
I want to show that
\begin{align*}
(x^2\delta^{(3)},\phi) = -6(\delta^\prime,\phi)
\end{align*}
Where $\phi$ is a test function. I'm not quite sure how to go about it. My attempt was defining $f(x) = x^2\delta(x)$. I get that
\begin{align*}
(f^{(3)},\phi) = 6(\delta',\phi)+6(x\delta'',\phi)+(x^2\...