Aug 13, 2020 04:23
@sai-kartik Hi! I hope you would be able to take from here:
After this, an iodide ion attacks the tertiary carbocation. Then with the second equivalent of hydrogen iodide, a Markovnikov addition takes place giving the product I got.
I think, now I found a method to arrive at the book's answer even after rearrangements:
So, the product I arrived at first might be incorrect. Even after two rearrangements (as given above), we get the same product without any rearrangement (as done in the book).