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12:25 AM
@TedShifrin welcome back :)
 
Yup @ Charlie; are you?
 
@TedShifrin yup
 
@TedShifrin do you have me on "ignore"?
 
No, @cyber, silly.
Not paying 1000% attention ...
 
@TedShifrin on the internet we use 9000%
:-)
 
12:29 AM
@TedShifrin oh...you're talking like Pedro...
 
Oh?
 
@TedShifrin tamaroff
 
Yes, i knew that.
 
then?
 
Didn't know why you said I sounded like him ...
 
12:31 AM
@TedShifrin he calls everyone silly
 
Oh ... Yes.
 
It's kind of an "old fashion" word...
 
I'm old :)
 
...not to be taken too seriously, right?
 
we're all old
 
12:33 AM
we're all adults, yes
 
Oh? @Charlie? More than 10?
 
@TedShifrin yes
 
@TedShifrin did you see my unicorn analogy to $\frac{1}{0}$ It is not real :-)
 
1:07 AM
Yes, @cyber ... Too mythological for me :)
 
@TedShifrin Thanks for responding :)
 
1:29 AM
If you have an equation like this: y = 2x + 5, it would translate to a y=mx+b function where m = 2 and b = 5.
Similarly, if you have are graphing square functions, like (x^2)+5, then what would the "5" translate to? Would that also be "b" in the equation?
Anyone?
 
Perhaps you mean "if ax^2+bx+c is x^2+5 then a=1,b=0,c=5."
Otherwise it is unclear what you mean by the strange words "translate to" and "in the equation."
 
1:54 AM
@anon You're right! Thanks. :) I have one more question.
 
go on
 
You factor ax^2 + bx + c, but what do you call when you expand something like (x+1)^2
 
just "expand." don't be fancy. students in the US often use the acronym FOIL for pedagogical purposes.
 
Again, what does is translate to. Is it (ax+b)^2 ?
So in (x+5)^2, a = 1 and b = 5?
 
what do you mean by "translate to"? as far as I can tell, the meaning of (x+1)^2 is already clear, there is nothing to translate it into and no reason to even if there were
do you mean "if ax^2+bx+c=(x+5)^2 then what are a,b,c?" or do you mean "if (ax+b)^2=(x+5)^2 then what are a, b?"
 
1:58 AM
Well, I am writing an analysis on what happens to the graph of the equation as its values change, so I need a way to refer to the 5 in (x+5)^2
 
5 is just 5. unless there is a general form you are considering...
you are not organizing or communicating your thoughts very well it seems to me
 
So I say as the second part of the equation increases, then the graph....?
 
what is "the equation"? do you mean the quadratic function f(x)=ax^2+bx+c? what do you mean?
 
So well, I need to analyze what happens to the graph when I graph (x+1)^2 vs (x-5)^2
So I need some way to refer to the +1 and -5 part.
"The graph moves to the left as the '+1' value increases." That sounds weird.
 
okay, so you are looking at equations of the form y=(x+a)^2 where a varies. you can put any letter in there where I have "a" and then refer back to that letter. that's how math works!
 
2:01 AM
Yeah, I guess I just needed to know what to call it and it would be "a." Thanks! :D
 
for example, say y=(x+c)^2 and allow c to vary, or y=(x+h)^2 and allow h to vary, it doesn't matter which letter you pick
 
Right, thanks :)
 
 
5 hours later…
6:42 AM
...and if you ask "why?" you will find your answer here.
:D
 
How to prove that the Complex numbers can't be ordered?
 
maybe, you should first ask how can you prove that the real numbers can be ordered?
 
7:02 AM
Why is it that so many people define topological closure as the union of a set and its limit points? That seems such an ugly definition.
 
ugly as compared to what?
 
As compared to 1. The intersection of all closed sets containing it as a subset, or 2. The smallest closed set containing it as a subset, or 3. The set of "adherent points" of the set, where an adherent point is a point $x$ in the space such that every open set about $x$ contains an element of the set.
I imagine there's a pleasant characterization in terms of limits of filters, but I'm too tired to think about that right now. The characterization in terms of limits of nets is a little too complex to be a good definition.
 
sleep well
 
THANKS.
That is unlikely.
But I realy do need to try.
*really
 
 
2 hours later…
8:55 AM
International Talk Like a Pirate Day (ITLAPD, September 19) is a parodic holiday created in 1995 by John Baur (Ol' Chumbucket) and Mark Summers (Cap'n Slappy), of Albany, Oregon, U.S., who proclaimed September 19 each year as the day when everyone in the world should talk like a pirate. For example, an observer of this holiday would greet friends not with "Hello," but with "Ahoy, matey!" The holiday, and its observance, springs from a romanticized view of the Golden Age of Piracy. It has become a holiday for members of the Church of the Flying Spaghetti Monster. History According to...
 
9:08 AM
Yarrrrrr. Shiver me timbers! I had completely forgotten about that.
 
:D
Yarrrrrr. Shiver me integrals!
 
J L
9:27 AM
can someone tell me why my post body isn't meeting the quality standards?
How do i integrate (int)(0topi)(cosx)^4(sinx)dx without using parts or trig integrals or trig substitution? Just plain u substitution?

All I can think of for u substitution is cosx, sinx, or cos^2x but those don't take care of anything..

Is there some kind of trig identity i have to use?

Help?
ughhhhh seriously ill just skip the problem
 
@JL You should probably look up how to do math markup on this site
 
J L
i never had a problem with not using math mark up before on this site though..... why wouldnt it meet the guidelines?
 
@JL hard to say. It is pretty hard to read what the math in it says, which might be the problem. But the precise algorithms are secret
 
J L
does anyone know of any other fast math help sites =_=
 
@JL just take a few minutes to look through how your other questions have been edited to see how to do the markup
I am fairly certain it will be good enough then
 
J L
9:33 AM
i just found an online integrator and figured out how to do it i think
-1/5cos(x)^5
 
finding out what the answer is is not the same as figuring out how to do it
 
J L
yeah but that reminds me of some rule where cos^n = -1/n cos^n right?
or i could be wrong...
 
that seems clearly wrong if you integrate the right side
sorry, differentiate
 
J L
oh wait that was cos(nx)
not cosx^n
cosnx antidirivative = 1/n sin(nx)
ugh
 
Learning the skill that Tobias is suggesting you acquire will help you out a lot...in the long run
 
J L
9:40 AM
im positive its not the markup though, because i put the same math symbols in the title and it was ok
 
@JL what do you mean it was ok? Can the title be rejected separately?
 
J L
last time i checked yes
this is my body
How do i integrate cos(x)^4*sin(x) without using parts or trig integrals or trig substitution? Just plain u substitution?

All I can think of for u substitution is cos(x), sin(x), or cos(x)^2 but those don't take care of anything..

Is there some kind of trig identity i have to use?
i've spent way too long just trying to figure out how to ask this question
i should have just moved on
my test is tomorrow
 
then do so
 
10:06 AM
Hello all, quick question: how do you call a function which statisfy:
f(x,y)=f(x)*f(y)
 
10:24 AM
@Mercury Hi, what does the comma mean? If it means f takes two arguments then how does it take just one on the right hand side?
 
I don't know if I have a name for it, but it looks like the standard beginning of a separation of variables argument in solving a PDE
 
10:35 AM
I wonder why one vote was sufficient to approve this suggested edit.
 
And the person who made the edit apparently doesn't know that you can just write \frac1n instead of \frac{1}{n}. It saves some typing.
 
@MartinSleziak I guess if you're the original poster and you approve of the suggested edit, then it only needs your vote.
 
Oh, I did not notice it was the OP.
D'oh
 
Also, Archimedean is misspelled
 
At least it was not completely pointless that I§ve mentioned it here.
 
10:40 AM
The benefits of having high rep: You can fix people's typos without needing someone to approve your edits ^_^. Though I usually only do that when it's only a few small errors. Fixing up posts full of typos and bad TeX usage suuucks.
 
I should have remembered the thing about OP approving suggested edits.
The disadvantage of having high rep: You can make typos in other people's posts and without approval process they are less likely to be caught.
 
10:54 AM
@JL Do you want to avoid $u(x)=\cos x$ for some reason.
That should work almost immediately.
 
 
2 hours later…
12:43 PM
hi guys
 
1:19 PM
hi guy
 
@cyberskull Hi ho!
 
@GustavoBandeira yo ho ho
 
@cyberskull How are you?
 
@GustavoBandeira fine thanks, how are you pal?
 
@cyberskull Fine too.
What ya doing?
 
1:33 PM
@GustavoBandeira reading the quora.com linked on the star panel...
 
@cyberskull Oh. It's a nice read. I've found it some time ago. Mariano posted on facebook.
 
the print is toooo small
 
@cyberskull Print? I don't get.
 
size of the printed letters
font size
like "reading the fine print in a contract"
 
@cyberskull Got it. Why don't you raise it?
CTRL + Mousewheel
 
1:39 PM
I did thanks :-)
 
@cyberskull Do you have an account there?
 
yup
 
@cyberskull Which one?
 
1:54 PM
i never use it
 
Got it.
 
2:20 PM
Greetings
Do you see any elegant way of computing $$\int_0^1 \frac{\log^2(1+x)}{x} \ dx$$?
 
hi, can someone help me about this problem ? Thanks. math.stackexchange.com/questions/498079/…
 
2:41 PM
hi
 
would anybody happen to know if I can have $a^n=1$ in an integral domain?
 
hello
 
hello
 
please i need help for this :{math.stackexchange.com/questions/498616/…}
if someone can help me
please pleas
e
 
2:50 PM
I'm not sure I understand
isn't the answer to the first question just y = 0.25?
 
i don't know
but how to answer a)
 
well you say that at t= 0, x = 0
then ask what the value of y is when x = 0
so basically you're asking for the value of y at t = 0
no?
 
but the initial conditions are different no?
 
I don't think I understand the question
 
ok and a)?
 
3:04 PM
I really don't know
 
3:25 PM
@JackM you understand french ?
 
oui
 
ok donc si je te donne la version française peut etre que ça sera plus claire ?
 
ben quand x(t) = 0, t = 0, non?
ou du moins t = 0 c'est une solution à x(t) = 0
 
ça c'est pour a)?
 
oui
 
3:33 PM
pour a je ne comprend pas il est dit trouver une valeur approximative pour y et après pour choisir on a $x\approx ...$ ???
 
oui moi aussi je comprends pas ca
faute de typographie?
 
surement oui donc pour toi ça serai quoi la valeur approximative de $y$
 
ben moi je mettrai 0.25
mais je sais meme pas de quelle matiere relève l'exo
je m'y connais pas, je réponds par intuition
 
systeme dynamique plan
mais y(t) ne peut pas etre égale a 0,25 pour tout t
je ne croit pas que y(t) soit une constante
 
mais on cherche y(t) quand x(t) = 0
 
3:41 PM
oui x(t)=0 ne veut pas dire que t=0
 
j'imagine que non
mais t = 0 et donc y = 0.25 est une solution
il peut y'en avoir d'autres, mais à ce moment la je vois pas pourquoi la question est posée comme ca
c'est pour ca que je pense pas avoir compris
normal, puisque je connais pas du tout la matiere
 
donc je pense que logiquement la réponse est :on ne peut pas répondre
 
possible
 
t'as une idée pour b) s'il te plait
je suis désolé mais ya personne pour m'aider
 
j'imagine que faut le faire graphiquement?
tu vas au point initial, tu trace un petit segment dans la direction du champ vecteur
et tu itère
 
3:51 PM
itère ?
 
tu recommence en ce point, quoi
 
dans le plant de phase a partir de (-2,-0,25) je trace un petit segment
 
je pense oui
 
j'ai pas sue faire
 
4:21 PM
@robjohn you were right, I am a badass ;-)
 
@cyberskull I said that? wow...
 
@robjohn Yes, you put it on a meme
of that physicist
 
4:33 PM
Heya =)
 
4:59 PM
@N3buchadnezzar: Hiya ;)
 
@cyberskull Ah, yes. I remember that.
 
@robjohn I'm trying to find a nice proof here $$\int_0^1 \frac{\log^2(1+x)}{x} \ dx$$
 
@Chris'ssis I think I did that recently...
 
@robjohn really?
@robjohn it evaluates $\zeta(3)/4$
 
{| border="1" style="float: right; border-collapse: collapse; margin: 0 0 0 1em;" | colspan="2" align="center" | |- |Binary | |- | Decimal | |- | Hexadecimal | |- | Continued fraction | 1 + \frac{1}{4 + \cfrac{1}{1 + \cfrac{1}{18 + \cfrac{1}{\ddots\qquad{}}}}}Note that this continuing fraction is not periodic. |} In mathematics, Apéry's constant is a number that occurs in a variety of situations. It arises naturally in a number of physical problems, including in the second- and third-order terms of the electron's gyromagnetic ratio using quantum electrodynamics. It also arises in conju...
Quite a lot of cute expressions there
 
5:16 PM
@Chris'ssis It is $$\sum_{n=2}^\infty\sum_{k=1}^{n-1}\frac1{nk(n-k)}$$
Which is also $$\sum_{k=1}^\infty\sum_{n=1}^\infty\frac1{(n+k)kn}$$
 
@robjohn $$\sum_{k=1}^\infty\sum_{n=1}^\infty\frac1{(n+k)kn}=2\zeta{(3)}$$
@robjohn our integral is $8$ times smaller.
 
5:39 PM
@robjohn It should be $$\sum_{k=1}^\infty\sum_{n=1}^\infty\frac{(-1)^{n+k}}{(n+k)kn}$$
 
@Chris'ssis yes. I figured that out and I am working on that
 
@robjohn ok
 
 
1 hour later…
6:58 PM
What is the set theory definition of sigma summation?
 
7:22 PM
@Chris'ssis Back at home. I will finish up that sum.
 
@robjohn ok. I think I found an elementary way to shoot it right in heart. (still need to make some checkments)
 
What does $$\sum_{n\in\text{primes}}\frac1n$$ converge to
 
@robjohn I'm curious about your way. (by the way, there is no hurry here - take your time)
 
@JackM If you still are interested, yes you can have $a^n=1$. Pick your favorite finite field. :)
 
@Alizter: it diverges, $\Bbb{P}$ is a large set
 
7:31 PM
@DanielR Explain?
 
@robjohn my approach was wrong.
 
@Chris'ssis okay, I'm still working on getting the alternation under control.
 
@robjohn ok. It works if I employ the trilogarithm but it annoys me this idea.
 
@Alizter A large set is a set where the sum of the reciprocals diverges, and a small set its counterpart
so $\Bbb{P}$ is a large set, but the set of the twin primes is curiously a small set
So, it is not known if there are infintely many twin primes, but even if that is true, it is known that the sum of the reciprocals converges. Which is kind of cool imo.
@Alizter If it's a proof you're after, pick a favorite out of the four ones that are presented here: en.wikipedia.org/wiki/…
 
8:31 PM
@robjohn I've just reconsidered my initial idea and I realized that I need to respect more what polylogarithm is. It's simply powerful here.
 
8:50 PM
Why is nobody on tonight?
 
Are we nobody?
Hmm, perhaps so.
 
9:17 PM
@TedShifrin When I refer to "on" I meant it in the sense that not many people are cahtting
 
10:20 PM
math.stackexchange.com/questions/499018/… --- does it "smell" to anyone else like OP is self-studying and in way over their head?
 
10:39 PM
@kahen Definitely way over their head - might not be self-studying - they might just not follow the lectures very well :)
 
11:08 PM
Need to solve a problem? Having trouble? Thought freeze? Well then just listen to this a couple of times and your brain will return to its normal state. Thought provoker
 
11:56 PM
Hi @anon
 
hello
 
@anon how are you doing?
 
pretty good
 
:11308015 ooooh
Almost (removed) your life, @ethan ?
 
11:59 PM
@Ethan One time when I was a small child I drank a small strange container of liquid in my kitchen that was supposed to be for some machine of my mom's. Then I asked her what would happen if someone drank such a thing, and she said they'd be poisoned. Went to bed that night making peace with myself, woke up the next morning alive.
 

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