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1:19 AM
@IͶΔ It might be better to forget about it entirely. Just pretend it's soluble in nitrogen.
 
 
7 hours later…
N A
7:55 AM
I flagged a post for spam and my flag was declined, yet that post was removed...
 
8:06 AM
@NA It was no spam, it was offensive. In order to not confuse the automatic spam detection I had to decline it. See also here
 
 
1 hour later…
9:18 AM
I wonder if there is a way to know beforehand that what the products will be.
 
I knew your sentence would start with "I wonder ..." ;)
 
I would have never guessed the products in this reaction. (0:
@pH13 Chemistry is a wonderful science. (0:
2
 
touché
 
Maybe one should just memorize reactions like these, and there will be some explanation further in the texbook.
 
What is you chapter about?
 
9:43 AM
@NA Spam != offensive
Well, @Mart always makes sense when it's not past midnight there.
@CopperKettle You don't need to memorize anything for science. Stamp collecting is another matter.
 
hmmm... I think I can make sense after midnight here. Just don't get me wet...
 
9:58 AM
@pH13 Dissociation of salts
Dissociation of Zn(NO3)2 yields an acidic medium. But wait, we've got two ions of NO3(-) created in the process, would they not nullify the influence of ZnOH(+) and H(+)?
Zn(2+)+2NO3(-) + OH(-) + H(+) == ZnOH(+) + 2NO3(-) + H(+)
 
10:21 AM
This is supposed to explain why the solution turns acidic.
But why not scratch out H(+), since this ion existed on the left side of the equation.
HOH = H(+) + OH(-)
Good afternoon, Muhammad!
 
@CopperKettle Afternoon
@CopperKettle What?
 
@IͶΔ The H(+) ion existed on the left too. Why not scratch it out, since they scratched out 2NO3(-).
Still I don't get why the solution is acidic. We've got two positive ions, and two negative.
 
10:40 AM
@CopperKettle Are all these reactions happening in the solution right now?
Sorry, I'm a bit distracted.
 
@IͶΔ Yes, it's basically a simple reaction of dissociation of zinc nitrate
I asked a question on Socratic, since there's no downvotes there. (0:
 
Well, ZnOH+ is an acid, no?
 
Yes, it must be, since it wants to grab an electron.
 
So you have lotsa acid and not lotsa base.
 
But I've got 2 base ions of NO3(-)
two positives, two negatives, voila! zero net charge.
I'd better ask this on a Russian website too.
 
N A
10:48 AM
@Martin-マーチン Thanks for the clarification on that. I'm a moderator on another website and that's the kind of thing we would consider spam there, but I guess things are done differently around here :)
*The clarification about the flagging I mean
 
no problem
 
11:06 AM
@NA Welcome to the Table anyway!
 
 
1 hour later…
12:07 PM
It seems that there's an error in the charges of PO4 here, they go from -1 to -2 instead of the other way.
Or maybe I don't understand something.
 
12:48 PM
@IͶΔ A Russian chemist explained it in another way. What we obtain is a basic salt, Zn(OH)NO3, and an acid, HNO3. Hence the solution is acidic.
Probably because a basic salt does not dissociate and loses no OH(-) groups into the solution?
 
1:27 PM
I forgot. Why when an acid loses H+ into the solution, why does the solution turn acidic? There's the negatively charged moiety too, generated by the same fact of H+ being split off. Why this negatively charged thing does not nullify the action of H+?
 
 
2 hours later…
3:10 PM
Can an 2NO3(-) ion make the medium more 'basic'?
A person answered my question on a Russian forum and said that it is only OH(-) ions that can make the medium 'basic'.
 
3:34 PM
@CopperKettle No, because HNO3 is a strong acid and basic salts are usually weak.
I mean in their basicity.
 
user116211
3:45 PM
Can anyone tell me why electrons beyond the concerned electron, say, in the $n$ shell do not contribute in the screening constant? Why do only electrons of $n-1$ shells contribute in the screening constant?
 
@user36790 You mean why for instance, in Ca, the other 4s electron isn't contributing in the screening constant?
 
user116211
@IͶΔ No, electrons in that particular shell other than the chosen one do contribute in the screening constant; each contribute $0.35$
 
user116211
What I'm asking is why the electrons beyond the shell where the chosen electron belongs to don't contribute in screening constant.
 
@IͶΔ But 2NO3(-) is a base, not an acid. It has not H(+) attached. Good evening, Mar.
 
4:24 PM
Probably I should ask this on the main site and get a handful of downvotes.
(0:
 
4:45 PM
@CopperKettle there are some errors
 
Yes, that answers volume is riddled with errors. I'll plow through it and switch to a better book at a higher level. (0:
 
you see that I was referring to the h3po4-image?
 
@pH13 Yes, the multi-stage salt lysis.
They got some numbers mixed up.
I'll go and read me some more.
BBL!
 
bbl?
 
 
2 hours later…
6:26 PM
@pH13 Be Back Later
@CopperKettle Yes, I agree.
@user36790 I know, I wanted to know what you know.
 
0
Q: Calculating spontaneity of galvanic cell reaction

user510I was having trouble on figuring out how to calculate spontaneity of a galvanic cell with electrolytes different than the electrodes: on the anode side, you have aluminum electrode and aluminum chloride solution and on the cathode side, you have copper electrode and sulfuric acid electrolyte. Us...

 
@user36790 But it wouldn't make sense if they did.
@Feeds What the hell
Why are people maining the meta?
 
@CopperKettle Yay
@Feeds Huh, that feels good.
I should write more comments like that.
 
user116211
7:02 PM
@IͶΔ: I don't know but it was put as one of the Slater's Rules in my book.
 
7:22 PM
What really obtains when we react zinc with sulfuric acid?
1. Zn + H2SO4 → ZnSO4 + H2
2. 4Zn + 5H2SO4 = H2S + 4ZnSO4 + 4H2O
And this is a third(!) variation. O_o
 
7:39 PM
Almost 90% questions in the first 2 pages are on hold!!
 
Homework questions, probably.
I wonder if my question just above is fit for the main site.
 
 
4 hours later…
11:48 PM
O/
hey
 

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