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Jan
12:30 AM
\cleardoublepage\null\cleardoublepage worked, so I’m going with that for now. Maybe I’ll find a witty quote for the publication version *shrugs*
 
 
2 hours later…
2:51 AM
I loved Portal, I wish Portal 2 had been funnier.
 
3:39 AM
@DHMO Sure, I could run those for you -- what sort of information are you looking for out of them, though? May or may not be as simple as a single calculation on each.
 
3:55 AM
Hey, @airhuff Don't mean to drag you into chat (or do I?) But I've seen you've been doing an awesome job with the editing! Keep it up, it's super appreciated! :)
 
 
1 hour later…
5:08 AM
@orthocresol tch you shouldn't have time for video games!
so...tired...zzzzzzzzz
 
 
2 hours later…
7:24 AM
@Jan if you don't mind me asking, how close are you to the epic badge?
You seem to have large gains on a regular basis
So I'm kind of curious... esp since no one has got it yet
 
7:58 AM
@hBy2Py molecular orbitals
shapes and energies
 
 
4 hours later…
11:57 AM
Are there people who know about capillary zone electrophoresis in chat?
3
 
@DHMO All occupied orbitals for all of them?
How advanced of a calculation do you need?
How certain do you need to be that the info is correct? (e.g., personal interest vs. publication)
@CowperKettle Not me, sorry.
 
I see
I'm translating a response from a technician. He says that in CZE we don't have neither "reducing" nor "non-reducing" conditions
He contrasts CZE with the methods in which the sample is passed through polymeric gels
> The choice of either of the two analytical conditions (reducing/non-reducing) indicates the presence or absence of pre-analytical processing of the test sample. Such processing enables the subsequent interaction of the sample with the SDS and makes the sample respond in a different way when it is passed through polymeric gels.
I never heard of pre-analytical processing of the test sample in order to somehow enable it s interaction with SDS
So I'm unsure whether I"m translating correctly, and the work is urgent.
Okay, let it stay thus.
 
@Cowp The text seems sensible as you quote it, assuming the motivation is valid for the underlying experimental method(s)
It seems likely to me that it's discussing a particular type of sample, though -- I can't imagine it would apply generally.
@hBy2Py @DHMO Let's continue discussion in [this side room ](chat.stackexchange.com/rooms/52126/dhmo-hby2py-quantum-calc)
 
12:15 PM
The technician is trying to explain to a colleague why exactly in CZE it is impracticable to demand from the workers that they specify "reducing/non-reducing"
 
Oh.
 
> In addition to SDS, proteins may optionally be briefly heated to near boiling in the presence of a reducing agent, such as dithiothreitol (DTT) or 2-mercaptoethanol (beta-mercaptoethanol/BME), which further denatures the proteins by reducing disulfide linkages, thus overcoming some forms of tertiary protein folding, and breaking up quaternary protein structure (oligomeric subunits). This is known as reducing SDS-PAGE.
Ah..
Maybe this heating is done prior to putting them in SDS?
Then I would understand the translated piece
 
Oh, absolutely, this would be prior to the SDS-PAGE
 
Bingo! Thanks
 
Well, I'm glad it helped you. I'm still fuzzy. :-)
 
12:17 PM
(0:
 
But I don't need to understand. :-D
 
 
1 hour later…
1:32 PM
@hBy2Py Ah, ignorance is bliss ;D
Now @Koolman, I've had a look at the question again (and referred some material) and I've arrived at @hBy2Py's conclusion as well: The question is incomplete...that, or it's very poorly worded. Now you'll have to make a few assumptions before you can start figuring out the answer...
Now, I'm using (what I understand of) the Crystal Field Theory
You'd probably already know how the color of (transition metal) coordination compounds are determined using the above-said theory.
Greater the crystal field splitting brought about by the ligands, greater the energy required to bump up electrons from lower d-orbitals (for example: t2g in octahedral complexes) to higher d-orbitals (eg in octahedral complexes). Which would mean the more energetic (lower wavelength) end of the electromagnetic spectrum would end up getting absorbed.
So, since wavelengths in one portion of the spectrum are absorbed, the rest pass on and give the complex the color we see...
Say, if the crystal field splitting were very large (as would be in the case of CN- ligands) light from the blue-violet region would be absorbed, and the complex would appear yellow.
Similarly, if the crystal field splitting were very small (as would be the case, when you're dealing with F- ligands) light from the red-magenta region would be absorbed, and the complex would appear green.
Now, assuming that it's just a part of the visible spectrum that gets absorbed, we'll move on to your options.
Your first option's wrong, since the color change (roughly) ought to be from bluish-green to a green-yellow; since Cl- is a much weaker ligand that H2O.
Option two seems about right, since a strong field ligand is replaced by a weaker one.
 
2:13 PM
Option three would look better in reverse (i.e- from blue to violet)
Option four, is ambiguous...what do they mean by pale-green? Is it a blue-green or a yellow-green?
I guess the question wants you to find the most appropriate ( correct) option instead of "incorrect". HOWEVER, I am not an expert on coordination compounds...so don't quote me on this ._.
 
 
2 hours later…
3:56 PM
@paracresol How you have compared third option
 
4:24 PM
0
Q: UC Davis ChemWiki is gone

Martin - マーチンI noticed today that the domain chemwiki.ucdavis.edu redirects to chem.libretexts.org. While most of the content is still available there, quite a few links may have gone rouge on our site. The switch must have happened sometime in July last year. old design new design redirect If you find a...

 
4:34 PM
hmpf, I could do a HNO3 temperature calculation for the safety shower question if only could find out how to read this table: books.google.de/…
I even have the original report, but the quantities and units are not really documented. :-(
 
@Loong for example, read the row for n=7000 and n=5000
it means that when 0.01110 M of HNO3 is diluted to 0.00793 M
sorry, the unit isn't M
reading from n=1.0, m=55.506, apparently this is concentration by mass
 
I am quite sure that m is not the molality of the acid here since most values go up to m = 55.5
 
since 1000/18 ~ 55.506
 
100 % HNO3 has a molality of 15.9 mol/kg
55.5 mol/kg is the molality of water in pure water.
 
so what is it
 
4:45 PM
All the engineers here, listen up!
0
Q: Turning a circuit off...without touching it

paracresolJust a curiosity question; Is it possible to reduce current (to almost zero) in the following complete, simple circuit without making ANY physical contact with it? Supposing this can be achieved by a certain procedure, say X. Then X must: Not involve any significant change in temperature (n...

 
5:00 PM
@orthocresol then what on earth is that?
 
5:19 PM
@MelanieShebel To be fair it was probably really difficult to live up to the original Portal. which is why I feel like Valve might not want to work on P3. Basically quit at a high point...
@pentavalentcarbon I am trying to enjoy whatever bits of life I can still enjoy, before starting org syn next year. :)
or before finals in June...
@MelanieShebel No, this does not drag him/her into chat, unless they have been spotted in the chat room within a certain period of time. See: meta.scifi.stackexchange.com/questions/938/…
@DHMO This is how I imagine it would go: i.stack.imgur.com/ZAiuo.jpg
 
@orthocresol but there isn't an aldehyde there
look at my intermediate
it has a tertiary carbon
 
I'm not sure what your point is. You can add 2 methyl groups to my substrate on the hydroxyl-bearing carbon and there's no difference.
 
the beta-carbon lost a hydrogen in the first step?
 
No, there aren't any hydrogens missing.
 
the beta-carbon in the first species has 2 attached hydrogens right
in the second species there is only 1 attached hydrogen
I mean the carbon with locant 3 in the first species
 
5:40 PM
Right. That's an alpha carbon. And that hydrogen goes onto oxygen by tautomerism.
 
ADH
Is anybody here interested in teaming up with me to start a software company?
 
@orthocresol a hydrogen is gained right
 
ADH
I have been building computer software since the late 90’s and would like to build computer aided drug design software.
 
@orthocresol oh, I realized that I'm a fool
 
6:16 PM
@orthocresol does making a double bond at the alpha-carbon make the dehydration easier?
 
Jan
6:48 PM
@ringo 34th day today =)
 
7:04 PM
Wow!
I'm only up to 13
 
7:16 PM
@Loong I have found even older values in Landolt-Börnstein, which explains the used quantities and units – in contrast to that stupid National Bureau of Standards report. Maybe I can explain the table when I compare the data. :-|
 
@ringo How did you even get to 13?
 
7:38 PM
It's been a process
Every now and again
Like yesterday
I'm a little surprised ron doesn't have 50 yet
 
 
3 hours later…
Jan
10:17 PM
Right, I’ve prepared my answer; I’m ready to post it the second the question gets reopened xD
@ringo Ron has 43.
 
 
2 hours later…
11:59 PM
@orthocresol going through that as we speak...play more music
 
Jan
@orthocresol You can enjoy life without org syn? (CC @penta)
 

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