let $v_1 = (x,0,0) - (0,y,0) = (x,-y,0)$ and $v_2 = (0, - y, z)$. I now have two direction vectors. Take the cross product, get a normal, call it $A$. Then eqn of plane will be $A \cdot \mathbf{(x - x_0)}$. where $x_0 = (1,2,3)$. Now this would be my constraint.