Conversation started Aug 5, 2014 at 18:23.
pourjour
pourjour
Aug 5, 2014 18:23
Supposing that $P=QD + R$ and $deg(S) \le n$ and $deg(D) = n+1$ and $deg(P) \le m$
what is the degree of Q?
Jasper Loy
Jasper Loy
@DanielFischer I have returned!
blue
blue
@pourjour by S do you mean R?
pourjour
pourjour
@blue yes ,
I was clumsy to put S instead of R
Daniel Fischer
Daniel Fischer
@900sit-upsaday You should totally upvote one post on main. Then everybody would go insane trying to guess which post was so awesome :D
anorton
anorton
@900sit-upsaday I, for one, am starting to downvote more. I'm also using my $5$ delete votes (and I'm using my closevotes strategically). A visit to Uber-meta (no umlaut on my keyboard, and I don't feel like internationalizing my layout) in addition to what 900 has said knocked some sense into me.
Daniel Fischer
Daniel Fischer
Aug 5, 2014 18:29
@JasperLoy Heya, @Jasper. Welcome back. I hope you'll keep your account a bit longer this time than last time.
Mike Miller
Mike Miller
@anorton What do you mean by ubermeta?
anorton
anorton
@DanielFischer Ditto! (Me! Me! Pick me! :P)
@MikeMiller Meta.SE. (900 calls it ubermeta)
Mike Miller
Mike Miller
Meta.SE, rather than metamath.SE?
Ah
anorton
anorton
Interesting: meta.stackexchange.com/questions/135073/…
pourjour
pourjour
@blue I don't need exactly a precise value,but I'm sure that $deg(Q)\le m-n-1$
but I don't a way to find out this result
Jasper Loy
Jasper Loy
Aug 5, 2014 18:31
@DanielFischer I hope so too. I will try not to delete my account anymore.
anorton
anorton
@DanielFischer As in this comment here... meta.stackexchange.com/questions/220558/…
blue
blue
@pourjour deg(P)=deg(QD+R)=deg(QD)=deg(Q)+deg(D), so deg(Q)=deg(P)-deg(D) which is less than or equal to m-(n+1), since deg(P) is less than or equal to m and deg(D)=n+1
Daniel Fischer
Daniel Fischer
@anorton Yes, I saw people wonder a lot what he may have upvoted.
 
Conversation ended Aug 5, 2014 at 18:34.