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12:04 AM
Yeah I really like the book as well! The relevant pages are 273, 274 and 275. Chapter 7 "Angular Momentum and Fixed Axis Rotation", section 7.9 "The Work Energy Theorem and Rotational Motion". (I have the 2nd edition).
Let me put another question to you if you don't mind:
Generally I mostly want to pass my exam, but still have a decent understanding of things for this stage. So I guess the best approach will be to go with the understanding that is illustrated in the book material.
Meaning, calculating total work as the authors explain: translational part is a line integral of the total force over the curve traced by the CoM. And rotational part is the integral over the torque from the starting angle to the final angle.
However - I would just like to validate one thing. You helped clarify for me, that if a force acts in a direction perpendicular to the velocity of *the point of contact* with the object (and not the CoM), than the force does no work on the object.

So can I apply this understanding in the problems I face (solely in order to understand if a particular force does any work) - and then later in the same exercise calculate *total* work done using the method illustrated above (from the book)?

You see what I'm asking? I think that's fine, but I want to make sure. Thanks!
I guess I would also mention, if it's relevant - in my current stage, I'm only concerned with "fixed axis rotation" - where an object can rotate around an axis, and the axis is free to translate in space, but the axis cannot change its direction.
 
 
2 hours later…
2:28 AM
Yes. Always pay attention to whether or not the displacement of the point of contact of the particular force is perpendicular to the force or not. If it is, then the force in question does no work. I will edit my answer tomorrow and include a worked out example for the problem of a ladder against the wall, that shows the details.
 
 
3 hours later…
5:52 AM
Great, thanks a lot!
 

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