12:27 AM
So the closed unit ball in $\ell^2$ isn't precompact, but it has the weaker property that every uniformly continuous function into $\mathbb{R}$ is bounded
and I am wondering, how is this property called, if anything. A name I could make is weakly precompact
maybe weakly precompact is a bad nomenclature considering how precompact is used in the context of vector spaces
apparently people did study this for metric spaces
apparently this is equivalent to, for each $\varepsilon > 0$, we can decompose $X$ into finite amount of sets $X_1, ..., X_n$ such that for every $x, y\in X_i$ there exists $x_1 = x, x_2, ..., x_n = y$ with $d(x_i, x_{i+1})\leq \varepsilon$ and we can do so while keeping $n$ bounded
sorry, replace $x_n$ by $x_m$ and last $n$ by $m$
so it is pretty much like totally bounded, but that one has $m = 1$
whereas here we allow longer steps
and by bounded $m$ I just mean, lets say, $m = m(\varepsilon)$ is a fixed natural depending on $\varepsilon$
@AlessandroCodenotti @Thorgott look at this pretty cool weakening of totally bounded metric spaces I've found
might generalize this result to uniform spaces