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14:59
No, I don't want to replace infinity with -1/12. The sum 1+2+3... equaling -1/12 satisfies many mathematical rules such as linearity and stability.

To simplify, we have v=c, so M = m0 / √(1 - v^2/c^2) ~ m0c / √(c + v)√(c - v) ~ m0c / √(c + c) √(c - v) ~ m0√c / √2√(c - v) = A/√(c - v) with A = m0√c/√2.

It is therefore enough to find a divergent series M0+M1+M2+... which represents this quantity A/√(c - v) when c=v, and this series must also respect linearity, stability and other properties like that of Ramanujan, and it will be equal to M0+M1+M2+... = A/√(c - v) = m0, not -1/12.
 
1 hour later…
16:05
"M = m0 / √(1 - v^2/c^2) ~ m0 / √(c^2 - v^2)/c^2 ~ m0 / √(c + v)√(c - v)/c^2 ~ m0c / √(c + v)√(c - v) Here, since the issue lies in c-v and not in c+v, I can simplify the limiting expression by setting c=v in c+v. Therefore, I have m0c / √(c + c)√(c - v) ~ m0c / √(c + c)√(c - v) ~ m0c / √2c√(c - v) ~ m0√c / √2√(c - v) = A/√(c - v) with A = m0√c/√2."

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