Discussion between A.D. and Joe Z. - 2015-04-20

last day (15 days later) »

11:15 PM

1

A: What is the next number in sequence?

The seventh number is 6136. Each digit is its own separate sequence, as follows: 6, 4, 6, 4, 6, 4... is just a sequence alternating 6 and 4. 2, 2, 3, 1, 3, 1... the sum of the four digits increases by 1 modulo 9 every time. 1, 1, 2, 3, 5, 8... is the Fibonacci numbers. Since the next one is 13...

Your solution pinning $4$ as the second digit seems a bit iffy.

If you look at the update I've made, you'll see you're on the right tracks :)

You have all the information you need to solve it. There is no unknown sequence of number involved.

Oh, so it was what I was thinking of earlier, then.

I added a hint to help you

You have the right number but not the right explanation. Your rules wont work with the next number.

The next number should be 4616, then?

11:15 PM

That's not it and it's pretty off. But you are really close in the rules you have.

Shoot, I thought I had it. In any case it fits the given numbers and seems elegant enough... what did you intend?

The next number is 9215. It might help you to find the rule

9215? wuuuuuut

oh, you mean the one after the one I think is 4616

yes

so the sequence now goes 6211, 4214, 6321, 4135, 6359, 4182, 6136, ????, 9215

or is it 6211, 4214, 6321, 4135, 6359, 4182, ????, 9215?

11:20 PM

the sequence is now 6211, 4214, 6321, 4135, 6359, 4182, 6136, 9215

oh

so the top one wasn't just alternating 6, 4, 6, etc.

hmm

the alternance of the 6 and 4 was chosen to disorient you

okay

then I'm in a pickle

2, 2, 3, 1, 3, 1, 1, 2

for the second digit

or maybe the first two digits are considered together

62, 42, 63, 41, 63, 41, 61, 92

so let me help you a little bit.

did I get the part about the "sum of the digits" right, though?

11:22 PM

your fourth rule is correct

oh, by 4616 I meant 4615, sorry :S

your third rule is almost correct

your "sum of the digits" rule is correct

so my last two digits are correct

yeap

my third rule is almost correct

so I assume it's the ones' digit of some other sequence

that just happens to look like the Fibonacci

11:24 PM

the sequence is correct

the "one digit" is not

so it's not a digit-by-digit thing then

exactly

well, "6136" and "9215" do indeed have "13" and "21" there

so would the number after that be 6343?

you have 3 out of 4 digits correct

it's X343

oh, uh

7343

11:27 PM

nope. do you want to know the rule?

sorry, forgot that 9 is speci--uh

it's not 7343?

or wait

no

nope

8343

Yes that's it

addition errors

11:27 PM

good job

It happens :)

and the one after that is 4555

That's the reason I needed to update the serie at first

yeah

actually there is no more values after that

because, the rule is sum all digits to have a single digit which match the rank of the number

rank?

oh

as in the digital root

yeah, I thought it might have been that

but if you wanted to continue it, it would be mod 9

11:30 PM

yes

I mean, 4555 gives you 19 -> 10 -> 1

anyway, good job.

If I was in your position, I think I couldn't solve it

That's right. I didn't think of that.

hmm

we all make puzzles that we couldn't solve

it happens

good job Joe

That's right :)

I hope you liked it

11:34 PM

I suppose

last day (15 days later) »

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Apr '1520

Discussion between A.D. and Joe Z.

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number-sequence

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