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A: Let $f(x)$ be a polynomial satisfying $\lim_{x\to \infty} \frac {x^4 f(x)}{x^8+1} =3$, $f(2)=5$, $f(3)=10$,$f(-1)=2$,$f(-6)=37$. Find $f(0)$

BuraianAssume: $$ f(x) = \sum_{i=0}^k a_i x^k$$ From the three linear system in the question, we can write: $$ \begin{bmatrix} 5 \\ 10 \\ 2 \\ 37 \end{bmatrix} = \begin{bmatrix} \alpha_0 & \alpha_1 2^1 & \alpha_2 2^2 & \alpha_3 2^3 &\alpha_4 2^4 \\ \alpha_0 & \alpha_1 3^1 & \alpha_2 3^2 & \alpha_3 3^3 &

incredible
truly incredible
 

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