@DanielFischer I have to describe the operation of the processure "RADIX SORT" at the following list of words:
COW, DOG, SEA, RUG, ROW, MOB, BOX, TAB, BAR, EAR, TAR, DIG, BIG, TEA, NOW, FOX
When I want to show the work of the algorithm RADIX SORT do I have to sort the letters by comparing them or do I have to show also the work of COUNTING SORT ??
Hello @user1787331 !! I have to describe the operation of the processure "RADIX SORT" at the following list of words:
COW, DOG, SEA, RUG, ROW, MOB, BOX, TAB, BAR, EAR, TAR, DIG, BIG, TEA, NOW, FOX
When I want to show the work of the algorithm RADIX SORT do I have to sort the letters by comparing them or do I have to show also the work of COUNTING SORT ??
user129943
12:38 AM
@MaryStar you really need to get ... like go to a library and get a computer science book
"MY FIRST JAVASCRIPT PROGRAM PLEASE GO EASY ON ME LOL", "AND I'M A STATISTICS BEGINNER"
find the calculator in question at,
http://js.do/NOFREEWILL/atleastonce
and the code I am using for this is......
function calculate_this() {
var input = document.getElementById('numbers').value;
var ...
@MikeMiller I suppose I want to know what a symmetric matrix means in terms of linear operators, like for example: Semi simple in terms of linear operators means that we have a basis of e-vectors, and in terms of matrices it means that some matrix A is diagonalisable
I don't know that I have a satisfying answer, and I'd have to think about it a bit
Unfortunately I'm a bit busy right now so hopefully someone else can say something interesting? (I think this might be a good question on main if you flesh out a bit more by what you mean 'in terms of linear operators')
Is there any good definition of "length of a curve" that does not depend on limits or integration?
Like, for area, all you need to do is define the area of a rectangle, and say that "A contains B" implies "A has a bigger area then B." This uniquely defines area for all open sets, I believe.
(So, in other words, it uniquely defines area for anything that you can actually say has an "area." The area under I_Q doesn't count.)
Guess: Well, we know the length of lines. And we know that lines are the shortest paths. And we know that "A is convex and contains B, also convex" implies "A has a shorter perimeter than B." Does this define length?
Like, let's say we want to find the perimeter of a circle. Since lines are the shortest paths, we know that it has a bigger perimeter than any inscribed polygon. And because of the last thing, we know it has a smaller perimeter than any circumscribed polygon. This gives us the perimeter, since it's the only such number.
A discrete set is something like {1, 2, 2.5, 6}, where each number is "separated" from all of its neighbors. An example of a not-discrete set would be the set of all rationals, or the set of all reals, or even {.9, .99, .999, .9999, ... , 1}, because the 1 isn't "separated" from anything (meaning that every open interval containing 1 also contains another number in the set).
At least, I think {.9, .99, .999, .9999, ... , 1} isn't discrete.
Another way of saying this: A discrete set is one where every point is an isolated point.
I went to a 21st birthday party on Saturday and I lost that entire day, and some of the Sunday, which meant time for study had to come from somewhere(normal sleep time)
Call the roller of big cigars, The muscular one, and bid him whip In kitchen cups concupiscent curds. Let the wenches dawdle in such dress As they are used to wear, and let the boys Bring flowers in last month's newspapers. Let be be finale of seem. The only emperor is the emperor of ice-cream.
Take from the dresser of deal, Lacking the three glass knobs, that sheet On which she embroidered fantails once And spread it so as to cover her face. If her horny feet protrude, they come To show how cold she is, and dumb.
@MikeMiller Any idea why $\dfrac{dS}{dr}\dfrac{1}{r\left(1+\left(\dfrac{dS}{dr}\right)^2\right)^{1/2}} \sim\dfrac{\frac{1}r\dfrac{dS}{dr}+\frac{1}r\left(\dfrac{dS}{dr}\right)^3} {\left(1+\left(\dfrac{dS}{dr}\right)^2\right)^{3/2}}$ ?
@MikeMiller the equation is $x''=0$, which you can discrtize as $x_{i-1}-2x_i+x_{i+1}=0$ (once you multiply by $h^2$) for $i=0,\dots,n$ (and so something at the endpoints...)
@ɧɿρρԹʅȝՇԵՐՎԾՌ If you are looking for an integral to try, I just posted a solution to $$\int_0^{2\pi}\int_0^1\int_0^1xy\sqrt{x^2+y^2-2xy\cos(\theta)} \,\mathrm{d}x\,\mathrm{d}y\,\mathrm{d}\theta$$ Try it before looking :-)
Does $A^n = \operatorname{Id}$ imply that $A$ is diagonalisable?
Is it as simple as seeing that $A^n = \operatorname{Id}\implies A^{-1}AA=\operatorname{Id}$ where Identity is obviously diagonal, hence the $P$ that diagonalises $A$ is $P=A$?
Someone was saying something about similarity and self-adjoints, but I didn't follow