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12:45 AM
@MadhuchhandaMandal i cleared JEE last year; i was just here to see what's this area, never been here before
this area seems fun :P would've loved it had i found this back then!
 
 
6 hours later…
7:02 AM
Anyone there?
 
7:29 AM
!
@DiyankoBhowmik Physics part 2 was 3x lengthy
@DiyankoBhowmik Biology was 0.33x lengthy? :P
Biology students had an advantage this time
@SakazukiAkainu It wasn't there back then
@OsheenSachdev It was out a week ago lol
 
Anonymous
8:03 AM
@Yashas I have a question about reflection of light from thin films. Are you interested?
 
yes
 
Anonymous
Okay, so in this video
 
I have slow net until 8th :/
32kbps
can u write it down?
 
Anonymous
Okay, I'm summarizing it
 
Anonymous
8:05 AM
There is a thin film on a metal plate
 
Anonymous
The film is transparent
 
Anonymous
And has thickness 3000 A
 
Anonymous
And refractive index 1.5
 
Anonymous
Now, what will be the path difference between the light rays ?
 
Anonymous
Which are reflected from either of the surfaces of the film
 
8:06 AM
$2d n sin \theta$?
+ pi
ok I screwd it up
+ lambda
not pi
 
Anonymous
There will be +lambda at both the surfaces, right?
 
wait
two reflected?
from either side?
 
Anonymous
The metal is more optically dense than film
 
Anonymous
I'm uploading a picture
 
I did not understand "Which are reflected from either of the surfaces of the film"
 
Anonymous
8:07 AM
wait a sec
 
the thin film is on top of the metal
when you said reflected, I took one as refracted and other one as reflected
the refracted one is the one which got reflected inside
 
Anonymous
 
Anonymous
Can you see the picture?
 
Anonymous
Over here, they added lambda/2 only for the upper surface
 
Anonymous
But not for the lower surface
 
Anonymous
8:09 AM
Why is it so?
 
Anonymous
I think the path difference should be just $2 \mu t$
 
loading... :P
 
Anonymous
buy jio 4g sim card :P
 
Anonymous
free 1 GB per day
 
I dont have a mobile
3/4 loaded
 
Anonymous
8:11 AM
You can use jio on dongle also
 
Anonymous
:P
 
Anonymous
Jiofi
 
btw I meant lambda/2 few mins ago
not lambda
pi = lambda/2
 
Anonymous
right
 
Anonymous
But there will be lambda/2 added for both the reflections
 
8:12 AM
ok now I see
no
 
Anonymous
@Yashas Why not?
 
consider a string tied at two ends
nvm
when light is reflected from a denser medium, u get extra phase difference of pi
if it is reflected from a lighter medium, u get no extra phase difference
I think string is a good example
 
Anonymous
So a metal is an optically denser medium than glass, isn't it?
 
one end is fixed
the other end is fixed to a denser string
take a string
@blue oh interesting
did not notice that
yea, u get lambda/2 at both places then
 
Anonymous
Right, the solution must be wrong :/
 
8:14 AM
is there zero separation b/w the metal and the glass?
In reality, there wud be some air b/w
 
Anonymous
I wonder....
 
Anonymous
No idea
 
Anonymous
JEE questions are very ambiguous :P
 
you can fight :p
 
Anonymous
BTW you know there were 4-5 wrong questions in the mains paper this time
 
8:17 AM
o0
 
Anonymous
Cp-Cv=R
 
Anonymous
That one
 
the Cp and Cv were ambigious
 
Anonymous
And the kirchoff's second law and null point one
 
o0
how is that wrong?
when u exchange G with E, the null point does not change
that was the answer, right?
 
Anonymous
8:18 AM
Firstly Kirchoff's second law can refer to both KVL and KCL
 
AH
I was confused too :D
 
Anonymous
And secondly "null point" in itself is a very vague term
 
xD
I did not know it :D
 
Anonymous
So that question might be cancelled
 
Anonymous
It was stupid
 
8:19 AM
but I found the null point options, so I guessed
 
Anonymous
:-P
 
second law to be KVL
 
Anonymous
Kirchoff's laws aren't named like that :/
 
Anonymous
Those bookworms won't undertstand
 
@blue how is null point a vague term?
ok I see
null point in a wheatstone bridge
they shud have told a potentiometer or something
lol
 
Anonymous
8:20 AM
ok, gotta fo for lunch
 
Anonymous
:)
 
they shud have used "the bridge is balanced" or smthing
but I think it was guessable that they meant ^ by null point
 
Anonymous
8:31 AM
@Yashas Yup, anyhow I am getting lesser than 250 I suppose :-P
 
Anonymous
I thought I would get over 250
 
Anonymous
So how are you preparing for advanced? :-)
 
Anonymous
I am redoing all my maths study materials and the physics galaxy problems
 
Anonymous
I am bad at organic chemistry though :/
 
Anonymous
Got to revise my notes and do the previous year problems
 
8:34 AM
I am good with organic
I suck at inorganic
 
Anonymous
Opposite for me :-P
 
Anonymous
I'm not bad actually at organic...just that I keep forgetting the reaction mechanisms
 
You don't need to remember reaction mechanisms; you can guess your way through.
Just learn the mechanism 2-3 times and you will remember it forever.
I always write the mechanism for most of the reactions.
Aldol condensation
Perkins reaction
Cannizaro
Claisen
Micheal Addition
Knovengel
Reformatskey
Beckmann
and many more
It is hard to remember tricks for each reactions
and btw aldol, perkins, claisen, etc. have the same mechanism
different names becaz u start with different products
 
Anonymous
@Yashas About 100 more :P
 
Anonymous
@Yashas Yup
 
8:38 AM
if u know cannizaro and aldol, then you know all of them
aldol has acidic hydrogen
cannizaro does not use acidic hydrogen
tbh I don't know the name of the reactions
I only know aldol, cannizaro and micheal addition becaz M for active "m"methylene group
I can write the products if u give the reactants though :P
 
Anonymous
Aldol can occur with nitro and cyanides also :P
 
yup
 
Anonymous
Too many exceptions
 
Anonymous
lol
 
nitro aldol
cyano aldol
retro-aldol (reverse reaction)
those are not exceptions
same mechanism
in carbonyl compounds the C=O is making the alpha H acidic
 
Anonymous
8:41 AM
Right
 
in CN or NO2 compounds, the CN or NO2 is making the alpha H acidic
it's the same thing
 
Anonymous
8:53 AM
@Yashas Does the equation $P_{net}=P_A+P_B+2\sqrt{P_AP_B} \cos(\phi)$ hold good? (Suppose we don't know the intensities of the light waves from two slits in YDSE but we know the slit powers)
 
Anonymous
I know that the equivalent equation for intensity holds true...not sure about this
 
Anonymous
Slit areas may be different
 
that formula will always hold good
it is a universal formula
if you treat two source independently
and you get the intensity to be A due to the first source and B due to the second source
that formula will always give u the net intensit
 
Anonymous
@Yashas Which one, the power one or the intensity one?
 
it is vector addition
P was power?
 
Anonymous
8:55 AM
P is power
 
Anonymous
Not intensity
 
Anonymous
The intensity one always holds true
 
Anonymous
I know that
 
let me complete though, A^2 is proportional to I, replacing A^2 with I in the vector addition formula, u get that frmula
ok power
P is proportional to Intensity
so that works too
 
Anonymous
No wait
 
8:56 AM
Intensity = power/unit area
 
Anonymous
P=I.A
 
Anonymous
If areas are different then it isn't true
 
you take infinitely small A
you are talking about points
power to due to different sources at two points
 
Anonymous
Wait a second
 
*one point
 
Anonymous
8:57 AM
I'm showing you the problems
 
wait what the hell am I talking
I wrote nonsense
That formula won't work
becaz u meant the power of the source
 
Anonymous
 
Anonymous
P=Slit Power
 
that is correct
 
Anonymous
Intensity * Area Of Slit
 
8:58 AM
wot?
 
Anonymous
did you get the image?
 
loading
 
Anonymous
In the image, I think the resultant power formula is wrong
 
Anonymous
As the slit areas will be different!
 
ohhh it is correct
you need to take it this way
 
Anonymous
9:00 AM
@Yashas Is it?
 
same intensity of light falls
the smaller slit gives out light on the other side with lower power
from the lens perspective, the intensity of light is smaller
P is proprotional to I
becaz at the lens surface area
u do P source/total area to get intensity
the total area is the same for both soruces at the lens
let me upload a pic
 
Anonymous
Ah, that is confusing....they mean something like Intensity= $\frac{(I.A)}{\text{Total Area}}$
 
Anonymous
What is $4\pi r^2$ ?
 
surface area of the virtual sphere
the power is distributed equally in all directions
in ur slit experiment, it is a hemisphere
 
Anonymous
9:05 AM
Ah, I see
 
Anonymous
Cool
 
Anonymous
This was a good problem then :)
 
it depends on what P is
 
Anonymous
yup
 
Anonymous
P is slit power
 
Anonymous
9:06 AM
I.A
 
Anonymous
9:25 AM
 
Anonymous
@Yashas In interference by an air wedge, why is reflection from the lower surface of upper plate and upper surface of lower plate considered only?
 
because they are not parallel
the reflection from the lower surface isn't parallel to the rays reflected from the upper surface
they don't interefere
 
Anonymous
@Yashas Wait, whose lower surface are you talking about?
 
Anonymous
The upper plate?
 
the lower plate :p
ok I mixed it up lol
The rays reflected from the lower plate are not parallel to the rays reflected from upper plate
 
Anonymous
9:28 AM
Here they took reflection from lower surface of upper plate and upper surface of lower plate
 
interesting
 
Anonymous
@Yashas I don't think they used that logic here...
 
I might want to draw what happens inside the two plates
I'll see after few hours
 
Anonymous
They clearly took reflection from both the plates
 
I don't have paper atm
 
Anonymous
9:29 AM
@Yashas You are studying on the terrace or what ?
 
Anonymous
:P
 
garden
 
Anonymous
Not in your room?
 
Anonymous
lol
 
I walk in the sun
so that I get some excersise
I wud be 24x7 inside home otherwise
 
Anonymous
9:30 AM
Yeah, collect some vitamin D :P
 
I have an iPad though
can draw in it
too lazy
 
Anonymous
I study on the staircase most of the time :P
 
Anonymous
Passer bys look at me strangely
 
need to download app and shit
 
Anonymous
They think I am mad, sitting with my laptop on the public stairs
 
Anonymous
9:32 AM
lol
 
Anonymous
this pg website has great problems...whew!
 
Anonymous
:D
 
Anonymous
10:22 AM
 
1:54 PM
@Yashas ah okay
 
@Yashas here is the catch. Before commenting typical Indian teacher dialogue you should get the facts right. The correct answer is C — user150700 6 mins ago
what the hell is that OP saying?
He says the correct answer given is C.
 
 
3 hours later…
4:48 PM
@Yashas shifting was going on at my place so I had no internet :P
got to know yesterday night
 

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