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Q: Show that the ring of integers of $\mathbb{Q}(i)$ is in fact $\mathbb{Z}[i]$

john mangualWhat is the name for a situation where the obvious thing turns out to be true, but the reasoning is more complicated? In abstract algebra we can say the rational numbers - the fractions, $\mathbb{Q}$ form a field. Then we can adjoin the number $x = \sqrt{-1}$ which solves $x^2 + 1 = 0$, and w...

 
 
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6:25 PM
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Q: How to calculate damages for educational misconduct

Luca DanieliI have an issue with my university. After 3 years of PhD research, I have presented to my examiners a out-of-format interdisciplinary research, as agreed with my supervisor. Unfortunately, my supervisor said "yes, yes, no problem", but after that he has never looked at my submission (I guess he w...

 

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