1
This is a partial answer, now with added material.
Assume that $n$ is a multiple of 3, the other two cases should be similar. I'll denote $C_1\mapsto a$ and $C_2\mapsto b$, such that for, e.g., $n=6$,
$$\tag{1}\label{1}
A = \begin{pmatrix}
a_1 & 1 & 0 & 0 & 0 & 0 \\
a_2 & 0 & 1 & 0 & 0 & 0 \\
a_3 &...