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9:24 PM
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Q: How to get polarised electromagnetic TE wave differential equation from Maxwell's Equations?

crobarI wish to understand how the following equation: $\frac{\partial^2 E_x}{\partial y^2} + \frac{\partial^2 E_x}{\partial z^2} + n^2 k_0 E_x = \frac{\text{d} (\ln \mu)}{\text{d}z}\frac{\partial E_x}{\partial z} $ where $n^2 = \epsilon \mu$ and $k_0 = \frac{\omega}{c} = \frac{2 \pi}{\lambda_0}$...

 
Which quantities can be assumed to be constant here?
 
$\omega$, $\mu$, $\epsilon$ and $c$ are constants
 
It's simple, I think: differentiate (2b) and (2c) with respect to $z$ and $y$ respectively, then substitute the resulting partial derivatives into (1a).
 
If you flesh this out into an answer, I'd be happy to accept.
 
Wait: Based on that first equation, the permeability $\mu$ is certainly not constant.
 
9:24 PM
Well, $\mu$ is a property of a material, and for some materials it is approximately constant, and others, a function of $H$. I'm happy just to consider the first case, constant $\mu$.
 
My point is that that derivative $d \ln \mu / dz$ will vanish unless mu depends on z
And so you'll only get the RHS of the equation if you treat mu as constant
*LHS
 
Yes, and that is what I've been getting in my attempts, so it must be the problem.
 
right. so you need to keep partial derivatives of mu
(well, not partial since it only depends on z)
 
ok, thanks, this is a good starting point for me to try and figure it out!
 
i've put together the mu=0 case for the answer as a reference point
err, \mu = constant
and it shouldn't be too painful to get that term, since the two partial derivatives you do will just pick up one extra term each
 
9:33 PM
Thanks, I'll go off and try your suggestion now, but I'm pretty certain you're right! Thanks again for the help.
 
glad to help, good luck to you
 

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