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12:00 AM
My teacher forgot to upload my grades and now I'm going to have a week full of bureacracy and paper work to fix the f***ing mistake.
 
@DonLarynx - Yeah, that's what I'm doing... I'm trying data science, but it is going to require quite a bit of work. Hopefully it'll all work out at the end.
 
@ModdedBear: Looks like it should be easy for you, as that requires no strength :)
 
mabye, but paperwork is like kryptonite.
 
@evinda A red-black tree? Also not something I know the rules of, I'm afraid.
 
@Clarinetist that's good! But also engage in one more area, preferably outside mathematics in general. Otherwise, you'll be worried about spending your life dealing with numbers.
 
12:03 AM
For example calisthenics
sports is the best hobby imho
@DonLarynx yeah, cardio is for girls
although I do sneak into the pilates classes once in a while.
 
@DonLarynx - True, true indeed. It's just hard to do *anything* really, when you work full-time and are expected to progress through exams. If I could do anything with my life, it would be some combination of the following:

1) Piano lessons and/or composing
2) Teach math/statistics/actuarial science at a university
3) Publish an actuarial textbook or study manual
 
@ModdedBear or should I say Dr. Fernandez, for the week being, you will be okay. Send me some extra kryptonite in case you are winning in our next challenge.
 
@Clarinetist: you are a pianist, then?
 
@AlexWertheim - Yes, and clarinetist. Clarinet for about 11 years now (been on a hiatus since I graduated last May) and Piano for about 5 years, but off and on. I'd like to improve my piano skills.
 
@DonLarynx you better not slow down in PE. Because when I decide to punch, I will punch hard.
 
12:07 AM
@Clarinetist: neat. Working on any piece in particular at the moment?
 
If you ever decide to. Ha
 
@AlexWertheim - Just trying to get back to composing at the moment. It's just hard to be inspired when I live in a city where everything seems to be business and insurance.
 
What city is that?
 
Des Moines, IA.
 
@DanielFischer A ok...
 
12:09 AM
I could see how that might be difficult. Doesn't seem like there's much soul or romance in business/insurance. :)
 
@AlexWertheim - Nah, not really. :P Especially when you're an actuary out here. Silence permeates the departments I've been in. You only talk to people when you have a question or if there's a department outing. And even those outings, dang, they're awkward as heck.
 
Okay let me tell y'all a thing and get some reactions
 
How comes your prep for the subject GRE?
 
@AlexWertheim - Right now, I'm not really sure what to do with that exam. I'm definitely going to take the General GRE again. My Q score wasn't bad, but not the best either.
 
@Alexander: is it a story all about how your life got turned upside down?
 
12:14 AM
The only reason that I've been switching between YES, I'M GOING TO TAKE IT and I MIGHT NOT is because I don't know if I'm going to have the time right now, and I don't know if I necessarily need it for what I want.
 
@AlexWertheim Now I'd like to take a minute just sit right there
I'll tell you how I'm going to calibrate some particle detectors using combinatorial optimization.
 
:)
@Clarinetist: I see, makes sense. Well, whatever you decide, good luck!
 
Thanks @AlexWertheim
 
@AlexanderGruber that's awesome
 
So, suppose we've got a machine with a bunch of keys, say 100 of them, call them $\text{k}_i$. Whenever a key is touched, it sends a signal to the machine, saying $\text{k}_i$ was touched at time $t_i$.
We can't personally go in and press any of the keys, but every once in a while, some person will come in and randomly press a bunch of keys and leave. Then we get that data
 
12:18 AM
so a person goes in at time $t$ and presses a subset of the keys simultaneously?
or at different times?
 
@ModdedBear We'll say that every time a person comes in and presses a bunch of keys, that constitutes an "event", and events restart the clock.
 
ok, so then the buttons get pressed at different times by the person right?
 
So if they only pressed one key during an event, it would always register as time $0$
right
 
We'll assume that the events are far enough apart that they're distinguishable.
 
12:20 AM
k
 
So, the problem is this, we think that each individual key may have a different activation time. In other words, if somebody came in and all the keys were pressed at once, the times the machine recorded for each key would be their "true zero," $\text{z}_i$. These are assumed to be consistent
But, we don't know what they are
 
when you say all the keys where pressed at once you mean by the same person right? not at the same time.
 
I mean, at the same time.
 
oh ok
then the machine would tell you all the keys got pressed at the same time. Or not?
 
So, I'm saying, if we had an experiment where someone pressed $k_1$ and $k_2$, the $t_1$ and $t_2$ couldn't be trusted, because $z_1$ and $z_2$ may be different. Does that make sense?
@ModdedBear Yeah. It'd record times for all of them.
 
12:24 AM
ok
I didn't get that "true zero" part
 
what happens to t_i if key i gets pressed more than once
not that I have any idea what you guys are talking about
 
Basically the event timer may start recording times differently for different keys. If $k_1$ and $k_2$ were pressed both at once, maybe we would see $t_1=1$ and $t_2=2$, which is non-desirable.
@SamuelYusim All but the first one would be dropped. Good question (Meaning, only the time of the first press of each key is recorded)
 
ok, I think I'm getting it
so if you press six keys at once you'll get times $1,2,3,4,5,6$?
 
@ModdedBear we'll get $1,2,1+(z_3-z_1),1+(z_4-z_1),1+(z_5-z_1),1+(z_6-z_1)$
whatever those may be
 
oh, I got it
each key takes up a certain ammount of time to activate?
So some are slower than others?
 
12:30 AM
Exactly
And we don't know what the activation times are
All we have is the actual data the machine gives us, and we can't measure the "true" times the keys are hit
So one would think this would be a hopeless problem. We are blind because we can't trust our own eyes
my idea is this
 
wait
 
ok, sorry
I'm ready
 
So if we kept looking for events with $k_1$ and $k_2$ in it and we always found data like [event 1: $t_1=2$ , $t_2=3$], [event 2: $t_1=12$ , $t_2=13$], [event 3: $t_1=8$ , $t_2=9$] etc
it'd be pretty obvious that $k_1$ was $1$ second ahead of $k_2$
 
wouldn't one event be enough?
 
12:36 AM
It would if we were 100% sure that they were pressed at the same time.
 
oh right
ok
I got it
 
My idea is this... within a single event, it isn't possible to tell how accurate the timing delay we get is. But, timing delays should be transitive.
$k_1$ should always be $z_2-z_1$ ahead of $k_2$, $k_3$ should always be $z_3-z_2$ ahead of $k_2$, then $k_3$ should always be $z_3-z_1$ ahead of $k_1$. Within a single event, we would measure $t_2-t_1$ and $t_3-t_2$ and $t_3-t_1$ for these values
 
How does $(n+1)(n)(n+2)(3n+5) = (n)(n+1)(n-1)(3n+2) + 12n(n+1)^2$ I just don't see it.
 
But over multiple events, we can measure those values and compare $t_2-t_1+t_3-t_2$ from one event to $t_3-t_1$ in another event.
 
makes sense
 
12:43 AM
the closer those two values are, the more likely it is that it's the real $z_3-z_1$
so i'm trying to figure out if that's really a good way of looking for those $z_j-z_i$'s or not
finding the most consistent set of measurements would amount to finding a minimal spanning tree on a graph with vertex set $\{k_i\}$, with edges weighted by $t_i-t_j$ over all events
@DonLarynx how bout by interpolation?
in $\mathbb{Z}[n]$?
 
interpolation? How do I do that? In $\Bbb{Z}[n]$
 
@DonLarynx both sides are $4^\text{th}$ degree polynomials. If they agree at 5 points, they are the same.
 
@AlexanderGruber Hehe, $\Bbb Z[n]$ looks so weird.
 
they're both the same at $0$ and $-1$, that's obv
 
But if they agree at only 5 points, they don't necessarily agree for six. Wouldn't this make them not the same?
 
12:52 AM
@DonLarynx if two polynomials $P$ and $Q$ of degree $n$ agree in $n+1$ points they are the same
becuase the polynomial $P-Q$ of degree $n$ or less would have $n+1$ roots. Thus $P-Q$ is the zero polynomial.
 
Wow @Modded I learned that last semester. WTH?
 
plugging in $n=1$ gives $48=48$, check
then $-2$ gives $0=-2\times -1 \times -3 \times -4 + 12\times -2 \times 4 = 0$
then pick your favorite number for your 5th and you'll be doin good
 
@Alex!
 
@TedShifrin Hola
 
Back still better?
 
12:58 AM
Yeah! Biked to the gulf this week.
 
Oh, I'm so glad for you.
 
@TedShifrin So I just gave in and ordered a dip pen
 
LOL, I still use my Parker 51 that's 50+ years old. @Pedro and several of my students are fountain pen devotees.
 
@TedShifrin Yeah, I am too.
 
Nerds unite :)
 
1:09 AM
@TedShifrin if you ever get to Cincinnati you should check out Appointments.
 
r9m
1:54 AM
@Chris'ssis ?? -_-'' wha was dat?=P
 
My lab mate uses a fountain pen
I use an electronic pen and a writing tablet. Paper is soooooo 2000 and LATE
 
electronic pen and tablet is for noobs lol
 
r9m
@KevinDriscoll what kind of lab is it ?
 
@r9m My lab?
 
r9m
@KevinDriscoll yes
 
2:07 AM
Technically, its in our minds. We're theorists.
So by lab mate I really mean we're in the same group and share an office
 
r9m
@KevinDriscoll what kind ? :)
 
@r9m We do Cold Atom Theory
 
r9m
@KevinDriscoll that sounds totally cool, although I have no idea what a cold atom is (pardon my ignorance)
 
@r9m Usually we consider alkali metal atoms, although with our particular research it doesn't really matter. By cold we mean they are in the micro to nano-kelvin scale
Which means they could be a billion times colder than outer space
 
r9m
@KevinDriscoll wow!! cool !!!
 
2:17 AM
Hey. I have always had this speculation: when is a mathematician considered a mathematician amongst the mathematics community?
 
They're cooled so much because at the scale almost all classical motion is suppressed. The atoms act essentially as ideal quantum mechanical objects
 
r9m
@KevinDriscoll I see ! I just started reading the wiki page :)
 
Hey. I have always had this speculation: when is a mathematician considered a mathematician amongst the mathematics community? I.e., They can create a website and such.
 
That's called a web designer @Julian
 
No. Like can create a website for their work. Like I consider myself an amature and that I cant create a website because it will make me look stupid
 
2:24 AM
Make you look stupid amongst whom, @Julian?
 
And I asked another question too: when is a mathematician considered a mathematician amongst the mathematics community?
 
When they produce a work, @Julian.
 
Idk. It is just that like the website will look stupid if you dont have any work. but i have written notes and have one expository. but that is it.
i have a blog now, but I have been looking at personal webpages and they are better than a blog to me. But I have only seem ones for people that have published a paper. and that makes me wonder...
@Don
 
2:42 AM
You have nothing to prove to anyone but yourself @JulianRachman. Some notes and an expository is better than nothing.
 
That is true. But then I want to display it so should I use a webpage? Or should i wait till i have more or a publication? Because i was told like dont get it unless you have published something
@Don
 
Remember owning a website costs money, it's basically e-land. Land costs money. Ask yourself if it will be worth it.
 
I found one that is free and can be programmed from scratch using HTML.
I can send you the link if you would like
But I think I will stick with my blog for now. It was just a hunch.
:)
@Don
 
3:08 AM
the universal property of tensor products is weird and while kind of cool I can't say I like it yet
whenever I use it I get a bad feeling for some reason
 
user105491
3:34 AM
@Samuel It becomes more natural once you think of it in terms of category theory
 
r9m
I am grieved to declare that yesterday I broke the 344 consecutive days visits to M.Se ! :(((((( disaster !!
 
user105491
basically it then becomes the existence of a map that leads to the commutativity of a triangle
 
user105491
@r9m That is a lot more than my personal high!
 
user105491
:-)
 
r9m
3:37 AM
@SanathDevalapurkar I wanted to reach 365 somehow ! I couldn't login yesterday :( da** our servers :((
 
user105491
i feel for you
 
user105491
are you at a university?
 
r9m
ya ... the uni with possibly the worst internet service in India :(
 
user105491
ah, you're in india?
 
user105491
i used to study there
 
user105491
3:39 AM
until i moved to the us with my parents
 
r9m
I see :) ..
@user153330 I hope there was no actual mating involved ! =P rofl
 
3:57 AM
I dont know what I would do if our internet went down
Id be very much beside myself
sometimes we have a minor outage in the middle of then night
even after midnight, they already have people working on it
 
I know that feeling. When a page takes more than a couple of seconds to load I get a bit nervous. In some places, we've definitely been spoiled by consistent and speedy access to the world at large.
 
The probability that you get a particular number on one roll is 1/6 . Roll it 6 times to get a probability of 1.

True or false?
 
r9m
When I go back home from the uni in the summer/winter vacations .. it's a 28 hr journey by train .. no internet :P most of the time I stare out of the window but after sunset I simply stare at my co-passengers until they freak out! :P
 
@DonLarynx False.
 
r9m
@DanielFischer are the mod duties are affecting the tropical rainforest ?!! :O
nywy .. Time to watch 'we'll never have paris' .. :D bbl
 
4:15 AM
@walkar false. How come?
 
r9m
@robjohn many thanks for the answer at the integral ineq problem :-)
 
Hello!
 
4:34 AM
@DonLarynx Presuming each roll is independent, the probability that the number will not be rolled is 5/6, each roll has independent probability so to find the probability of the number not occurring after repeated rolls we multiply the chances together. (5/6)(5/6)...(5/6) six times gives us 15625/46656 chance of not rolling it after six tries. The probability we will see it at least once in six rolls is then 1-15625/46656 = 31031/46656.
@DonLarynx That, of course, assumes the dice is fair.
 
5:20 AM
Thanks @walkar
 
5:43 AM
Could someone recommend a book to practice probabilities based interview questions? It doesn't necessarily have to be geared toward interview questions, but I want to know about how to calculate things like expected values and related topics (I don't honestly know what related topics there are in probability). I have a basic knowledge but would like to become comfortable with the topic.
 
@DonLarynx No problem! Next time ask it as a question instead of on chat so I can get some rep from it, eh? Hahaha!
 
To clarify on my original post, when I say 'practice probabilities based...' I meant to say 'learn probabilties based...'
 
5:58 AM
@mathguy Im not sure anyone here would know. Those kind of questions usually get asked in wallst or consulting type job interviews.
 
@KevinDriscoll Well it was worth a try =/....but yea that is what i was going for
 
@mathguy Ya sorry. Most of the people who hang out in chat are academics. I dont know everyones background though so there may be someone.
 
6:31 AM
Hi people
I have a question that requires a proof .....can someone give me
The question is ......can every perfect number be expressed as the sum of three positive cubes .......
If someone has the proof or gets the proof send me on my email.....the paradox conjecture@gmail.com
No space in the emil
Email*
 
@ABeautifulMind Hi!
 
@user91500 Hello!
 
@ABeautifulMind How is my new picture?
 
@user91500 It's nice.
 
 
1 hour later…
7:59 AM
@r9m That was taken from the picture above my message. ;)
 
8:14 AM
@user153330 I have no idea who she is... Why?
@user153330 (re this message)
This has got to be the strangest question I've been asked here, by the way
 
8:40 AM
@r9m Yes, not entirely unexpectedly. But in the last days I've started finding time to look for questions again and even found a couple to answer.
 
8:59 AM
@robjohn the answer to that nested radical is not $\sqrt{2}$ (I initially made a typo). Anyway, it's nicely solved!
 
 
1 hour later…
10:22 AM
@DanielFischer Good Morning!!!
I am looking at collisions when we have a hash function... We can treat the collision with the method seperate chaining. We symbolize with n the length of the dictionary and with m the size of the hashtable.
In a structure of hashing with chains, of n elements, the median number of elements that are saved in a chain is a=n/m (load factor).
So is n the number of possible values that we can get from the given hash function? Or have I understood it wrong?
 
10:45 AM
@evinda n is the number of elements in your hash table, and m the number of buckets, as I understand it.
 
@DanielFischer So for example if we want to insert the keys 6, 9, 14, 17, 5, 7, 16, 20, 18, 19, 4, 11 in a hash table with 7 positions and we are given the hash function h(k)=k mod 7, then is m equal to 7 and n equal to 12? Or have I understood it wrong?
 
@evinda That's how I understand it.
 
@DanielFischer Nice... Thank you :)
 
Hi all
 
11:09 AM
@user153330 LOLOLOL
@TedShifrin Listened to what? I am studying homology right now :P
 
Huy
11:37 AM
Mathematics Advisory
Proposed Q&A site for people who are on the path to higher mathematics and want advise on certain techniques, future topics, reference requests, and "road maps" to related fields.
Really?
Hi @BalarkaSen. How's your studying going?
 
@Huy Isn't that already covered by this site?
 
Huy
@ABeautifulMind: Exactly my thoughts. I was just quoting it, see JulianRachman's starred message on the RHS.
 
@Huy OK, I am definitely not supporting it.
 
Huy
@ABeautifulMind: +1. How's your day so far?
 
@Huy Not good. I am planning for my future now, giving myself a few more years to get well and enter grad school. Also, making sense of what has been happening the last few years.
 
Huy
11:44 AM
@ABeautifulMind: I'm by no means a psychologist but doesn't thinking about it every day just make it worse?
 
@Huy It depends on what kind of things you think about, and how you think about it.
 
Huy
@ABeautifulMind: Ok. I hope you're making it better, then.
 
anyone got the answer to my question
 
Huy
@ABeautifulMind: Have you seen this? i.imgur.com/SJfTrr5.png
 
@ABeautifulMind u got the answer for the question
 
11:46 AM
@SayanChattopadhyay No.
 
is it tough
 
I am not in the mood to look at questions now, sorry.
Also, my knowledge is limited to simple arithmetic.
 
So can anyone solve it
so can anyone in this chat solve it
 
Huy
@SayanChattopadhyay: No, nobody.
 
thanks then
 
11:55 AM
hi
 
what's up ?
 
Huy
The sky.
 
@Huy lol
 
so what do u guys do .......i mean profession?
 
Huy
12:02 PM
Teacher.
And you?
 
Huy
Is that considered a profession?
 
nope i was asking yours
which field in mathematics r u a teacher in
 
Huy
I teach at high school.
 
oh......but u will love a topic right
 
Huy
12:05 PM
@SayanChattopadhyay: I like mathematical physics, but that's a bit too advanced to teach at high school. I currently teach linear algebra at high school.
 
oh i love number theory
 
@SayanChattopadhyay I'm at school, too
 
which country ramanewbie
 
France, like @hippa
 
Oh your name sounded like indian
 
12:10 PM
@SayanChattopadhyay @hippa gave me this account so he choose thye name, in fact he told me it was a joke to make @ted upset...
 
@Huy did u get something on the question that i wrote
 
Huy
@SayanChattopadhyay: I don't really care for number theory, sorry.
 
oh ........fail then
i have to now break my head out on this question
 
@SayanChattopadhyay where and what level are you studying ?
 
10 grade,India,bangalore
 
12:13 PM
ok
 
I don't know... in France we don't talk "grades"!
I should ask ted again
 
Then what do u talk
For "grades"
 
we say "5th, 4th, 3rd, 2nd, 1st" etc
 
12:16 PM
I'm on what we call "second"
 
I am 10th then
 
yes.
how old are you ?
 
@r9m how is it going?
 
r9m
@Chris'ssis ya I saw that ... quite alarming =P lol
@Chris'ssis good good not bad .. :)
 
12:17 PM
@r9m That was taken from the picture inside. ;)
 
@SayanChattopadhyay I'm 14 then
 
@r9m Do you wanna see my last creation?
 
r9m
@Chris'ssis YES!!!!
 
@r9m ^^ I'll include it in my book.
 
@r9m did u get anything from the question i posted
 
r9m
12:18 PM
@Chris'ssis haa!! Sweeeet ! :D
 
@r9m Thanks :-)
 
r9m
@SayanChattopadhyay which one?
 
This one I have a question that requires a proof .....can someone give me
The question is ......can every perfect number be expressed as the sum of three positive cubes .......
 
r9m
@SayanChattopadhyay okay :) lemme see .. thanks
 
Huy
@r9m: Are you familiar with Lie groups?
 
12:20 PM
Thanks a lot coz i want an answer
 
@Chris'ssis are you ok with your book ? is it nearly finished ?
 
r9m
@Huy not exactly
 
Lie groups what r those
 
@Ramanewbie I have all I need to it. It's just a matter of time for arranging things and make all looking amazing.
 
@Chris'ssis what kind of book
 
12:22 PM
@Chris'ssis You're sending it to @hippa right ?
 
@SayanChattopadhyay A collection of amazing integrals, series and limits.
@Ramanewbie I'll give him a copy of my book, yeah.
 
Wow feels like its going to be interestig
interesting
 
@Chris'ssis Then I'll be able to read it for free e_e
 
@SayanChattopadhyay I have thousands of questions and solutions created by me, so if the readers will love my book there will also be other books, if not, it's OK. I simply want to publish a book because I put much work in this area and I wanna see my results in hand under this form. :-)
 
THEn try my question
will you @Chris'ssis
 
12:27 PM
@SayanChattopadhyay I don't get your point.
 
well i thought of a question and the question is can every perfect number be expressed as the sum of three positive cubes .......
 
@SayanChattopadhyay that sounds interesting.
 
@Chris'ssis @SayanChattopadhyay isn't that the great theorem of Fermat ??
 
i have checked it for almost 9 perfect numbers
its the cube of every perfect number not perfect number
You should try it @Chris'ssis and also u @Ramanewbie
 
@SayanChattopadhyay @Chris'ssis have you seen my post just above ?
 
12:33 PM
Its not the great theorm of fermat
 
@Chris'ssis @SayanChattopadhyay yes, my bad, I was mistaking with that..
 
Fine not a problem
 
@SayanChattopadhyay There are tons of problems I should try, and I'll also try this one, but after finishing the work on my book. There are many things to do, it's a real adventure to publish a book! (especially for someone that has no background in mathematics like me) :-)
 
its the cube of a perfect number which can be expressed as the sum of three cubes@Ramanewbie
 
12:35 PM
@SayanChattopadhyay a perfect number is a number for which the root $\in{Z}$ right ?
 
it will be good if u try
a perfect number is one whose divisors accept itself add up to the given number
 
oh ok I see
 
For example 6=1+2+3 and 1,2,3 are its divisors
 
r9m
I take that back ... lemme work my chances with google (@Chris'ssis knows how obnoxious a googler I am :P)
2
 
Yes I see, but I'm doing a maths exercice right now, I may think of it a bit later !
 
12:38 PM
well r9m i want the proof
that it can be expressed as sum of three cubes
r9m so is what i am saying right
i have googled it already
 
@r9m :-))))))))))))))))))))))))))
 
@r9m i have tried everything
 
r9m
okay .. :) I'll take my chances anyway ;)
 
@SayanChattopadhyay what have you tried ?
 
so is what i am saying legit or right
googling, going to india's most prestigious institution by bunking my school for this question and much more
so tell me @r9m is what i am saying right
 
12:43 PM
@SayanChattopadhyay but have you searched by yourself ?
 
i have searched every book possible
worked for 8 weeks for this question without doing my schools work
now mathoverflow and mathematics stack exchange r my only hope
U got something @r9m
 
r9m
@SayanChattopadhyay I'll let you know when I find something :)
 
where will u let me know
take my email
theparadoxconjecture@gmail.com
 
r9m
@SayanChattopadhyay I'll ping you in chat .. that'll inform you (you'll get a red bubble in your chat tab :) .. )
 
Fine and thanks
 
12:51 PM
@Huy Homology looks complicated.
 
homology is complicated
 
Objects in singular chain complexes looks huge. I have no idea how Hatcher plans to compute singular homology of very non-simplicial objects.
 
Balarka u interested in number theory
 
@SayanChattopadhyay You're familiar with homology?
@SayanChattopadhyay Sure.
 
if u r pls help me in this question
 
12:53 PM
What is the question?
 
that the cube of every perfect number can be expressed as the sum of three cubes
 
r9m
@BalarkaSen man you make me feel like I have jelly in place of grey matter =P
 
u from wesstbengal
@BalarkaSen even me
 
@SayanChattopadhyay Looks interesting -- I have no idea.
 
Pls try doing it
 
12:55 PM
I have to run a program then :P
 
Yeah, well, I'd search for counterexamples by coding.
 
fine and when will u finish with it
well then there is one more question which i found during my research
 
technically, never, as I can't search every cube in the whole world
 
@BalarkaSen what language would you use, Python ?
 
12:57 PM
PARI. Way better than Python in case you're on number theory.
 
Are there infinitely many N3 (especially for prime N) that cannot be expressed as a sum of three positive cubes?
 
because i found that cubes numbers more than 100000 have 94% of having their sum written as cubes
Three cubes
 
@SayanChattopadhyay Probably yes, but I have no proof.
 

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