ungolfed:
if (y%2==0) return f(x)*y;
else return f(x);
golfed:
return f(x)*(y&1?y:1);
is there any way to further shorten this C code?
if (y%2==0) return f(x)*y;
else return f(x);
golfed:
return f(x)*(y&1?y:1);
is there any way to further shorten this C code?
C, exponentiation by squaring
int power(int a, int b){
if (b==0) return 1;
if (b==1) return a;
if (b%2==0) return power (a*a,b/2);
return a*power(a*a,(b-1)/2);
}
golfed version in 46 bytes (thanks ugoren!)
p(a,b){return b<2?b?a:1:p(a*a,b/2)*(b&1?a:1);}
should be faster than ...
I am mulling over a challenge to draw the Eiffel Tower in 3D with ASCII art, similar to this: http://codegolf.stackexchange.com/a/22763/10766.
However, it has a problem. If I do it code-golf, it will be a boring kolmogorov-complexity problem and will produce some pretty ugly Eiffels. If I do i...
Keystrokes needed to type the text
We all know that programmers tend to be lazy. In order to maximize your free time you decide to write a program that outputs a minimal number of keystrokes for text fed into it.
Input: A text that has to be converted into keystrokes. You may decide on how to...
You have to create a code which prints
:)
No white-space and newline character included
Random times but ranged between 0-255
Your score :
The count in bytes
Your Bonus :
Each up-vote = -5 from your score
Each down-vote = +5 to your score
NO need to edit scores according to number of...
using namespace std;
int main() {
string s1,s2;
char a;
cin.ignore(10000,'\n');
cout<<"please enter an character using your keyboard:"<<endl;
cin>>a;
cout<<"the S1 and S2:"<<endl;
getline(cin,s1);
getline(cin,s2);
cout<<a<<endl;
cout<<s1<<endl<<s2<<endl;
return 0;
}
the input is :
b
...
As per Jeff's suggestion in this comment:
You can use this question as a formatting sandbox. You can
edit this question itself (Community Wiki questions such as this one require 100 reputation to edit)
post answers to this question (Since this question is protected this requires 10 reputatio...
