in Mathematics, 1 hour ago, by
user193319 Is $f_n : [0,1] \to \Bbb{R}$ defined by $f_n = n 1_{[0,1]}$ a cauchy sequence with respect to the $L^1$ norm? If my calculations are right, it seems to reduce to determining whether $\epsilon > 0$, there is $N \in \Bbb{N}$ s.t. if $s \in \Bbb{N}$ and $n \ge N$, then $\frac{2s}{n+s} < \epsilon$...But I'm having trouble showing that this is true...
