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12:00 AM
I really need to learn to focus, I wasted all day today not studying
 
user19161
@Jordan And what did you do?
 
Procrastinate
 
I get a feeling that somewhere in the world, black hats have gotten together and created a search engine specifically for sites with robots.txt
shadow google
 
user19161
Who knows how to make gmail not record "most contacted"?
 
user19161
I can set it to add contacts myself but that is another story.
 
user19161
12:03 AM
Oh, for once I appeared in the "frequently in room" list here!
 
user19161
@Jordan Less procrastination, more discipline then.
 
"frequently in room" list?
 
user19161
@anon Click on "info" near top right.
 
I am a little surprised I am not on there
That is a competitive list
 
user19161
@Jordan It changes according to an unknown algorithm.
 
12:12 AM
@JasperLoy Yeah I know that.
 
Is there a limit to how many times a comment may be edited? 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36
 
@anon Not times, but time. There is a finite amount of time.
 
apparently that's the case
 
I thought it was 5min
 
@anon BTW, I was telling rob I got Modern Algebra by MacLane and Birkhoff
Seems to be an awesome text, I got it for 15 bucks more or les, hardcover.
 
12:20 AM
@PeterTamaroff I was reading that in Reno. I loathe some of the notation used.
 
@anon It has Group Theory, Class Algebra, Transfinite Arithmetic, Rings and Ideals, Galois Theory and other simpler stuff.
@anon Hahaha well, it is an old text.
@anon What is Reno?
 
Nevada
like, $f^*$ and $f_*$ for images and preimages.
 
@anon Well, it is a cool notation IMO.
Succint.
 
user19161
@anon 2 min.
 
impossible for me to remember which is which :P
 
user19161
12:24 AM
@Weiler That pair wrote two books: Algebra and A Survey of Modern algebra.
 
user19161
@weiler I see you have gone incognito.
 
user19161
Algebra has more advanced topics than the other book, but both start from scratch.
 
meta.stackoverflow.com/a/33939 says that comments can be edited for 5 minutes.
 
@JasperLoy I have the latter.
@JasperLoy I'll go back, I guess.
 
user19161
@MarkDominus Oh, sorry if I was wrong then. Anyway these things change all the time.
 
user19161
12:27 AM
@Weiler I have the former.
 
Am I sounding harsh here?
@JasperLoy So you know quite a good deal of algebra right?
 
@JasperLoy Quite so. You might be correct that it is now 2m.
 
user19161
@MarkDominus It's interesting how you suddenly appeared in chat on a number of occasions after I commented on something.
 
(If you studied from it)
 
I'm not sure about biology being the best subject for it. And there is a spectrum, so some of the "higher-functioning" autistics can indeed explain themselves to some extent. (See "Born on a Blue Day" for instance.)
 
user19161
12:28 AM
@Weiler Well, I forgot everything. But I'll start reading up again if I were to apply to grad school.
 
user19161
@anon Yes, there is the autism spectrum. Then there is Asperger's too.
 
@JasperLoy Strange that I have not noticed you before.
 
user19161
@MarkDominus Well, maybe it was someone else, and maybe I had another username!
 
I need to get a B on this test to have a chance in the class I think
 
user19161
@Weiler You will be comforted then to know that it does have some things the other one does not contain that are important as well.
 
12:30 AM
@anon Well, that'd mean the autism has been "cured" in some degree.
@JasperLoy It's cool it has Group Theory, Class Algebra, Transfinite Arithmetic, Rings and Ideals, Galois Theory.
 
I have just edited a three minute-old comment.
 
user19161
So I was looking at some meta posts on whether we should give hints or complete solutions. I guess both are allowed and have pros and cons.
 
user19161
So I guess I'll just go by my gut feeling when answering questions as to how complete the answer should be.
 
I edited a 4m old comment, but after 5m the "edit" option vanished.
 
user19161
@MarkDominus OK, so I think it is 5 min right now.
 
user19161
12:34 AM
Haha, you actually bothered to find out.
 
Well, I can prime factorize 81^100 in less than 2.5 minutes.
 
You had the same username in 2010.
 
user19161
@MarkDominus Are you talking to me?
 
Yes.
 
user19161
@anon So can I.
 
user19161
12:36 AM
@MarkDominus Yeah but I was also Will Hunting and Clark Kent at some other points in time.
 
user19161
Not to be confused with the Clark who asked about tensor products that Ben mentioned.
 
user19161
@weiler Now I must mentally make the map weiler=peter.
 
@JasperLoy lol. I'll ask amod to change it back.
@anon I have a problem here.
 
user19161
@Weiler Hey, if you keep asking them to change they will be pissed!
 
user19161
Your changes might crash the whole network!
 
12:39 AM
@JasperLoy I didn't ask yet. @Eugene didn't tell me who to contact.
 
user19161
@Weiler An exception to the 30 day rule seems to be if you create a new account. Then you can change it there and copy to all the rest.
 
über trippiness
 
user19161
@mark Are you a potato?
 
Not to the best of my knowledge.
In fact, I am a parsnip.
 
user19161
Ah, well I only know about potatoes.
 
12:43 AM
I only know about blue squares.
 
user19161
@MarkDominus Haha, you remembered that I was a blue square?
 
user19161
Maybe I shall use that again.
 
oh lawd
this same question came up like 4 times in the review problems for my test and I am pretty sure something like it but more difficult will be on the test
 
user19161
@Jordan What's up?
 
$\int_0^5 2 \pi (3t^2) \cdot \sqrt{36t^2 + 36t^4} dt$
 
12:46 AM
@Jordan start by taking $36t^2$ out
 
I made that into $36t^2(1+t^2)$
 
@Jordan Where's the $\sqrt{}$?
 
but from here I am a little confused on how to proceed, I know I can make that into sinh
still there
 
Yeah, that's true.
Why don't you try to find a primitive of the integrand and then use Barrow's Rule?
(so that the limits of integration don't get too messy)
 
I don't know barrows rule
 
12:52 AM
@Jordan Could you do it?
@Jordan It is $\int_a^b f(t) dt = F(b)-F(a)$, sure you do.
 
oh I thought that was named something else
 
just call it the fundamental theorem
 
@anon FTC II
 
Stewart probably names it Stewarts rule in his book
 
It is actually a corollary to the FTC
@anon Hehe, look at this vector space:
 
12:54 AM
they're both corollary to each other, so their order of presentation is actually arbitrary
 
@anon True.
 
I will just have to take this class over in a year probably
 
$V= \Bbb R_{>0}$ , $K=\Bbb Q$ and $\oplus : a\oplus b = a \cdot b$ and $\otimes: m/n \otimes a = a^{m/n}$
 
everything with college seems purposely drawn out to keep you there as long as possible to get as much money as possible from you
 
@Jordan Haven't you watched American Pie: The wedding?
 
12:56 AM
nope
 
YOU DON'T SCORE UNTIL YOU SCORE.
 
why does this same thing come up so many times
I skipped that problem and went back and it came up again
$\int_0^1 \sqrt{36t^2 + 36t^4} dt$
 
@Jordan $$\int\limits_0^1 {\sqrt {36{t^2} + 36{t^4}} } dt = 3\int\limits_0^1 {2t\sqrt {1 + {t^2}} } dt\mathop = \limits^{{t^2} = u} 3\int\limits_0^1 {\sqrt {1 + u} } du$$
 
oh
 
Helpful spacing commands: \, \; ~ \quad \qquad \hskip 1in (set $1$ however desired, even in decimals)
11\,1\;1~1\quad1\qquad1\hskip{0.5in}1 $$11\,1\;1~1\quad1\qquad1\hskip{0.5in}1$$
 
1:04 AM
@anon Thanks for the brotip.
 
@robjohn You missed a prime opportunity to fire your Bezout canons!
 
@BillDubuque It is interesting how all your questions are linked to each other.
 
@Weiler Mathematics is linked in many beautiful ways. Unlike linear-limited books, we have the capability here to make these links explicit.
 
Oh no, I forgot to memorize eulers formula
 
@BillDubuque Indeed. BTW, I'm Peter Tamaroff, I just changed my username. Do you know if any of you can change it back?
@Jordan $e^{i \varphi}=\cos \varphi + i\sin \varphi$?
 
1:10 AM
eulers method
 
@Weiler why did you change it?
 
@AndrewSalmon I googled my username and Google spat out all the chat logs and stuff, which I found uncool. But I can deal with that.
@BillDubuque Is your avatar Klein's j-invariant in the complex plane? (Not that I know what that is, just found the Wikipedia page on $j$-invariants)
 
@Weiler Yes, that's my gravatar
 
@BillDubuque That is really high arithmetic right?
(Pardon the inevitable pun)
 
modular forms
 
1:14 AM
@Weiler yes, especially after a little moonshine!
 
@BillDubuque Hahhah lol.
 
memorizing eulers method seems like wasted effort at this point
 
@Jordan It is very useful!
 
I just need to get an A on this test
 
@Jordan Then keep the rythm! =)
 
1:16 AM
I will probably fail the test
failing this class really sets me back far, i don't know when I can take it again and I will have to before I can transfer
Means I can't transfer for another year or two
 
@Weiler What do you want your Display Name to be?
 
And then when I do apply for transfer it is for the next year, and I will be done with all the classes at this school so I will be wasting my time
9 years for a 4 year degree, no big deal
 
@BillDubuque Peter Tamaroff
 
@Weiler Ok, done.
 
@BillDubuque Thanks.
@BillDubuque What is your opinion on Modern Algebra by MacLane and Birkhoff?
 
1:23 AM
I can't believe how little studying I did in 4 days
I went over like 12 problems
 
I never heard the name "Barrow's rule" either.
 
@Weiler I've only ever browsed it, so I really can't say. But given the distinguished authors, it is surely worth a look.
 
Wikipedia also has no entry for "Barrow's rule". Is it named for Isaac Barrow?
 
@MarkDominus Yes.
 
That makes sense
 
1:27 AM
@MarkDominus It is mentioned in the FTC page of Wikipedia
 
Thanks.
 
I cant get any of these answers
I am so screwed
 
@BillDubuque Bill, I have a conundrum going on.
 
I have $x^2lnx - \frac{x^2}{2} = y^2 + \frac{2}{3} \cdot (3+y^2)^{\frac{3}{2}}$
for y(1)=1
 
Hmm, saying a group is a direct product of subgroups is different from saying it is isomorphic to a direct product of subgroups.
 
1:31 AM
Say $v$ is a vector in $V$ and $k$ are scalars, such that $V$ is $K$-vector space.
In the property that $(a\cdot b)\cdot v=a \cdot (b \cdot v)$ shouldn't one more clearly write:
 
two different binary operations?
 
$(a\cdot b)\otimes v=a \otimes (b \otimes v)$ where $ \otimes$ is the action from $K\times V$ to $V$ and $\cdot$ is the binary operation of $K$?
 
I would not use otimes, because then it's confusable with the tensor product.
Also, it's called "abuse of notation."
 
@anon Well, whatever, make it a $\star$,
@anon Yeah I know, but it makes things confusing, like proving the vector space I mention above is one
Also
, for $(a+b)\cdot v= a\cdot v + b \cdot v$ one should write $(a+b)\otimes v= (a\otimes v) \oplus (b \otimes v)$
where $\oplus$ is vector addition (properly defined whatever the vector space is)
 
If one is first introducing the notion of a vector space, using two different symbols for the scalar-vector versus scalar-scalar is a good idea.
@PeterTamaroff now you risk confusing with an element of the direct sum of vector spaces!
 
1:37 AM
@anon Hahhaha but that is just for now!
I'm not dealing with direct sums now.
 
I dont get this
 
However, if we simply write \cdot for everything, the correct symbols can be recovered unambiguously, so there's no inherent issue with using \cdot for both after this is clear.
 
I need to make $ \int y dy = \int x dx$ equal to y(0) = -3
that seems impossible, the books answer seems like they just made it up
 
Why no up/down votes for this?
 
@RajeshD TL;DR all over you, dude.
 
1:39 AM
@RajeshD What the monkeys is the point of indexing things? The equalities apply to each triple a,b,c separately!
Argh.
 
?? I did'nt get what is TL and DR?
 
team liquid and diminishing returns
 
@RajeshD Too long, didn't read.
 
team liquid?
ok
 
1:41 AM
@anon, yes the question isn't related to sequences actually
 
jesus
no matter how many times I do this stupid u sbustituion problem I cant ge tit
I have never felt this bad before a test
this is going to set my life back like two years
 
user19161
@PeterTamaroff It's great, but in my opinion the other one is better!
 
@Jordan Which one?
 
0
Q: Solve $y' = x + y$

JordanI am suppose to use the substitution of $u = x + y$ $y' = x + y$ $u(x) = x + y(x)$ I actually forget the trick to this and it doesn't really make much sense to me. I know that I need to get everything in a variable with x I think but I am not sure how to manipulate the problem according to mat...

 
user19161
@Jordan Stop whining.
 
1:44 AM
@JasperLoy Hhaha well, I'm not aiming for really high algebra, and I have amazing luck I even got this one.
 
@anon : But I don't understand how it managed to get 9 upvotes?
 
user19161
@PeterTamaroff Neither is too advanced. Both are suitable for undergrads.
 
I think I will get to take a year break from math
 
If $u=x+y$ then $u'=1+y'$ then $y'=u'-1$
Then you get $u'-1=u$
 
user19161
@raj I see your new photo!
 
1:46 AM
thanks
 
@JasperLoy Cool.
 
@RajeshD Me either. I'm reading your answer, and it seems it can be substantially simplified. At any rate, I think there's an error, as you confuse HM with its reciprocal in the equation after "it can be seen that."
 
user19161
If you want really advanced general algebra, look for the three volumes by Paul Cohn.
 
In particular, it should be AM / (GM^3 / HM)
 
i'll see
 
1:47 AM
this problem doesn't make any sense to me, I just can't do it on my own. I read through the solution and tryi t myself and I can't do it
 
user19161
@Jordan Don't you have tutors and lecturers there to help you?
 
they are horrible
 
user19161
Aren't they better than asking people here?
 
If you get lucky and one is a native english speaker then it can be okay, but they are always booked
no
 
user19161
It's hard to discuss math in a chat room.
 
1:48 AM
I am better at math than most of them
I have to wait for them to go through the problem, I always finish the problem first
 
user19161
@Jordan Most of who?
 
the tutors
 
user19161
Er, I doubt it.
 
lol, that's a bad sign
 
@JasperLoy Yeah, same here.
 
1:49 AM
@anon : Argh, I don't know how to forgive myself for doing this type of crap!
 
user19161
@jordan You saying you are better than your tutors, I think that's a joke.
 
there is one tutor who is a native english speaker but he is a huge asshole about it, he laughs at people who are bad at math and thinks the classes are too easy
 
@Jordan Then why are you struggling?
 
because I am bad at math
 
@Jordan Reminds me of 13-year-old version of me.
 
1:50 AM
@Jordan That's a bad person, not a bad tutor, technically.
 
It is possible to be both.
 
Someone really needs to jump that guy, so he can learn some respect
 
@anon Shame on you!
 
user19161
@Jordan Considering how you keep saying people here are talking down to you when they are not, I don't think he really laughs at you.
 
user19161
1:51 AM
@Jordan Maybe you need to learn that yourself.
 
He should write a textbook some weekend.
 
user19161
@jordan Do you know how many people you have insulted here? Yet you say people lack respect. I am finding it quite amusing.
 
@anon Hahah, I proposed @Bill wrote one some day! I'd mindlessly but it!
 
Arturo is really amazing.
 
Well when people say things are easy it isn't directly talking down to me but it is hard to interpret it otherwise
How do I insult people here?
 
user19161
1:52 AM
@Jordan Go figure out. You are not an idiot.
 
popcorn
 
user19161
I have met too many people in this world who hurt others but keep saying others hurt them. I am very sick and tired of all these people.
 
@anon : how to scratch out, latex code?
 
I think I should just skip it, it is kind of in depth and a one-off problem
 
1:54 AM
@anon Silly. Nachos and cheese.
 
I have an hour left to study tonight befoer the test tomorrow
 
user19161
@jordan My honest opinion of things is that you really should not be doing math, but you are free to choose your own path in life.
 
@RajeshD don't bother scratching it out, that's only something you do if lots of people were exposed to a wrong version of some math and a big fuss was made. in your case, your answer has next to zero attention given to it, so you should just edit it out.
 
user19161
For example, I can't ride a bicycle, even though I have tried many times.
 
There isn't anything else to do if I avoid math
 
1:56 AM
ok
fine
 
In fact scratching out latex without reason will just make it longer and even less likely to attract attention.
 
@JasperLoy Interesting. Get a gyroscope, dude.
 
@Rajesh: Would you mind if I edit it?
 
everything requires math that I have an interest in
 
no You can edit it
@anon
all yours
 
1:58 AM
@Jordan Then work your ass off.
 
user19161
@anon Well, sometimes it is clear from the context what one is trying to say.
 
@JasperLoy I was just making an observation that I thought was interesting.
 
@Jordan Why do you keep unaccepting?
 
I dont understand it
 
user19161
@Jordan Is it because it is too sketchy?
 

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