Conversation started Nov 19, 2015 at 2:59.
Nov 19, 2015 02:59
Thanks @TedShifrin I had made some really weird mistake. it's actually trivial because it's =0 as you mentioned and the point is in the domain. (I stand by the $0<|h|<\delta$ bit, because the quotient isn't defined for $t=0$)
our professor will use apostol for analysis next semester
so that is is good
I want to continue studying it by myself during the summer
Oh, I thought you were in the valley, @Julian. I will be dropping folks at LAX on Sunday, 11/29, and then heading home. So that's not far from you.
Yes, @Alec, that's correct. But when you get to the end of the proof, you merely observe there's no problem when $h=0$.
Yeah there isn't. Because it's in the domain
@Ted Also, I literally just noticed that I will be multi next year because I will be taking the AP BC exam this year so should I learn ahead or maybe learn some complex analysis?
what is that !?
Nov 19, 2015 03:01
I wish there was a way to re-wind time so that I could stop myself from typing things like "$x/x$ is differentiable but not continuous at $0$"
@JulianRachman your a high school student?
@Ted Oh! That is actually pretty great. Should we meet?
@L33ter Yes I am.
@Julian: I still want you to learn single variable rigorously and then multivariable rigorously, as opposed to the engineering course, but still learning computations.
cool I took calculus BC exam when I was in high-school wasn't bad
I got 5 in it and calculus based physics
We can figure something out, @Julian, or wait for my next trip.
Nov 19, 2015 03:03
but I got 4 in chem
The Calculus BC exam is a total travesty.
@Ted engineering course?
They give 5s basically for anything from 60% to 100%. Totally uninformative, but everyone skips everything with that.
no @TedShifrin when I went to uni I actually took calculus to raise my average
Ok. Lets try for next time since it is a holiday coming up and I am quite busy @Ted
Nov 19, 2015 03:03
A typical multivariable course is computational/rote, @Julian, and often doesn't stress the interesting geometric ideas going on.
and ended up getting 99 in it
OK, @Julian. I'll be back up in the winter/spring, I'm sure.
anyway back to studying
need to do algebra assignment
Okay last one, and I hope this isn't daft. What do we actually define limits on? When I encountered them the "space" on $\mathbb{R}$ was never mentioned. It can't be just a metric space because limits in discrete metric would make no sense.
Nov 19, 2015 03:05
@L33ter I am only a sophomore in HS and so getting ahead will let me take any course I want
and do you remember anything from the test?
I guess that a limit means $0<|x-a|<\delta$ and stuff actually means metric induced by a norm, right? Norms I can believe.
I am going to be so nervous
You can define limits in any first countable topological space, @Alec.
do you think if I have canadian passport with my name people at airport will give me attitude when I go to US @TedShifrin
I don't know, Karim. I have very little belief in my country these days.
Nov 19, 2015 03:07
we will see its not like I hold any religious beliefs anyway I thought it would be nice to escape the cold for sometime
@Alec: There are more general notions of convergence, too, with nets.
I know like people tend to generalize
well, Karim, I don't think I'm volunteering to drive up to LA (for the third time in a month), but keep me posted.
alright I definitely want to come and visit you !
@TedShifrin I'm not "convinced" at the first countable bit. I would totally believe that for any NORMED space you could define limits and differentiability. A metric lacks...the scalar part (discrete metric for example) (how can I find out without pestering you?)
Nov 19, 2015 03:08
I didn't say a word about differentiability. Then you want a Banach (or at least Frechet) space.
But you don't need a metric to talk about convergence of sequences, nets, etc.
Look at standard books, like Munkres or Dieudonné's Treatise on Analysis.
@TedShifrin I wouldn't say that limits where you have the discrete metric say make any sense. But in my mind if you have a (complete, as you said) normed space, I can totally believe you get limits (derivatives and limits of functions, you know the classic real analysis)
When you have the discrete metric, only a constant sequence converges.
I don't know what'd break exactly but I cannot see "today we'll use the discrete metric for everything" leading to anything interesting as we know it.
It's not very interesting.
Yeah
Which Munkres book BTW?
Nov 19, 2015 03:13
Just Topology.
@TedShifrin if you consider the directional derivative for a moment, it matters not if you use $\Vert\cdot\Vert_\infty$ or $\Vert\cdot\Vert$ in the denominator, because these are equivalent norms, unless every first countable topological space is norm-able(?) (if it's metricisable, this isn't that big of a jump)
 
Conversation ended Nov 19, 2015 at 3:16.