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BAYMAX
10:05
@MartinSleziak hey!
BAYMAX
10:37
@MartinSleziak it shows err for thislink "Found using Approach0"
Martin Sleziak
10:59
For 4 see also radius of convergence of the power series $\sum_{n=0}^{\infty} z^{n!}$. Found
using Approach0
. —
Martin Sleziak
39 mins ago
For 1 see also
Complex exponential series convergence $\sum_{n=0}^{\infty} \frac{z^n}{n!}$
and
Determine Radius of Convergence of $\sum_{k=0}^\infty\frac{z^{k^m}}{k!}$
. —
Martin Sleziak
38 mins ago
BAYMAX
ok
Martin Sleziak
It seems to be working for me. Although I have forgotten to add link to the post:
radius of convergence of the power series $\sum_{n=0}^{\infty} z^{n!}$
Anyway, both comment are obsolete after your edit.
BAYMAX
also a -1 is obsolete i think! he he
Martin Sleziak
So I have deleted them - they are copied here in chat anyway in case you need them.
@BAYMAX Well, that's mainly the question for the user who downvoted the post.
BAYMAX
ok sorry
Martin Sleziak
11:03
@BAYMAX If you simply tried to enter this series
into Approach0
you would have found:
Radius of convergence of $\sum_{n=0}^\infty 4^{{(-1)}^n n} z^{2n}$
BAYMAX
ok
so since we need to take limsup what will be radiuso f convergence ?
BAYMAX
11:51
ok got it !
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