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12:24 AM
D1 dupe of FAQ, nothing novel.
 
 
8 hours later…
 
9 hours later…
RRL
4:56 PM
Delete: DA, DB, DC, DD, DE, DF, DG, DH
Delete: DI, DJ, DK, DL, DN, DM, DO, DP
 
 
2 hours later…
6:58 PM
D1, D2, D3.
D4, D5, D6.
D7, D8, D9.
 
That's not my area of expertise, but I wonder if this coin problem has been asked (and answered) before. I only found this similar question but it seems to me that the solution for the coins (3, 7, 9) cannot be applied to (5, 7, 11).
 
7:36 PM
@MartinR I have referred askers to this answer by Robjohn whenever the question involves two coins (of coprime values). Its answer gives a useful bound for three coin problems whenever two of them are coprime, and we can apply brute force to check the finitely many missing sums below the guaranteed bound.
I dont't know if there is a comprehensive of theory for the case of three coins. The techniques become more diverse when there are more coins, and there is scope for trickery.
 
7:54 PM
FWIW I did (6,7,15) as a part of this answer.
 

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