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Q: Does PA prove that Con(PA) implies Con(ZF-I) and Con(NFU)?

user21820I read from many sources that PA and ZF-I (a suitable axiomatization of ZF minus Infinity plus its negation) are bi-interpretable, but is PA enough to prove that they are equiconsistent? Specifically is the following true? $\newcommand\t[1]{\textrm{#1}}$ $\def\imp{\rightarrow}$ $\def\eq{\leftrigh...

 

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