The Periodic Table

12:04 AM

@Benzene o/

@Mithoron Am I wrong?

I am pretty sure that spherical aromaticity is a thing

Q: Relation between strength and proticity of an acid

@Benzene Well, I also didn't get OP intention at first

-1

The strength of an acid is related to the number of molecules which have dissociated into hydronium ions in aq solution of that acid while proticity is the number of hydronium ions furnished by 1 molecule of that acid in water. But what is the relation between the two. Does a strong acid have a h...

acid-base

oh, yeah, I wasn't sure what he was asking

@Benzene spherical is a conception, but how valid is debatable

any idea what he wants to know?

So we don't know if spherical aromaticity actually exists?

12:09 AM

@Benzene If strong acids loose many protons :D

lol

@Benzene I was hoping it gets closed quickly enough, but it's night etc.

the acid question?

Yeah :D

I can flag it, but I assume that does not help. I don't have the ability to close vote yet.

12:15 AM

I flagged it quickly, but flag is still pending

g2g eat dinner. Bye

flagged as too broad but maybe homework may be more appropriate

@Benzene Your question doesn't look bad ;)

@Benzene bye

1:04 AM

Thanks

12 hours later…

user116211

1:22 PM

Hey @mith o/

@MAFIA36790 o/

Not much happening here lately

user116211

@Mithoron Yeh as usual without @TIPS and @Mart

user116211

Damn, the later can't be even pinged ;/

user116211

1:40 PM

Heyo @Brian.

Hiya

user116211

Well, I've nothing to do other than welcoming two or three people here; it's so lonely ;_;

@MAFIA36790 It's a different vertical reflection plane from the first $\sigma_v$

<nod>, impressively dead.

Summer break?

user116211

@Brian Ah! Well, I didn't get such notation anywhere ;/

I've had a hard time finding a readable resource.

user116211

1:43 PM

I finally got somewhere reading a combination of three books:

Bishop's Group Theory and Chemistry

user116211

Dover books are quite cheap.

Harris & Bertolucci's Symmetry and Spectroscopy

And the classic Wilson, Decius & Cross: Molecular Vibrations

I would start with Harris & Bertolucci

and follow with Wilson

And yes, Dover books are awesome.

Harris & Bertolucci laid out the symmetry operations and point groups in a way that I finally got my mind around.

Wilson, Decius & Cross's description got me to the point of (mostly) being able to remember what operations belong in what point groups

And Bishop is a really nitty-gritty exposition of the group theory math and manipulations .

Still in the middle of Bishop, actually.

user116211

@Brian My last buy on Dover Fermi's Thermodynamics; it is damn excellent lucid. Just $4

user116211

Thanks for the recommendations, @Brian

user116211

1:53 PM

For @Brian, !!beer

Chemobot

1 hour later…

3:11 PM

o/ @Benzene

1 hour later…

4:33 PM

@Mithoron hi

@Benzene hello

Beware mod is here ;) @DavidZ o/

2 hours later…

7:03 PM

Cr(OH)3 + H2O2 + KOH

Good evening all!

I wonder how I can guess what the products will be in this reaction

Q: Chromium (III) hydroxide + alkali hydroxide + hydrogen peroxide

7:14 PM

$$\ce{2Cr(OH)3 + 4NaOH + 3H2O2 -> 2Na2CrO4 + 8H2O}$$ How does this reaction occur? We suddenly get sodium chromate in the place of sodium hydroxide. I can't understand it. What role does the peroxide play?

reaction

Because I just stare at this reaction in disbelief

7:26 PM

@CowperKettle Still having problem with redox?

@Mithoron Maybe

Maybe it's impossible to combine self-studying chemistry with other things..

Maybe I need to read anew about the properties of peroxides

@CowperKettle This reaction is logical, but I wouldn't bet on to work like this. Doubt if H2O2 is strong enough in basic solution.

orthocresol

@CowperKettle your problem is that you are trying to learn so many individual reactions

i do not know anything about peroxides except that they are oxidising agents

nor do i know the existence of this reaction

I am sure people have tried to tell you to not memorise reactions

I will say, you get nowhere by studying individual reactions. I know someone who knew all sorts of random factoids about the reaction between xxx and yyy. They had no understanding of basic concepts. To everybody else who didn't know much about chemistry, it looked extremely impressive, until he scored poorly on his tests.

This reaction is just H2O2 oxidising Cr(III) to Cr(VI). there is not much else to say. Whether H2O2 is a good enough oxidising agent in base is not something that you memorise. You either gain enough experience after doing chemistry for long enough, which is what Mith has done, or you consult a table of standard electrode potentials.

Maybe one other thing I would say about this reaction is that it forms CrO4(2-) instead of Cr2O7(2-) because the equilibrium between those two compounds (both are chromium(VI)) favours CrO4(2-) in base. en.wikipedia.org/wiki/Chromate_and_dichromate

8:23 PM

@orthocresol In order to solve the exam's Problem 37, you've got to know these reactions. I'm 100% sure people just rote-drill them into memory

@orthocresol nice!

8:40 PM

@orthocresol that's really a balm for me. I should not worry too much about not knowing some particular reaction precisely

@orthocresol I agree.

2 hours later…