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04:26
@Mr.Xcoder The choice to start at 1 seems rather arbitrary.
@Dennis um, maybe start at a given number? Anyways this way it would only save 1 byte but would be a nice addition
# should never have done what it does in the first place. All other quicks use # for one and Ð# for all...
What was # meant to do then?
At the moment, what it does now. It's either a very old quick and predates the convention, or I'm not very good at following my own conventions. Don't remember.
Something to fix for Jelly 2.
Oh you are developing Jelly 2? Or didn't really start yet? (I'd ask why, but I think you don't want to make backwards incompatible changes to Jelly)
04:37
I have a whole bunch of ideas, but no code yet.
I'm not even sure I'll keep the name. Depends on how different the next incarnation will be.
Aww it sounds great! Good luck implementing it!
No clue when that might be. Currently focusing on TIO.
 
6 hours later…
11:10
@Dennis Is that expected behavior?
 
2 hours later…
12:44
Can Jelly be viewed as an equation written in prefix notation with many, many operators? (or is it postfix?)
 
4 hours later…
16:26
@SocraticPhoenix Neither. It is tacit.
@Dennis Can ȷ2 be replaced by ³ for 100 in Jelly? Of course, I'd say my program works as a monadic link, and can act as a function would do in other languages, called using code, so that the input (third command line argument is empty). Do you think this would be allowed? For instance, I submitted the following code to one of my answers: 0;+\÷S×ȷ2ḞI. Can I just say it's a monadic link, not as a full program, and use 0;+\÷S׳ḞIinstead?
17:07
@Mr.Xcoder Sure that works.
Thanks!
@SocraticPhoenix While Jelly can behave like postfix and infix (never prefix) on occasions, it isn't really any of those. +×_ is an infixy example (for arguments x and y, it computes (x+y)×(x-y), +H a postfixy one (computes (x+y)/2).
 
2 hours later…
19:30
@Dennis would you mind explaining exactly what " does to a dyad? I don't think I understand what the docs mean by "Vectorize/zipwith."
19:45
@cairdcoinheringaahing If you apply d" to [x, z] and [y, w], you'll get [(x d y), (z d w)].
@Dennis Ah, that makes it clearer. Thanks!

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