12:02 AM
bobble is okay?
tailhugs

1:00 AM
@Deusovi I think I may be in need of some assistance with math
If you're free?

1:16 AM
i'm around now, what's going on

Ah, actually, I have to go practice the trumpet :/
But it does have to do with partial fractions

alright then, ping me whenever you're working on math then?

Okay, thank you :)

2:09 AM
@Sciborg the gist of it is I have a problem where if I make a mistake, and I know that other people will see/know that I have made a mistake, no matter what the mistake is, I become worried that everyone will think I'm stupid and look down on me
This is obviously illogical, but it's based on some very real events where I was a little know-it-all that some other kids resented, so they would make fun of me if I made even the smallest mistake
Ideally the people on The Internet would be more mature than a group of 2nd graders, but then, it's The Internet

2:22 AM
Okay @Deusovi I'm back

hey!

Hey :)

(fwiw, bobble - i know that feeling very well. i'm not sure the best way of getting over it, but hopefully it helps to know that you're not alone there)

oooh, I love these kinds of problems

I'm not sure how to solve this -_-;
Not even sure where to begin for number one

2:24 AM
try clearing out the fractions first

Hm okay

fractions nasty
no fractions good

x+7=a(x-2)+b(x+5)?

hmm, looks better

Okay, now what?
We still have three variables -_-

2:26 AM
x isn't a variable
well, it is

This looks oddly familiar from last year

but it's not something you're solving for - it doesn't have a specific value, you want it to work for all values

this is one of those cases where you have to remember, this is true for all values of x
jink :)

ah right

oh wow only a single jink. i'm used to getting multiple at once

2:27 AM
Where you had like a, b, and c and you would like swap stuff out I don't remember

hijinks?

Wasn't it something like ax^2+bx+c andthen you solve for those individual coefficients?

i'm not quite sure what you're referring to, but that sounds along the right lines

Anyhow, still not sure what to do next. Should I distribute?

sure, why not

2:28 AM
@Deusovi Well, it's been over a year, so I probably have some stuff mixed up

Dec 13 '20 at 19:51, by bobble
these equations must be true for any value of x
found one case where we discussed this

x+7=Ax-2a+Bx+5B

looks good
the technique here is an interesting one - you shouldn't really look at x as a variable. instead it's more like... a "carrier" for coefficients that you want to be equal

Hm, okay
So like
x=Ax-Bx?

yep!

2:31 AM
and 7=-2A+5B?

also yep!

Ah, yes, this looks somewhat familiar

because both sides are linear equations of x, and every line only has one set of coefficients that can represent it

I forgot what to do from here
@Deusovi Ah, I see

(so this would also work for, say, both sides being quadratics, or cubics, or whatever)
@PrinceNorthLæraðr there should be an 'obvious' thing to do to the first equation
then look at the two equations you have

2:33 AM
Well, I guess you can divide out the x in Ax-Bx?
1=A-B?

looks good to me

Hm, 1=A-B, 7=-2A+5B
Oh it's SOE now

indeed it is!

SOE = So Easy :P

:P
A=1+B, 7=-2(1+B)+5B

2:34 AM
systems of linear equations can be a pain but they're very mechanical

B=3?
Yee
And A=-2

hooray!

Wait... my answers don't match up with the key

un-hooray!
2
yeah that's not quite right, i don't think those values work

(FYI, I couldn't be in math class today because I had a band thingy, which is why I'm needing extra help :P)
Let me re do this again

2:37 AM
yeah it's not b=3, but i think it's correct up to there

Hm, not sure what I'm doing wrong
7=-2(1+B)+5B
7=-2-2B+5B
7=-2+3B; B=3...?

The answer says it's 9/7 which is close to what I did

@PrinceNorthLæraðr ah here's the problem
that should be a +, not a -

Oh, duh
There we go
B=9/7
A=-2/7

2:45 AM
hooray (for real this time)!

re-hooray! :P

3:02 AM
@Deusovi A reference to the grid deduction room :P
@PrinceNorthLæraðr And another reference

...no? just a joke

It happened in that room before
Wait, let me find it

no need, i'm sure it did

Did you really have to ping me for that?

Happy un-birthday y'all!

3:05 AM
Hehe
Hm, I'm getting some funky values for my next problem
44 mins ago, by Prince North Læraðr
Oh, am I not supposed to write (Ax+B)/((x^2)+x) as Ax/((x^2)+x)+B/((x^2)+x)?

it's over x²+2, not x²+x
(and you can write it that way but it's easier not to)

@PrinceNorthLæraðr Does this jog your memory?

@Deusovi Hm, okay

After 14 minutes, I found it

Un-un-hooray!
(BTW it's a lot easier to just use the search bar to find exactly what you want instead of what I presume you did, which is literally go through the transcript day by day until you came across the right message)

3:38 AM
@PrinceNorthLæraðr It's been a while now, any updates or progress?

Nope
I gave up and now I'm playing chess -_-;

Welp
Let us know when you're in the mood for more math then

And I'm losing all my games after I mentally lost it when my mouse slipped

Ouch, not fun
Have this chess-themed HNQCC to relieve the stress:

ha!
that's cute

3:42 AM
Why are none of my links formatting properly?
Oh well, lemme just post the actual question

you switched brackets

@Deusovi Ugh, I keep messing that up still

the mnemonic i've heard is that you'd normally put the URL in parentheses, not brackets, and that stays the same

But what if I'm a rebel and always put all my URLs in square brackets?

Then [text] is always in square brackets, including in the [text][1] syntax

3:49 AM
Now the transcript will make it seem like I telepathically beamed the CC into Deus's mind

1 hour later…
4:55 AM
To friends: tomorrow, I have constant tests for a large part my schoolday. I'll also be doing some studying for these tests in the morning. Therefore, expect me to disappear around 7:30-ish and not reappear until much, much later. :/

10 hours later…
2:33 PM
:/