My teacher told us the middle carbon in 3‐bromopentane‐2,4‐diol is chiral: $$\ce{CH3-CH(OH)-\overset{\star}{C}H(Br)-CH(OH)-CH3}$$ Since there are two identical groups around it, I would guess it should not be chiral. It was a pre-recorded class and I was not able ask this question. Has my teacher...