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Q: How to transform the two-dimensional Berry curvature integral into a loop integral along Fermi circle?

JackThe Hall conductivity is given by $$\sigma_{xy}^{2D}=\frac{e^2}{\hbar} \int \frac{d\vec{k}}{(2\pi)^d} f(\epsilon(\vec{k}))\Omega_{k_xk_y} \tag{1} $$ in which $f$ is the Fermi distribution function and $\Omega$ the Berry curvature. If we write the Berry curvature in terms of the Berry vector poten...

 

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