« first day (587 days earlier)      last day (3898 days later) » 

5:29 AM
@Mr.Wizard also congrats on the 100k network rep :D, which is also GREEEEEEEEEEAT :)
 
5:51 AM
Thanks, @Jacob
 
 
6 hours later…
11:45 AM
Meet our new forum super-asker, Mr. Matrix Transpose Man. (user9***)
 
 
2 hours later…
1:17 PM
@halirutan thanks for your reply, it was very nice and informative!
oh, and hi everyone
 
@Sosi No problem. I hope you have the read the pre-notes ;-) If you are really interested in the point which is most far away from all borders, then you need something like a distance transform or you use a nearest function like the others suggested.
 
@halirutan yeah! I hadn't thought about that point! Thank you so much, I learnt something
on another subject: is there any way to ping someone in here, that is currently not in the list over on the right? Say I wanted to ping @kuba
 
Hmmh. At least web version of documentation of Element lacks reference to symbolic array domains.
 
@Sosi The list to the right is not so important. What is important AFAIK is whether you get the user name completion when you start typing @ku.. which is not the case.
In this case, normal users have no possibility to inform someone.
 
@halirutan I thought that automatic completion would be related with that user list.
oh
ok ok, no problem. Thanks!
 
1:24 PM
@Sosi Nope. Try MrWiz, who is currently not here.
 
Oh! I see! I thought it was because I am a normal user
Ok ok
 
 
1 hour later…
2:37 PM
posted on August 27, 2013 by Michael Trott

(This is the third post in a three-part series about electrostatic and magnetostatic problems involving sharp edges.) In the first blog post of this series, we looked at magnetic field configurations of piecewise straight wires. In the second post, we discussed charged cubes and orbits of test particles in their electric field. Today we will [...]

 
...so the other day I was speaking with a colleague that does only wet lab (i.e. experimental biologist, not computational). He was telling me that his boss wouldn't let him get an automatic way of counting cells, and was asking him to count them manually the good-old-fashion way. I was searching around and found this very interesting post. Boy, do these guys do wonders with Mma
 
3:39 PM
@rm-rf thanks for asking - short on time today, so if anyone else feels up to posing the question, please go ahead!
 
@Sosi There are some very impressive posts on here as well in that area, e.g.: mathematica.stackexchange.com/questions/25137/…
 
@Calle wow that first reply!
this is awsome!
if i ever have to do some lab work, I'll make every single of my colleagues learn mathematica just to do this
 
4:13 PM
:P
 
@Sosi unfortunately, scientists are human and can be blind. I'd suggest, if they have mma installed, an experiment (being scientists, it is something they can get behind): your friend v. the computer. Who does it better, faster? Ultimately, image processing is the way to go for this type of thing because it can be automated. Save the brain power for the tricky things ...
 
@rcollyer yeah! And even if some error is associated with the automatic methods, a lot of error is also associated with manual methods... So using an automatic algorithm will always win (as long as it is well implemented)
 
5:07 PM
@Sosi I had a boss who wanted to automate everything, primarily to get rid of people, but some of it was reduction in error. If the automated system can be proven to be better, then use it. Adherence to an empirical philosophy (i.e. science) demands it. :)
 
5:51 PM
I have an ordering problem: Ordering[{-1.2, 2.0, 5.3, 0.0}] returns {1, 4, 2, 3}. I've read mathematica.stackexchange.com/questions/2729/ordering-problem, but using N[] doesn't seem to help me get the output I want, {1, 3, 4, 2}. Any suggestions? TIA.
Sort[{-1.2, 2.0, 5.3, 0.0}] returns {-1.2, 0., 2., 5.3} as I would expect.
 
@Gareth The result ordering returns is correct, how'd you come up with your result?
@Gareth For example, the fourth element in the original list is the second element in the sorted list. This is how it should be. In the output you want, you suggest that the third element in the original list should be at the second place in the sorted list, which as you say is not what we'd expect for sorting..
 
Ah, thank you! Apologies, I misunderstood documentation. I was expecting the output to be the ranks corresponding to the original list rather than the sorted one.
 
@Gareth I misunderstood the documentation for that same function just a few days ago lol.
 
 
1 hour later…
7:16 PM
@Sosi I hate this old fashioned guys. I had some kind of apprentice ship with one dr. There was a lot of data stored on one site but a little scattered and also without any interface to get to this. She told me to to manually copy and paste about 500 records ...
@Sosi and when I refused, and started working on mma script to do this, after 1h she asked, why I'm not doing anything. "I could have 25% gathered by far"
@Sosi this "@" will notifiy people but sometimes this notification system is unreliable.
 
 
1 hour later…
8:21 PM
@rcollyer of course! Yet, simply denying everything just without even giving a look... Seems rather pointless and, ahem, square of his part :P
@Kuba yeah! Some of my colleagues in my lab drive me nuts because they don't even cross-reference a Word document correctly. This makes them have to redo all the numbering every time a new figure is added.... But then again, some people prefer to loose more time doing brainless work, than losing some time thinking
@Kuba I saw your reply to this question. Thanks for that!
 
8:58 PM
@Sosi my rule: if it takes more than ten minutes and I'm likely to have to repeat the job, especially if it is prone to error, automate it. (And, yes, it is worth spending 40+ hours to automate those tasks, despite what the bean counters say!) Obviously, this doesn't work for things like house work, but one can always hope!
 
@Gareth, to get the result you are after you just need to apply Ordering twice: Ordering[Ordering[{-1.2, 2.0, 5.3, 0.0}]]
@rcollyer, I wouldn't be surprised to learn that Mathematica can already do house work, it's just undocumented...
 
9:56 PM
why List is locked? Unprotect[List]; gives error ?
But Unprotect[Sqrt] does not.
The symbol List is locked and cannot be modified:
It must be some special symbol.
I wanted to make List Listable, but could not.
 
 
2 hours later…
11:46 PM
@rm-rf Are you around?
 

« first day (587 days earlier)      last day (3898 days later) »