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7:21 AM
There are nine questions tagged as .
7
Q: Nonstandard models of PA of large cardinal size

JasonIt is easy to overlook the fact that the existence of a given large cardinal provides us with a true arithmetical statement that would otherwise be false if the large cardinal notion were not consistent with ZFC (See On statements independent of ZFC + V=L ). The arithmetical statement that I'm r...

12
Q: Is there a nonstandard model of arithmetic having precisely one inductive truth predicate?

Joel David Hamkins$\newcommand\Tr{\text{Tr}}$My question is whether there can be a nonstandard model of PA having a unique inductive truth predicate. Background. If $\mathcal{N}=\langle N,+,\cdot,0,1,<\rangle$ is a model of the first-order PA axioms, then a truth predicate on $\mathcal{N}$, also commonly called ...

7
Q: On a theorem of Zhang Jinwen about models of arithmetic

Mohammad GolshaniIn the paper ''A Nonstandard Model of Arithmetic Constructed by means of Forcing Method'', Zhang Jinwen states the following in his abstract: The first nonstandard model of arithmetic was given by Skolem. A. Robinson has introduced the concepts of standard, internal and external objects (sets...

21
Q: What is the spectrum of possible cofinality types for cuts in an ordered field? Or in a model of the hyperreals? Or in a nonstandard model of arithmetic?

Joel David HamkinsI am interested to know the full range of possibilities for the cofinality type of cuts in an ordered field and in other structures, such as nonstandard models of arithmetic. Definitions. Specifically, in any linear order $\langle L,\leq\rangle$, a cut is a partition $L=A\sqcup B$, such that ev...

7
Q: Finding a PA cut in a nonstandard model of PA

Joel David HamkinsFor a certain project I am currently working on, I need to be able to find PA cuts in nonstandard models of PA, in desirable intervals. For example, I wonder if the following is true, where $\newcommand\PA{\text{PA}}\PA_k$ refers to the theory with only $\Sigma_k$ induction. Question. If $M$ is...

9
Q: Uncountable nonstandard models of PA

JasonStandard techniques (no pun intended) can be used to show that countable nonstandard models of Peano Arithmetic are order isomorphic to $\mathbb{N} + \mathbb{Z} \cdot \mathbb{Q}$. Once we have used the compactness theorem to verify that nonstandard models of PA exist, we can appeal to the Löwenh...

8
Q: Models of arithmetic in a signature with exponentiation but not addition and multiplication

Beau Madison MountLet $\mathcal{L}_{\mathrm{exp}}$ be the language with signature $(0, ^\prime, <, \mathrm{exp})$ (with $0$ interpreted as zero, $^\prime$ as successor, and $\mathrm{exp}(x)$ as $2^x$) and let $\mathsf{TA}_{\mathrm{exp}}$ be true arithmetic in this signature; i.e. $\{ \phi \in \mathsf{Sent}(\mathca...

4
Q: When can two elementary end extensions of models of PA be uniquely amalgamated?

Athar Abdul-Quader$\DeclareMathOperator{Cod}{Cod}$ $\DeclareMathOperator{Scl}{Scl}$ $\DeclareMathOperator{Def}{Def}$ $\DeclareMathOperator{Lt}{Lt}$ Background: All of the background to this question can be found in Kossak-Schmerl, The Structure of Models of Peano Arithmetic (2006) (referred hereafter as [KS]), s...

2
Q: Definability in countable nonstandard models of Peano arithmetic

Marcus DubiousI know that every element of $\mathbb{N}$ is definable the standard model of Peano Arithmetic. Does there exist a countable non-standard model of PA where the same is true?

As mentioned above is now a synonym of . Of the 213 questions, three have the new tag, while 210 have the old one.
14
Q: Which recursively-defined predicates can be expressed in Presburger Arithmetic?

Dan BrumleveIn Presburger Arithmetic there is no predicate that can express divisibility, else Presburger Arithmetic would be as expressive as Peano Arithmetic. Divisibility can be defined recursively, for example $D(a,c) \equiv \exists b \: M(a,b,c)$, $M(a,b,c) \equiv M(a-1,b,c-b)$, $M(1,b,c) \equiv (b=c)$...

16
Q: Is (Z,+,0,1,P2,P3) decidable?

ikpIs Presburger arithmetic, augmented with two unary predicates P2, P3, for powers of 2 and powers of 3 respectively, decidable? I know that adding just one of P2, P3 to Presburger keeps it decidable, and I'm asking about both. If I understood correctly the table in the end of http://www.logique....

2
Q: Set theories that are complete modulo finite-order arithmetic

BenIn a previous question, I asked whether there can be effectively axiomatizable set theories (at least as strong as, say, ZF) that are complete modulo first-order arithmetic, to which the answer is no; there will be sentences of second-order arithmetic that can't be proved even using the omega-rul...

I was a bit curious whether the synonym influences the results of these queries. (But my guess iss that it's not very likely - SEDE should still find posts with .)
Maybe the important things is that this query looks at the "Text" in the Posthistory table and it doesn't use the tags table (which contains a field called name). The query is written in this way on purpose - since I want to find also instance of tags which have been deleted, AFAIK such tags are not in the Tags table.
 

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