Resonance's Chemistry Gyan Sutra Basically all formulas of chemistry chapter wise.

This might be helpful.

@Wolgwang tnx mate

i spent 30 min looking for this yesterday

tnx again

@Arjun Teri kitni chem hui hai

NVM

@LalitTolani less than yours for sure

@RajdeepSindhu bhai sahi me cobid ho gya kaya

@Arjun No idea bhoiya, jan-ne ka iraada nahi hai 🙃

@RajdeepSindhu heater use karte ho bhaiya?

@RajdeepSindhu i don't use razai at all💀

@Arjun I use two, founding myself buried inside them every morning

@LalitTolani my advice: run

@Arjun i get tired with a walk of 7-8 mins over 400-500m

@LalitTolani bhai

kya baat kr re ho

drive.google.com/drive/folders/…

ye lo

mafs

@Arjun I can't leave home without my father's two wheeler even for buying milk 150 m away

pura h

@Arjun tanks

@LalitTolani 💀💀💀💀💀💀💀💀💀

i have walked home 7-8 km from school with a 6kg bag

and it seemed normal😂

yaar

nvm

@Arjun @LalitTolani @YashAgrawal

shouldn't the answer to this be mg/4k?

which is nowhere in the options but everywhere on internet

@RajdeepSindhu take care!

@Wolgwang thanks a ton! i didn't know such books also exist🙃

@hansika trusted source?

mera dimak kharab hua pada h

par match kar raha h jo given h us se

@Arjun trusted toh nai hai

when i attempted for the first time mera bhi match ho raha tha

but baad m realise kiya jo geff=g/2 aaya hai vo pendulum ke liye hai..not for box

eak line ka h

@hansika g/4 nahi hua?

@Arjun root mein hai toh 4 bahar aake 2

dikkat kahan aai

kahi nai..bass final ans match ni kr raha😂

$\frac{-kv}{M}+ g=\frac{g}4$

how?..may i tell what i did?

@hansika ji

@LalitTolani bhai aaplog better explain karte ho

what i said was wrong..toh geff g/4 hi ho jaayega and box is moving down with acc say a, toh pendulum pe upar pseudo acc a, eff honi chahiye g/4 toh g-a=g/4 isse a aaya 3g/4

box pe neeche force Mg upar kv aur net acc 3g/4 toh Mg-kv=3Mg/4

@hansika box par neeche force Mg kaise

@hansika this

box pe tension nahi lagegi kya , bob ko kisi rassi se hi bandha hoga

the situation is much complicated than it seems

ye jo eqn main lagayi..techinically toh system pe lagayi..kyuki mass maine maana M

Ok so $$F_{\text{net( on system)}}=Mg-kv=m_1\vec{a_1}+m_2\vec{a_2}$$

Now a_1 and a_2 kaise likha

they both are moving together with same acceleration a toh pendulum ki bhi net acceleration is downwards which is equal to a which should be equal to g/4

sahi boli?

I think i am overthinking , I would advice you and me to wait for john sir he will explain better than anyone

okay, i'll ask in PSS

during what time sir is available?

@hansika from 11 to 6

okay!

@hansika I think the question is seemingly assuming too many assumptions , as first of all if pendulum swings , due to the tension on the block , block even can't fall vertically and after that talking about oscillations of pendulum makes no sense ig ,So assuming very small oscillations becomes necessity more than for mathematical reasons , and after that acceleration of center of mass is (g-kv/M) , so it should've been of the block

So pseudo force on pendulum (say its mass being m) wrt block's frame is m(g-kv/M) on upward direction and then after finding torque and then finding time period gives me mg/4k as the answer , same as you

@YashAgrawal matlab mai sahi bol raha tha?

@LalitTolani very small oscillations ke liye toh complicated nhi h fir itna (** agar mg/4k shi h toh) , aur assumptions na manne toh oscillations hi nhi honge :)

@YashAgrawal haan very small ke liye jyada nahi hoga

@hansika @YashAgrawal Stability of halide ions ka order?

Yeh wala question

I->Cl->Br->F-

@hansika what about electron gain enthalpy factor

Down the group, the size factor is considered and within a period the EN factor (generally)

this is what I learnt, now I never cared to know why as long as I was able to solve questions🙃

@hansika I learnt same in O chem

@hansika Bas appne nahi care kiye to ham bhi nahi kar rahe

XD

@YashAgrawal this was asked in mains ka mock test toh i don't think it should be that complicated..thanks!

@LalitTolani free for a question?

Yes

@hansika can u see mathjax

yess

The net force on particle will be towards the center of tunnel given by $$\frac{GMmr}{2R^3}\sqrt{4r^2-r^2}$$

yes??

The force by earth will be towards the center of earth, taking it's components along the tunnel and perpendicular to tunnel , the perpendicular component will be will be cancelled by some normal force and therefore horizontal component will cause the motion as given by above equation.

ohhhh

got itttt

:-)

thank youu :)