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Math Guy
Math Guy
12:09
@SineoftheTime Did you mean that the antiderivative of $|\psi(x)|$ must be bounded?
Sine of the Time
Sine of the Time
@MathGuy the integrals are definite integrals but I've omitted the bounds for brevity
you're integrating over and interval $I$
Math Guy
Math Guy
@SineoftheTime So the integral of $|\psi(x)|$ over any interval must be finite?
Sine of the Time
Sine of the Time
no
Math Guy
Math Guy
@SineoftheTime then what is the interval $I$?
Sine of the Time
Sine of the Time
you're interested in $\lim_t \int_I$
In your case you're integrating over $[0,+\infty[$
Math Guy
Math Guy
12:21
@SineoftheTime @SineoftheTime Ok thanks, got it.
Sine of the Time
Sine of the Time
np

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