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6:33 PM
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Q: Why do dihaloalkanes lose both halogen atoms during mass spectrometry?

chematworkI was looking through mass spectrums of haloalkanes and found the one for 1,2-dibromobutane confusing: The base peak is at 55 m/z, and the only fragment I can think of with that ration will be $\ce{C4H7+}$. The two bromine atoms must be absent as the relative molecular mass of one bromine atom i...

 
 
4 hours later…
10:36 PM
@M.A.R., have you seen Martin lately? I came here to point out that there's a "Want to improve this post" notice on the top of one answer here:
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A: Reaction of glucose with 2,4-dinitrophenylhydrazine (DNPH)

dadaThat is because the glucose react with 2,4-Dinitrophenyl hydrazine, when the correspoding imine is formed, immediately ring closed and form DNPH-glucose, the final product is closed six member ring form, the imine cannot detect. Due to the two strong electron withdrawing nitro groups on the arom...

But the other answer needs even more improvement! haha. I see I can @orthocresol and @FadedGiant though.
 

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