I thought your "noes" are related to the song i posted...
 
Argon
Argon
@draks... No, It was related to the Samba :). I know @Charlie is not a big fan
 
draks ...
draks ...
@Argon big carneval fans should be rare here today...
@Argon Why "Argon"? Are you a rare g(ue)as(t)?
 
Argon
Argon
@draks... Nobility, pal
My name is Aaron, so I like "Argon" as a username
 
draks ...
draks ...
@Argon no chemistry background?
 
Argon
Argon
12:35 AM
@draks... Not much. I know some elementary stuff though.
 
draks ...
draks ...
if you could help here
2
Q: Construction of Hadamard Matrices of Order $n!$

draks ...I'm trying to get a hand on Hadamard matrices of order $n!$, with $n>3$. Payley's construction says that there is a Hadamard matrix for $q+1$, with $q$ being a prime power. Since $$ n!-1 \bmod 4 = 3 $$ construction 1 has to be chosen: If $q$ is congruent to $3 (\bmod 4)$ [and $Q$ is the c...

matrices
 
Charlie
Charlie
@Argon no...
 
draks ...
draks ...
I would be ever so glad...
ok people gotta go now. CU...
 
Jonas Teuwen
Jonas Teuwen
 
Charlie
Charlie
@draks... Bye!
 
Old John
Old John
12:44 AM
@JonasTeuwen bugger - that is sad news
 
Jonas Teuwen
Jonas Teuwen
Yes, interestingly - there is a graph that states how long it takes before a drug gets on the market.
 
Old John
Old John
@JonasTeuwen and I bet it is not very encouraging ...
 
Jonas Teuwen
Jonas Teuwen
It is a well-known thing.
 
Charlie
Charlie
@Argon it could be any Amir
 
Argon
Argon
@Charlie hahahaaha
"that is my house"
 
Charlie
Charlie
12:46 AM
@Argon hahahahahha
 
user43758
user43758
12:59 AM
Hello
Can somebody help me by any chance with this: math.stackexchange.com/questions/300748/…
I would really appreciate it
@Alex Hello
 
Alex Youcis
Alex Youcis
Hey
 
user19161
Good night bros, see you in your dreams.
 
Jonas Teuwen
Jonas Teuwen
See you.
Good night! I need a shave for I grow a beard.
 
user43758
user43758
1:16 AM
Can anyone help me with this: math.stackexchange.com/questions/300748/…
Please
Is anyone here?
 
user19161
1:44 AM
Oh man some of the hints are really too sketchy...
 
user19161
math.stackexchange.com/a/300790/4594 this should really be a comment.
 
user19161
Hey @people how are your classes?
 
Ethan
Ethan
any 1 here know about integer partions
 
Michael Corleone
Michael Corleone
Here I will use $\mathbf N=\{1,2,3,\ldots\}$. If $(f_n)_{n=1}^\infty$ is a sequence of functions from $\mathbf N\to \mathbf N$ and I define $g(n)=n\prod\limits_{i=1}^n f_i(n)$, then can I say that $\forall m\in\mathbf N$ $\lim\limits_{n\to\infty} \frac{g(n)}{f_m(n)}=\lim\limits_{n\to\infty} n\prod\limits_{i=1,i\neq m}^n f_i(n)=\infty$?
 
peoplepower
peoplepower
@JacobBlack Overly large.
 
user19161
1:48 AM
@peoplepower Must be calculus then LOL
 
peoplepower
peoplepower
@JacobBlack No I was just referring to the mathematical term class.
 
Riem
Riem
is there a way to display latex in this chat or must we all parse through the code like fluent experts?
 
Michael Corleone
Michael Corleone
see the link at the top right for latex in chat
 
user19161
@peoplepower Oh, I only understand silly jokes, not sophisticated ones.
 
Ethan
Ethan
$$\sum_{n=0}^\infty r_2(4n+1)x^{4n+1}=\sum_{n=0}^\infty\frac{4x^{4n+1}}{1-x^{16n+4}}-\sum_{n=0}^\infty\frac{4x^{12n+9}}{1-x^{16n+12}}$$
 
anorton
anorton
2:36 AM
@robjohn @robjohn I don't quite understand how you made the first step... how did you pull the $\arctan(e^{-x})$ out of the integral as $\frac{\pi}{4}$?
(referring back to that nice and hard integral)
 
user19161
Still awake...
 
user19161
3:01 AM
@argon Have you done your homework?
 
anon
anon
3:25 AM
@MichaelCorleone $g(n)/f_m(n)\ge n$, so yes
 
user19161
@CogitoErgoCogitoSum I saw your comment.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
Ive made many
 
user19161
Ha, well, it's hard to give an answer without giving more or less the full answer sometimes.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
The 10/40 problem?
 
user19161
Yes, but anyway I have edited it to give some work for the asker.
 
user19161
3:30 AM
See, some people don't like it when I give too incomplete an answer.
 
user19161
And some don't like it when I give too complete an answer.
 
user19161
It is very hard to please everyone.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
I dont know if that person was being sarcastic or what. When people ask a simple question and you give a simple answer... I dont know, I cant help but to criticize when people who expect more complain about not getting it when its totally unnecessary.
It just proves how gross their misconceptions are.
 
user19161
Well, a little bit of sarcasm is fine on this site. I am not talking about this case but in general.
 
user19161
Also, we must know that every thing that is said can be interpreted in 9000 ways.
 
user19161
3:33 AM
It's hard enough to understand people in real life.
 
user19161
It's even harder over the internet.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
You cannot please everyone. I dont even try. In fact, if anything, I go out of my way to be a critic to displease them. One of my favorite attributes of mathematics is that it is totally absolute. To hell with peoples feelings.
 
user19161
I have been downvoted for giving too few details and also too many details.
 
user19161
Also, sometimes we take the time to type an answer and post a few minutes after someone else.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
I was down voted on a question a while back... for not citing sources... totally absurd. If I found sources I wouldnt need to ask the question.
 
user19161
3:34 AM
Then they get upset as if we are plagiarising them.
 
Eric
Eric
Find all $p \geq 0$ such that the following series converges:
$$
\sum_{k=1}^{\infty} \frac{1}{k\log^p(k+1)}
$$
The solution is here http://imgur.com/2tWgQOa but I really don't understand this. I get the inequality and how the second series converges if $p>1$, but I don't see how this implies that the first series must converge for $p>1$.
 
user19161
I don't need to plagiarise anyone for something as simple as 1+1=2 to me.
 
user19161
@CogitoErgoCogitoSum Well, a few downvotes now and then I have gotten used to, though I still complain in this chat over them. =)
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
Math is math, it stands on its own. It doesnt matter if the Joe Theorem was discovered by Joe or not. If not Joe then inevitably someone else. Its all there already, built into the fabric of reality. No mathematician deserves credit and I dont cite sources. Ever. As long as your premises are theorems then I dont cite mathematicians or articles... because that is just an appeal to authority and is a fallacious basis to give merit to a paper or answer.
 
Eric
Eric
The way I see , this first series certainly converges from $p>1$, but how does the comparison ensure that perhaps the first series does not converge for $p > .99999987$ ?
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
3:37 AM
If people dont recognize the truth of a theorem then they are in no position to judge.
 
Eric
Eric
I fee that the comparison theorem puts a "bound" on $p$.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
I find that most people are just petty. They down vote their competitors to make themselves look more credible. I hated that with yahoo answers. Here, they actually dock you for down voting. I appreciate that. I think they should also inform people who gave the down vote
 
user19161
@CogitoErgoCogitoSum I also want to add that some of my downvotes are accidental.
 
user19161
It's not too hard to click wrongly on a moving screen.
 
user19161
But we can reverse them within 5 minutes.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
3:40 AM
downvotes can be undone though. I already noticed that. Just click it again.
 
user19161
After 5 minutes, we have to edit the post.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
Oh, there is a 5 minute limit?
 
user19161
Yes, there is.
 
user19161
But that comment on the question itself that you commented on, I don't know if he was joking @cog
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
It doesnt matter. I have actually asked someone explicitly if they were "joking". They asked for some elaborating details to a question. But it was totally absurd to ask. The question was sufficiently worded to answer. The commenter was throwing out the most off-the-wall alternative interpretations I could only assume they were either retarded, joking, or being malicious.
 
math101
math101
3:46 AM
Being malicious
Or just an act of superiority
 
user19161
@CogitoErgoCogitoSum I just wanna add that it is very easy to misunderstand people sometimes.
 
user19161
I try not to jump to conclusions too fast.
 
peoplepower
peoplepower
My downvotes tend to start chains of such, for I am not a bandwagon downvoter and I rarely downvote.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
I can be malicious too though. There are some things I just sooo hate. Calculus students who get confused about basic algebra is one of my biggest pet peeves, or similar such questions where the questioner is confused about the most simplistic and fundamental of prerequisites.
 
user19161
Yeah we all have our faults.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
3:49 AM
I feel as though 50/50 up and down voting is appropriate. You dont want to be a bandwagon anything. Doing either one a little too liberally and the other conservatively is a bias, I feel. I try to judge fairly.
 
user19161
The risk of giving too few details is that the asker may actually get the wrong answer in the end.
 
anon
anon
Given that one of my big pet peeves of question-askers is when they fail to provide context that would save potential answerers and commenters from wild goose chases, I am obligated to be suspicious of anyone negatively characterizing another for asking for details on a question.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
I dont mind explaining calculus to a calculus student, calculus to an algebra student, or even algebra to an algebra student. But I cannot bite my tongue when a calculus student needs help with algebra. What a crappy education system we have that such students are promoted to levels they are so painfully obviously ill-prepared for.
 
user19161
Also, the question is not just for the asker, it is for the world to read.
 
user19161
If we just give hints that are too skinny, the site looks stupid.
 
CogitoErgoCogitoSum
CogitoErgoCogitoSum
3:53 AM
Indeed. In the interest of being constructive, why should down votes be justified when up votes dont have to be? I dont like doing homework for people though. Hints are appropriate when the question is soliciting homework help.
 
math101
math101
@Ethan Hey
 
Ethan
Ethan
hi
 
math101
math101
How is ur studying coming along?
 
Ethan
Ethan
tired lol
 
math101
math101
I gave up on math. @JacobBlack agrees with me that math and I just dont get along
 
user19161
3:56 AM
@math101 Haha, let's leave our private conversations to email. =)
 
Ethan
Ethan
What are you doing now
I think, if you do anything long enough, you start to enjoy it
 
user19161
@Ethan Are you talking to me?
 
math101
math101
@Ethan Not sure abt that
 
user19161
@Ethan She is studying analysis now.
 
user19161
I am trying to give her some help sometimes, LOL.
 
Ethan
Ethan
3:59 AM
Didn't know it was a she
2
whats analysis?
Sounds like a broad term
 
math101
math101
Ya IT is a SHE
 
user19161
Analysis is the study of limiting processes.
 
user19161
For example, calculus in high school is part of analysis.
 
user19161
Differentiation and integration are really limits.
 
user19161
@Ethan Where do you think "analytic number theory" came from?
 
Ethan
Ethan
4:01 AM
analysis
lol
 
user19161
Though "analytic" can mean various things.
 
Ethan
Ethan
and number theory
 
user19161
It can mean just analysis, or it can mean in particular complex analysis.
 
Ethan
Ethan
Water towers, are towers of water
 
user19161
Elementary can mean easy or it can mean not using the methods of complex analysis.
 
user19161
4:03 AM
Real analysis and complex analysis are of course related, but they are also quite different.
 
Ethan
Ethan
Can you give me some fundamental results of each
Significant ones
 
user19161
Haha, I am only a mango. But I will try.
 
user19161
Haha, well for you, can I just give you the fundamental theorem of calculus for real analysis?
 
Ethan
Ethan
no
lol
 
user19161
Too trivial for you?
 
Ethan
Ethan
4:06 AM
;f
Somthing more general
@JacobBlack nvm that, its ok
 
user19161
Well, for complex analysis surely Cauchy's theorem is fundamental?
 
Ethan
Ethan
@JacobBlack Know any good books as an intro to enumerative combinatorics
A book that goes over standard techniques
etc
 
user19161
@Ethan Koh's Principles and techniques of combinatorics and Cameron's Combinatorics are my favourites.
 
Ethan
Ethan
Let me look it up
 
user19161
However, I am not sure what level books you want.
 
user19161
4:10 AM
I know you are good in number theory, but I think you really need to build up the basics.
 
Ethan
Ethan
I have no real background in discrete mathematics, no abstract algebra or stuff like that
 
user19161
I think there is a lot of basic material you don't really know.
 
Ethan
Ethan
ye I have looked at this one before, its to hard for me lol
 
user19161
@Ethan Which one?
 
math101
math101
I have a really simple book for discrete math
 
Ethan
Ethan
4:11 AM
The principles and techniques one, it assumes knowledge I don't have
 
user19161
@Ethan No, that is very simple. You can read it.
 
user19161
Cameron is harder.
 
math101
math101
Discrete math and its applications by Susan Epp
 
Ethan
Ethan
@JacobBlack I don't know any of that set theory notation
 
user19161
@Ethan You can ask here.
 
user19161
4:12 AM
Notation is just notation dude.
 
user19161
I can call a cat a dog and a dog a cat.
 
user19161
@Ethan You can just wait till you enter college to learn stuff though, no hurry.
 
Ethan
Ethan
ye I think I should start practicing for the sat, my ocd really slows me down lol
 
user19161
I never practised for my SAT.
 
Ethan
Ethan
The english part
 
user19161
4:15 AM
I still got 790/800 for math in the end.
 
Ethan
Ethan
I don't like tests
 
math101
math101
I dont like english
 
user19161
Yeah tests are stupid.
 
Ethan
Ethan
me neither
 
user19161
Stephen Smale got poor grades in undergrad and even grad school.
 
Ethan
Ethan
4:16 AM
whose stephen smale
 
user19161
A Fields medallist.
 
Ethan
Ethan
@anon when did you start studying mathematics?
 
user19161
As a baby LOL
 
anon
anon
it is difficult to draw a line between playing and studying
 
Ethan
Ethan
what do you mean by playing
 
anon
anon
4:19 AM
it wasn't until I was 13 when I learned calculus from my dad's old textbook, so I'll pin it down there
 
math101
math101
It wasn't till I was 18 when I learned Calculus
 
user19161
Looking at my life, I have not yet started studying math seriously...
 
user19161
My whole life is a mistake...
 
math101
math101
lol no it isnt
 
user19161
I hope I am strong enough to mend it...
 
anon
anon
4:25 AM
how many have you killed?
 
math101
math101
hahahahahha
 
user19161
I have killed a few thousand ants.
 
Ethan
Ethan
@anon how hard is it to show $$\lim_{s\to1}\frac{1}{\zeta(s)}\sum_{n=0}^\infty\frac{\ln(an+r)\mu(an+r)}{(an+r‌​)^s}=0$$
 
anon
anon
they had it coming
dunno
 
Ethan
Ethan
I know I can express the mobius sum in terms of combinations of $$\frac{L'(s,\chi)}{L(s,\chi)^2}$$
I don't know much about L functions tho
 
user19161
4:26 AM
Anyway @ethan I don't know any number theory, but you seem to be doing lots of limits and I think you really should study analysis first before analytic NT.
 
Ethan
Ethan
Im not really studying ant
Im just manipulating series\
 
user19161
OK, but if the series are infinite ones then limits are certainly involved.
 
user19161
For example one can't always change the order of two infinite summations.
 
Ethan
Ethan
ye I kind of work liberally with my series lol
 
math101
math101
Ok gotta begin studying
Bye guys
 
user19161
4:28 AM
An integral really is a limit of some kind.
 
Ethan
Ethan
4:47 AM
@Sanchez can you help me
 
 
1 hour later…
awllower
awllower
5:55 AM
What a strange notation:
http://math.stackexchange.com/questions/300940/solving-non-linear-congruence
 
Orange Harvester
Orange Harvester
6:13 AM
@awllower what is strange?
 
awllower
awllower
It has been modified, but it was some equation modulo 0.
I was wondering what it means by dividing by 0...
 
Orange Harvester
Orange Harvester
I see. I could not see it in the edits. Must have been done within 5 minutes.
 
awllower
awllower
Per chance.
I tried to be clear, but I worry that OP cannot understand, as he is new in number-theory.
 
Orange Harvester
Orange Harvester
Yes. I think your solution is clear though. You might want to put Chinese Remainder Theorem instead of CRT.
 
awllower
awllower
All right.
I edit so as to illustrate upon the theorem.
 
Orange Harvester
Orange Harvester
6:25 AM
That's good.
 
awllower
awllower
Haha, it turned out that I was wrong.
 
Orange Harvester
Orange Harvester
Eh?
Ohh you got the wrong answer.
 
awllower
awllower
I am finding where I went wrong.
 
Orange Harvester
Orange Harvester
@awllower your factorization went awry?
 
awllower
awllower
I got x+1 is congruent to 2, hence x to 1
I treated x+1 as x. Apology here...
 
Orange Harvester
Orange Harvester
6:29 AM
Yes.
 
awllower
awllower
Finally.
So embarassing an event.
 
Orange Harvester
Orange Harvester
Happens. Happens.
 
robjohn
robjohn
@anorton Note that $\frac12(\arctan(e^{-x})+\arctan(e^{x}))=\frac\pi4$.
 
awllower
awllower
6:52 AM
At least I learn to look more carefully, haha
 
Mariano Suárez-Alvarez
Mariano Suárez-Alvarez
 
Orange Harvester
Orange Harvester
7:11 AM
@MarianoSuárez-Alvarez c'mon that is hazing!
 
robjohn
robjohn
@MarianoSuárez-Alvarez we could start The Axiom Clearinghouse...
 
Abhijit Navale
Abhijit Navale
7:32 AM
hello guys
anyone awake?
i need help regarding one math puzzle
 
00:00 - 09:0009:00 - 17:0017:00 - 19:0019:00 - 22:0022:00 - 00:00

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