so i had the question about enantiomeric excess calculation, normally
e.e = [α]mix/[α]pure*100. So for instance if i were give [α]p = 24, and [α]m = +8 and am asked to calculate e.e and %age of R and S forms..I just 8/24*100 = 33.33% = e.e
the rest 66.6% is optically inactive, so the so the (+) form is 66.6% and the other is 33.33%.